IGCSE Chemistry 0620 Paper 43, Oct/Nov 2024

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0620/43 · Oct/Nov 2024

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1

A list of substances is shown. bauxite carbon dioxide cryolite ethane ethanol ethene graphite helium hematite hydrogen silicon(IV) oxide sodium chloride Answer the following questions using only the substances from the list. Each substance may be used once, more than once or not at all. State which substance:

a

is manufactured by fermentation

[1]
b

is monatomic

[1]
c

is a reactant in photosynthesis

[1]
d

is a solvent in the extraction of aluminium

[1]
e

is an ore of iron

[1]
f

is manufactured from methane

[1]
g

is a compound with a giant covalent structure

[1]
h

is used as a lubricant

[1]
i

is tested for with limewater.

[1]
2

This question is about electrolysis.

a

State the meaning of the term electrolysis.

[2]
b(i)

Table 2.1 gives some information about the electrolysis of two electrolytes using graphite electrodes. Table 2.1 Complete Table 2.1.

[4]
b(ii)

Oxygen is produced at the anode by the electrolysis of aqueous copper(II) sulfate. Write the ionic half-equation for this reaction.

[2]
c(i)

Aqueous copper(II) sulfate is electrolysed using copper electrodes instead of graphite electrodes. Explain why the mass of the anode decreases during this electrolysis.

[1]
c(ii)

Name the product formed at the cathode.

[1]
c(iii)

State what change, if any, is observed in the appearance of the aqueous copper(II) sulfate.

[1]
3

This question is about compounds of tin.

Figure 1 of 1 for question 3
a

Tin(IV) oxide has the formula SnO2. The relative formula mass, Mr, of SnO2 is 151. Calculate the percentage by mass of tin in SnO2. percentage by mass of tin in SnO2 = ..............................%

[1]
b(i)

SnO2 is an amphoteric oxide. SnO2 reacts with aqueous sodium hydroxide, NaOH, to form a sodium salt and water only. The sodium salt contains a negative ion with the formula SnO32−. State the meaning of the term amphoteric.

[1]
b(ii)

Write the symbol equation for the reaction between SnO2 and NaOH.

[2]
c

Tin is a metal that forms both covalent and ionic compounds. Suggest why this is unusual for a metal.

[1]
d(i)

Tin(IV) chloride, SnCl4, is covalently bonded. A tin atom has four electrons in its outer shell. Complete the dot-and-cross diagram in Fig. 3.1 for a molecule of SnCl4. Show the outer shell electrons only.

[2]
d(ii)

Tin(II) oxide, SnO, is ionically bonded. The melting points of SnCl4 and SnO are shown in Table 3.1. Table 3.1 Explain, in terms of structure and bonding, why SnCl4 has a much lower melting point than SnO.

[3]
e(i)

Part of the reactivity series is shown. magnesium most reactive aluminium tin copper least reactive When aluminium foil is added to aqueous tin(II) sulfate, a reaction does not occur even though aluminium is above tin in the reactivity series. Explain why a reaction does not occur.

[1]
e(ii)

An aqueous solution of tin(II) sulfate contains Sn2+ ions. Two experiments are carried out. Experiment 1 Copper is added to aqueous tin(II) sulfate. Experiment 2 Magnesium is added to aqueous tin(II) sulfate. Write an ionic equation for any reaction that occurs in each experiment. If no reaction occurs, write ‘no reaction’. Experiment 1 ...................................................................................................................... Experiment 2 ......................................................................................................................

[2]
f(i)

Hydrated tin(II) nitrate, Sn(NO3)2⋅20H2O, decomposes when it is heated. State what is meant by the term hydrated.

[1]
f(ii)

Complete the equation for the decomposition of Sn(NO3)2⋅20H2O. 2Sn(NO3)2⋅20H2O→......SnO+......NO2+O2+......H2O

[2]
4

This question is about sulfuric acid, H2SO4.

