IGCSE Chemistry 0620 Paper 43, May/June 2024

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0620/43 · May/June 2024

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1

Name the process used to:

a

produce ammonia from nitrogen

[1]
b

produce lead from molten lead(II) bromide

[1]
c

separate an insoluble solid from a mixture of an insoluble solid and a solution

[1]
d

produce ethanol from ethene

[1]
e

identify the components of a mixture of soluble coloured substances

[1]
f

separate a mixture of several liquids with different boiling points

[1]
g

determine the volume of an acid required to neutralise a given volume of an alkali.

[1]
2

Complete Table 2.1. Table 2.1

atom or ionnumber of protonsnumber of electronsnumber of neutrons
2963Cu29
1737Cl−20
302834
[5]
3

This question is about elements and compounds.

Figure 1 of 1 for question 3
a(i)

Some properties of graphite, oxygen and carbon monoxide are shown in Table 3.1. Table 3.1

melting point / °Cboiling point / °Cconduction of electricity when solid
graphite36524827good
oxygen-218-183poor
carbon monoxide-199-191poor

Explain why graphite conducts electricity when solid.

[1]
a(ii)

Complete the dot-and-cross diagram in Fig. 3.1 of a molecule of oxygen. Show outer shell electrons only.

[2]
a(iii)

Deduce the physical state of carbon monoxide at −195 ∘C. Use the data in Table 3.1 to explain your answer. physical state ...................................................................................................................... explanation ......................................................................................................................... .............................................................................................................................................

[2]
a(iv)

Explain in terms of structure and bonding why graphite has a much higher melting point than carbon monoxide.

[3]
b

Potassium reacts with chlorine to form potassium chloride. Write a symbol equation for this reaction.

[2]
c(i)

A dilute aqueous solution of potassium chloride undergoes electrolysis. Oxygen is produced at the anode. State what is meant by the term electrolysis.

[2]
c(ii)

Write an ionic half-equation for the production of oxygen at the anode.

[2]
4

Dinitrogen tetroxide, N2O4, decomposes into nitrogen dioxide, NO2. The reaction is reversible. N2O4(g)⇌2NO2(g) colourless gasbrown gas Fig. 4.1 shows a gas syringe containing a mixture of dinitrogen tetroxide and nitrogen dioxide. The gas syringe is sealed. The mixture reaches equilibrium and the colour of the mixture of gases is a pale brown.

Figure 1 of 1 for question 4
a

Describe a reversible reaction at equilibrium in terms of: ● the rate of the forward reaction and the rate of the reverse reaction .................................................................................................................................................... ● the concentration of reactants and products. ....................................................................................................................................................

[2]
b

The pressure of the mixture is increased. All other conditions stay the same. The mixture immediately turns darker brown before the position of equilibrium changes. Explain in terms of particles why the mixture immediately turns darker brown.

[1]
c

The temperature of the mixture is increased. All other conditions stay the same. The mixture turns darker brown. State what can be deduced about the forward reaction from this information.

[1]
d(i)

Sulfur is converted into sulfuric acid, H2SO4, by a series of reactions. Sulfur dioxide, SO2, and oxygen, O2, react to form sulfur trioxide, SO3. The reversible reaction reaches equilibrium. 2SO2(g)+O2(g)⇌2SO3(g) Complete Table 4.1 using only the words, increases, decreases or no change. Table 4.1

effect on the rate of the forward reactioneffect on the equilibrium yield of SO3(g)
add a catalyst
increase the pressure
[4]
d(ii)

Deduce the oxidation number of sulfur in: S .................................................. SO3 ..............................................

[2]
5
a(i)

Barium sulfate, BaSO4, is an insoluble salt and is made by precipitation. Name two aqueous solutions that produce a precipitate of barium sulfate when they are mixed. 1 .......................................................................................................................................... 2 ..........................................................................................................................................

[2]
a(ii)

Describe how to produce a pure sample of barium sulfate from the mixture of aqueous solutions in (a)(i).

[2]
a(iii)

Write an ionic equation for the precipitation reaction which produces barium sulfate. Include state symbols.

[3]
b

Soluble salts are made from dilute acids. Name the dilute acid and one other substance that react together to make copper(II) sulfate. dilute acid .................................................................................................................. other substance .........................................................................................................

[2]
c(i)

Nitrates decompose when they are heated. When hydrated copper(II) nitrate is heated, oxygen gas is produced. Describe a test for oxygen. test ...................................................................................................................................... observations .......................................................................................................................

[1]
c(ii)

Complete the equation for the decomposition of hydrated copper(II) nitrate. 2Cu(NO3)2∙3H2O→.....CuO+.....NO2+O2+.....H2O

[2]
d(i)

Hydrated zinc sulfate gives off water when it is heated. ZnSO4∙xH2O(s)→ZnSO4(s)+xH2O(g) A student does an experiment to determine the value of x in ZnSO4∙xH2O. step 1 The student weighs a sample of hydrated zinc sulfate. step 2 The student heats the sample of hydrated zinc sulfate. step 3 The student weighs the solid after heating. step 4 The student repeats step 2 and step 3 until the mass of solid after heating is constant. State why the student does step 4.

[1]
d(ii)

In an experiment, 0.574 g of ZnSO4∙xH2O is heated until the mass is constant. The mass of ZnSO4 that remains is 0.322 g. [Mr: ZnSO4, 161; H2O, 18] Determine the value of x using the following steps. ● Calculate the number of moles of ZnSO4 remaining. .............................. mol ● Calculate the mass of H2O given off. .............................. g ● Calculate the number of moles of H2O given off. .............................. mol ● Determine the value of x. x= ..............................

[4]
6

This question is about iron.

Figure 1 of 2 for question 6
Figure 2 of 2 for question 6
a(i)

Fig. 6.1 shows a blast furnace used to extract iron from its ore. Name the main ore of iron used in the blast furnace.

[1]
a(ii)

Name the substance that enters the blast furnace at A.

[1]
a(iii)

Name the reducing agent in the extraction of iron in the blast furnace.

[1]
a(iv)

Explain why limestone is added to the blast furnace. Give details of the chemical reactions that are involved.

[3]
b(i)

The list shows the properties of some elements. ● act as catalysts ● have low densities ● have low melting points ● form acidic or basic oxides ● form coloured compounds ● form positive or negative ions Iron is a transition metal. Sodium is a Group I metal. State which property from the list: is true for sodium but not iron

[1]
b(ii)

State which property from the list: is true for iron but not sodium

[1]
b(iii)

State which property from the list: is true for both sodium and iron

[1]
b(iv)

State which property from the list: is not true for sodium and not true for iron.

[1]
c(i)

Steel consists mainly of iron. Iron rusts when it reacts with water and oxygen. Fig. 6.2 shows magnesium blocks attached to the bottom of a steel boat. The magnesium does not completely cover the steel. The magnesium blocks provide sacrificial protection for the steel. Explain, in terms of electrons, why magnesium is used for sacrificial protection.

[2]
c(ii)

Name a metal that cannot provide sacrificial protection for steel.

[1]
7

Many organic compounds contain carbon and hydrogen only.

Figure 1 of 1 for question 7
a(i)

An organic compound A has the following composition by mass. C, 83.33%;H, 16.67% Calculate the empirical formula of compound A. empirical formula = ..............................

[3]
a(ii)

Compound B has the empirical formula C2H5 and a relative molecular mass of 58. Determine the molecular formula of compound B. molecular formula = ..............................

[2]
b(i)

Fig. 7.1 shows a section of a polymer formed from an alkene. Identify the functional group in alkenes that reacts when alkenes form polymers.

[1]
b(ii)

A section of a polymer is shown in Fig. 7.1. ● Draw the displayed formula of the monomer that forms this polymer. ● Name the monomer used to form this polymer. .............................................................................................................................................

[3]
c

Alkenes are produced by cracking alkanes. When C12H26 is cracked, the products are ethene and an alkane which form in a 2:1 mole ratio. Write a symbol equation for this reaction. C12H26→........................+...................................................

[2]
d(i)

State the general formula for alcohols.

[1]
d(ii)

Draw the displayed formula of one alcohol with the molecular formula C3H8O. Name the alcohol you have drawn. name of alcohol ..................................................................................................................

[2]

Mark scheme

0620/43 · May/June 2024

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1a · 1 mark

  • 1 mark

    Haber (process)

1b · 1 mark

  • 1 mark

    electrolysis

1c · 1 mark

  • 1 mark

    filtration

1d · 1 mark

  • 1 mark

    catalytic addition

1e · 1 mark

  • 1 mark

    chromatography

1f · 1 mark

  • 1 mark

    fractional distillation

1g · 1 mark

  • 1 mark

    titration

2 · 5 marks

  • M1

    Cu: 29 and 34

  • M2

    Cl<sup>–</sup>: 17 and 18

  • M3

    <sup>64</sup><sub>30</sub> to left of symbol

  • M4

    Zn

  • M5

    2+

3a(i) · 1 mark

  • 1 mark

    mobile electrons

3a(ii) · 2 marks

  • M1

    double bond of two dots and two crosses

  • M2

    4 non-bonding electrons on each oxygen atom

3a(iii) · 2 marks

  • M1

    liquid

  • M2

    melting point is below –195 °C and boiling point is above –195 °C or –195 °C is higher than –199 °C / melting point and lower than –191 °C / boiling point or –195 °C is in between melting point / –199 °C and boiling point / –191 °C