Figure 1 of 1 for question 4
a(i)

Dilute sulfuric acid and aqueous sodium hydroxide can be used to prepare sodium sulfate crystals using a method that involves titration. The apparatus for titration is shown in Fig. 4.1. Thymolphthalein is used as an indicator for this titration. State the colour change of thymolphthalein at the end-point of this titration. from ............................................................ to .............................................................

[2]
a(ii)

Suggest why universal indicator is not used for this titration.

[1]
b

25.0 cm3 of aqueous sodium hydroxide, NaOH, of concentration 0.100 mol/dm3 is neutralised by 20.0 cm3 of dilute sulfuric acid, H2SO4. The equation for the reaction is shown. 2NaOH+H2SO4→Na2SO4+2H2O Calculate the concentration of H2SO4 using the following steps. ● Calculate the number of moles of NaOH used. .............................. mol ● Determine the number of moles of H2SO4 that react with the NaOH. .............................. mol ● Calculate the concentration of H2SO4. .............................. mol/dm3

[3]
c

A student is provided with an aqueous solution of sodium sulfate. Describe how to prepare a pure sample of sodium sulfate crystals from this solution.

[3]
d

Potassium hydrogen sulfate, KHSO4, can be prepared by a reaction between aqueous potassium hydroxide and dilute sulfuric acid. Water is the only other product. Write a symbol equation for this reaction.

[1]
e(i)

Potassium hydrogen sulfate, KHSO4, dissolves in water to form solution X. Solution X contains K+, H+ and SO42− ions. Name the type of solution that contains H+ ions.

[1]
e(ii)

State the observations when the following tests are done. ● A flame test is carried out on X. ............................................................................................................................................. ● Solid copper(II) carbonate is added to X. ............................................................................................................................................. ............................................................................................................................................. ............................................................................................................................................. ● Aqueous barium nitrate acidified with dilute nitric acid is added to X. .............................................................................................................................................

[5]
f(i)

0.325 g of Zn is added to dilute sulfuric acid which contains 0.0100 moles of H2SO4. The equation for this reaction is shown. Zn+H2SO4→ZnSO4+H2 Determine whether Zn or H2SO4 is the limiting reactant. Explain your answer.

[2]
f(ii)

In another experiment, 48.0 cm3 of hydrogen gas, H2, is produced. The experiment is carried out at room temperature and pressure, r.t.p. Calculate the number of molecules in 48.0 cm3 of H2 gas measured at r.t.p. The value of the Avogadro constant is 6.02×1023. .............................. molecules

[2]
5

This question is about rate of reaction and equilibrium.

Figure 1 of 4 for question 5
Figure 2 of 4 for question 5
Figure 3 of 4 for question 5
Figure 4 of 4 for question 5
a(i)

A student investigates the rate of decomposition of aqueous hydrogen peroxide, H2O2, using manganese(IV) oxide as a catalyst. The equation for the reaction is shown. 2H2O2(aq)→2H2O(l)+O2(g) The student uses the apparatus shown in Fig. 5.1. The student: ● adds the catalyst to the aqueous hydrogen peroxide ● replaces the container on the balance ● starts a stop-watch ● records the mass at regular time intervals. Table 5.1 shows the mass recorded at regular time intervals. Table 5.1 Suggest why the mass decreases as time increases.

[1]
a(ii)

After a certain time the reaction stops. Explain why the reaction stops.

[1]
a(iii)

Suggest why it is not possible to use the results in Table 5.1 to determine the exact time when the reaction stops.

[1]
b(i)

Fig. 5.2 shows a graph of the mass against time. The experiment is repeated at a higher temperature. All other conditions remain the same. Explain, in terms of collision theory, why the rate of reaction is higher at a higher temperature.

[3]
b(ii)

On Fig. 5.2, sketch the line expected when the experiment is repeated at a higher temperature.

[2]
c(i)

Manganese(IV) oxide is the catalyst in this reaction. Explain the meaning of (IV) in manganese(IV) oxide.

[2]
c(ii)

State how the mass of the catalyst has changed, if at all, at the end of the experiment.