3a(iv) · 3 marks

  • M1

    graphite has a giant covalent structure

  • M2

    attraction between molecules in carbon monoxide

  • M3

    weaker attraction (between particles) in carbon monoxide ORA

3b · 2 marks

  • M1

    KCl as only product

  • M2

    correct equation

3c(i) · 2 marks

  • M1

    breakdown by (the passage of) electricity

  • M2

    of an ionic compound in molten or aqueous (state)

3c(ii) · 2 marks

  • M1

    any negatively charged OH species losing electrons

  • M2

    correct ionic half-equation

4a · 2 marks

  • M1

    (rates are) equal

  • M2

    (concentrations are) no longer changing

4b · 1 mark

  • 1 mark

    more molecules of nitrogen dioxide per unit volume OR same number of nitrogen dioxide molecules in a smaller volume

4c · 1 mark

  • 1 mark

    (the forward reaction is) endothermic

4d(i) · 4 marks

  • M1

    increases

  • M2

    increases

  • M3

    no change

  • M4

    increases

4d(ii) · 2 marks

  • M1

    (the oxidation number of sulfur in S) = zero

  • M2

    (the oxidation number of sulfur in SO3) = +6

5a(i) · 2 marks

  • M1

    named soluble barium salt e.g. barium chloride / barium nitrate

  • M2

    named soluble sulfate salt e.g. sodium sulfate / potassium sulfate / ammonium sulfate / sulfuric acid

5a(ii) · 2 marks

  • M1

    filter

  • M2

    wash (residue) with water and dry (residue) between filter papers / in a warm place

5a(iii) · 3 marks

  • M1

    BaSO4 as only product

  • M2

    Ba<sup>2+</sup> + SO4<sup>2–</sup> as only reactants

  • M3

    state symbols

5b · 2 marks

  • M1

    sulfuric (acid)

  • M2

    copper(II) carbonate / copper(II) oxide / copper(II) hydroxide

5c(i) · 1 mark

  • 1 mark

    glowing splint and relights

5c(ii) · 2 marks

  • M1

    2CuO + 4NO2

  • M2

    6H2O

5d(i) · 1 mark

  • 1 mark

    (To ensure that) all the water is given off

5d(ii) · 4 marks

  • M1

    mol ZnSO4 (0.322 / 161 =) 0.002(00)

  • M2

    mass H2O given off (0.574 – 0.322 =) 0.252

  • M3

    mol H2O given off (0.252 ÷ 18 =) 0.014(0)

  • M4

    value of x (0.014 ÷ 0.002 =) 7

6a(i) · 1 mark

  • 1 mark

    hematite

6a(ii) · 1 mark

  • 1 mark

    air

6a(iii) · 1 mark

  • 1 mark

    carbon monoxide

6a(iv) · 3 marks

  • M1

    limestone thermally decomposes (into calcium oxide and carbon dioxide)

  • M2

    calcium oxide reacts with silicon(IV) oxide

  • M3

    producing slag

6b(i) · 1 mark

  • 1 mark

    have low densities or have low melting point

6b(ii) · 1 mark

  • 1 mark

    act as catalysts or form coloured compounds

6b(iii) · 1 mark

  • 1 mark

    form basic oxides or form positive ions

6b(iv) · 1 mark

  • 1 mark

    form acidic oxides or form negative ions

6c(i) · 2 marks

  • M1

    magnesium loses electrons more readily than / in preference to / instead of iron

  • M2

    magnesium is more reactive than iron ORA

6c(ii) · 1 mark

  • 1 mark

    any metal below iron in the reactivity series e.g. copper / silver / gold

7a(i) · 3 marks

  • M1

    C 83.33 / 12: H 16.67 / 1 or 6.94:16.67

  • M2

    C 6.94 / 6.94: H 16.67 / 6.94 or 1:2.4 or 5:12

  • M3

    C5H12

7a(ii) · 2 marks

  • M1

    M<sub>r</sub> of C2H5 = 29

  • M2

    58 / 29 = 2 and C4H10

7b(i) · 1 mark

  • 1 mark

    C=C

7b(ii) · 3 marks

  • M1

    \>C=C< any C=C with both carbons having a valency of 4

  • M2

    displayed formula of but-1-ene

  • M3

    but-1-ene

7c · 2 marks

  • M1

    2C2H4

  • M2

    C8H18

7d(i) · 1 mark

  • 1 mark

    CnH2n + 1OH

7d(ii) · 2 marks

  • M1

    displayed formula of propan-1-ol or propan-2-ol

  • M2

    propan-1-ol or propan-2-ol

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