[1]
d(i)

Nitrogen monoxide gas, NO, and oxygen gas, O2, react to produce nitrogen dioxide gas, NO2, at room temperature. The reaction can reach equilibrium. The equation is shown. 2NO(g)+O2(g)⇌2NO2(g)ΔH=−113 kJ/mol NO(g) and O2(g) are passed into a beaker as shown in Fig. 5.3. Explain why the method shown in Fig. 5.3 will not allow the reaction to reach equilibrium.

[1]
d(ii)

The apparatus is changed and equilibrium is reached. The temperature of the equilibrium system is then increased and the position of equilibrium shifts to the left. Explain why the position of equilibrium shifts to the left.

[1]
d(iii)

The pressure of the equilibrium system is then increased. State the direction, if any, in which the position of equilibrium shifts. Explain your answer. direction .............................................................................................................................. explanation .........................................................................................................................

[2]
6

This question is about hydrocarbons.

Figure 1 of 1 for question 6
a

State the meaning of the term hydrocarbon.

[1]
b(i)

Propene, C3H6, can be made from long-chain alkanes such as dodecane. Dodecane contains 12 carbon atoms. Deduce the molecular formula of dodecane.

[1]
b(ii)

Name the type of reaction that occurs when long-chain alkanes are converted into shorter chain alkenes.

[1]
c(i)

Propene is an unsaturated hydrocarbon. Propene reacts with bromine. State the meaning of the term unsaturated.

[1]
c(ii)

Write the molecular formula of the product formed when propene reacts with bromine.

[1]
d(i)

A styrene molecule is represented as shown in Fig. 6.1. The molecular formula of styrene is C8H8. Determine the empirical formula of styrene.

[1]
d(ii)

Styrene can be polymerised into poly(styrene). State the type of polymerisation that occurs when styrene is converted into poly(styrene).

[1]
d(iii)

Draw the structure of one repeat unit of poly(styrene). Include all of the atoms and all of the bonds. The C6H5 group should be represented as C6H5.

[2]

Mark scheme

0620/43 · Oct/Nov 2024

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1a · 1 mark

  • 1 mark

    ethanol / carbon dioxide

1b · 1 mark

  • 1 mark

    helium

1c · 1 mark

  • 1 mark

    carbon dioxide

1d · 1 mark

  • 1 mark

    cryolite

1e · 1 mark

  • 1 mark

    hematite

1f · 1 mark

  • 1 mark

    hydrogen

1g · 1 mark

  • 1 mark

    silicon(IV) oxide

1h · 1 mark

  • 1 mark

    graphite

1i · 1 mark

  • 1 mark

    carbon dioxide

2a · 2 marks

  • M1

    breakdown by (the passage of) electricity

  • M2

    of an ionic compound in molten or aqueous (state)

2b(i) · 4 marks

  • M1

    brown solution OR black solid

  • M2

    iodine

  • M3

    hydrogen

  • M4

    copper

2b(ii) · 2 marks

  • M1

    OH– AND e–

  • M2

    correct equation

2c(i) · 1 mark

  • 1 mark

    copper OR anode forms Cu2+ which goes into the solution

2c(ii) · 1 mark

  • 1 mark

    copper

2c(iii) · 1 mark

  • 1 mark

    no change

3a · 1 mark

  • 1 mark

    78.8 (%)

3b(i) · 1 mark

  • 1 mark

    reacts with acids and with bases to produce a salt and water

3b(ii) · 2 marks

  • M1

    Na2SnO3

  • M2

    correct equation

3c · 1 mark

  • 1 mark

    metals form ionic compounds or ionic bonds only OR covalent compounds contain non-metals only

3d(i) · 2 marks

  • M1

    four single bonds using one dot and one cross

  • M2

    three pairs of non-bonding electrons on each chlorine and no non-bonding electrons on tin

3d(ii) · 3 marks

  • M1

    attraction between molecules or intermolecular forces in tin(IV) chloride

  • M2

    tin(II) oxide has a giant ionic structure

  • M3

    weaker attraction (between particles) in tin(IV) chloride ORA

3e(i) · 1 mark

  • 1 mark

    unreactive coating of aluminium oxide

3e(ii) · 2 marks

  • M1

    no reaction

  • M2

    Mg + Sn2+ → Mg2+ + Sn

3f(i) · 1 mark

  • 1 mark

    substance that is chemically combined with water OR containing water of crystallisation

3f(ii) · 2 marks

  • M1

    2(SnO) + 4(NO2)

  • M2

    40H2O

4a(i) · 2 marks

  • 1 mark

    blue

  • 1 mark

    colourless

4a(ii) · 1 mark

  • 1 mark

    too many colour changes

4b · 3 marks

  • M1

    0.0025 / 2.5  10–3 (mol)

  • M2

    0.00125 / 1.25  10–3 (mol)

  • M3

    0.0625 / 6.25  10–2 (mol / dm3)

4c · 3 marks

  • M1

    heat the solution / warm the solution /boil the solution / leave solution in hot place

  • M2

    to saturation (point)/ crystallisation point AND leave to cool

  • M3

    suitable method of drying

4d · 1 mark

  • 1 mark

    KOH + H2SO4 → KHSO4 + H2O

4e(i) · 1 mark

  • 1 mark

    acid / acidic

4e(ii) · 5 marks

  • M1

    lilac flame

  • M2

    solid dissolves / solid disappears

  • M2

    bubbles / fizzing / effervescence

  • M3

    blue solution

  • M5

    white precipitate

4f(i) · 2 marks

  • M1

    moles of Zn = 0.005 / 5  10–3 (mol)

  • M2

    Zn is limiting because moles of H2SO4  moles of Zn AND 1:1 ratio required for reaction

4f(ii) · 2 marks

  • M1

    (48.0 ÷ 24 000 =) 0.00200 (mol)

  • M2

    1.20  1021 (molecules)

5a(i) · 1 mark

  • 1 mark

    oxygen gas escapes from the flask

5a(ii) · 1 mark

  • 1 mark

    the hydrogen peroxide is used up OR all the hydrogen peroxide has reacted or decomposed

5a(iii) · 1 mark

  • 1 mark

    time intervals are too large

5b(i) · 3 marks

  • M1

    kinetic energy of particles increases

  • M2

    frequency of collisions between particles increases

  • M3

    more / higher percentage OR higher proportion OR higher fraction of particles have energy greater than / equal to activation energy OR more of the collisions / higher percentage OR higher fraction or higher proportion of collisions have energy greater than or equal to activation energy

5b(ii) · 2 marks

  • M1

    graph starts at same mass and has steeper gradient

  • M2

    levels off at the same mass but earlier

5c(i) · 2 marks

  • M1

    oxidation number of manganese

  • M2

    + 4

5c(ii) · 1 mark

  • 1 mark

    no change

5d(i) · 1 mark

  • 1 mark

    not a closed system

5d(ii) · 1 mark

  • 1 mark

    forward reaction is exothermic

5d(iii) · 2 marks

  • M1

    (to the) right

  • M2

    there are fewer gas molecules on the right

6a · 1 mark

  • 1 mark

    compound containing carbon and hydrogen only

6b(i) · 1 mark

  • 1 mark

    C12H26

6b(ii) · 1 mark

  • 1 mark

    cracking

6c(i) · 1 mark

  • 1 mark

    contains at least one carbon – carbon double bond

6c(ii) · 1 mark

  • 1 mark

    C3H6Br2

6d(i) · 1 mark

  • 1 mark

    CH

6d(ii) · 1 mark

  • 1 mark

    addition

6d(iii) · 2 marks

  • M1

    only two carbon atoms joined by a single bond and two additional bonds on each carbon

  • M2

    correct repeat unit including two extension bonds

Questions

  1. 1
    Question 19 marks
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  2. 2
    Question 211 marks
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  3. 3
    Question 316 marks
    Mark scheme ›
  4. 4
    Question 420 marks
    Mark scheme ›
  5. 5
    Question 515 marks
    Mark scheme ›
  6. 6
    Question 69 marks
    Mark scheme ›

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