A Level Chemistry 9701 Paper 23, May/June 2026

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9701/23 · May/June 2026

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1

The chlorides of Period 3 elements show different physical and chemical properties.

a(i)

Complete Table 1.1. Table 1.1

elementformula of chloridetype of bonding in the chloridetype of reaction, if any, of the chloride with cold water
sodium
silicon
[3]
a(ii)

Write an equation for the reaction of PCl5 with an excess of cold water.

[1]
b(i)

The reaction of chlorine with cold water is used in water purification. Write an equation for the reaction of chlorine with cold water.

[1]
b(ii)

Explain the use of chlorine in water purification.

[1]
c(i)

The relative strength of Cl2, Br2 and I2 as oxidising agents can be compared by adding NaBr(aq) to separate samples of Cl2 and I2. Describe the relative reactivity of Cl2, Br2 and I2 as oxidising agents.

[1]
c(ii)

Complete Table 1.2 to describe the reactions of NaBr(aq) with separate samples of Cl2(aq) and I2(aq). Table 1.2

aqueous halogencolour of aqueous halogenappearance after NaBr(aq) is addedhalide ions present in the mixture after the reaction
Cl2(aq)pale green
I2(aq)red–brown
[3]
d

Describe what is observed when Ag+(aq), followed by NH3(aq), are added to a sample of NaI(aq). observation after addition of Ag+(aq) ........................................................................................ observation after addition of NH3(aq) .......................................................................................

[2]
2

Group 18 elements exist as colourless gases at room temperature and pressure. Table 2.1

atomrelative volume of atom
neon172
argon287
krypton355
xenon446
a

Use Table 2.1 to describe and explain the variation in atomic radius down Group 18.

[2]
b

Identify one Group 18 element from Table 2.1 that behaves most like an ideal gas under standard conditions. Explain your answer.

[3]
c

A sample of 1.775 g of gas X occupies 617.0 cm3 at 300 K and 101 kPa. Calculate the relative molecular mass, Mr, of X assuming that X behaves as an ideal gas. Mr of X= .........................................................

[4]
3

The conditions used for the conversion of sulfur dioxide to sulfur trioxide in the Contact process are carefully controlled. reaction 1 2SO2(g)+O2(g)⇌2SO3(g)ΔH=−196 kJ mol−1

Figure 1 of 1 for question 3
a

Complete Figure 3.1 to show the reaction pathway diagram for reaction 1. Draw arrows to represent the enthalpy change, ΔH, and activation energy, EA.

[2]
b

Define Le Chatelier's principle.

[2]
c

In industry, reaction 1 occurs at 400–450 ∘C and 110–200 kPa with a catalyst. Complete Table 3.1 by using the terms 'increase', 'decrease' or 'no change'. Table 3.1

use temperature greater than 450 ∘Cwithout catalyst
effect on value of equilibrium constant, Kp
effect on yield of product at equilibrium
effect on rate of reaction
[3]
d(i)

A sealed tube that initially contains only 2.00 mol of SO2(g) and 2.00 mol of O2(g) is left to reach equilibrium. At equilibrium, 1.96 mol of SO3(g) is present and the total pressure is 150 kPa. reaction 1 2SO2(g)+O2(g)⇌2SO3(g) Complete Table 3.2. Table 3.2

SO2(g)O2(g)SO3(g)
amount initially/mol2.002.000
amount at equilibrium/mol1.96
mole fraction at equilibrium0.013250.3377
[3]
d(ii)

Table 3.3 shows the mole fractions at equilibrium of SO2(g), O2(g) and SO3(g) under different conditions. Table 3.3

SO2(g)O2(g)SO3(g)
mole fraction at equilibrium0.3600.0190.621

Calculate Kp at 200 kPa using the data from Table 3.3. Include units in your answer. Kp= ............................................................... units ...............................................................

[3]
4

The structure of compound V is shown in Figure 4.1. Figure 4.1

Figure 1 of 4 for question 4
Figure 2 of 4 for question 4
Figure 3 of 4 for question 4
Figure 4 of 4 for question 4
a(i)

Complete Table 4.1. Table 4.1

primary hydroxyl groupssecondary hydroxyl groupstertiary hydroxyl groups
number of groups in one molecule of V
[2]
a(ii)

Complete Table 4.2 to show what is observed when separate samples of V are added to each reagent. State 'none' if no reaction occurs. Table 4.2

reagentobservation with V
Na(s)
2,4-dinitrophenylhydrazine (2,4-DNPH)
Fehling's reagentnone
[2]
a(iii)

Suggest why Fehling's reagent does not react with V but does react with aldehyde functional groups.

[1]
b(i)

Figure 4.1 is repeated for use in 4(b). V is completely oxidised by heating under reflux with an excess of acidified K2Cr2O7(aq) to produce organic compound Z. Describe the colour change in this reaction. colour of mixture at start of the reaction ............................................................................ colour of mixture after the reaction ....................................................................................

[1]
b(ii)

Draw the structure of Z.

[1]
c(i)

Compounds W, X and Y are structural isomers of V. Describe structural isomerism.

[2]
c(ii)

Identify which of structures V, W, X and Y show stereoisomerism. Explain your answer by referring to the relevant parts of the molecule that cause stereoisomerism.

[2]
c(iii)

Y reacts with reagent R to produce compound E. Name reagent R.

[1]
d(i)

Exactly 0.03 mol of one of the isomers, V, W, X or Y, is completely oxidised by 0.08 mol of acidified K2Cr2O7(aq) to produce only one organic compound with molecular formula C5H4O8. Identify which isomer, V, W, X or Y, is used in this reaction.

[1]
d(ii)

Complete the equation for this reaction. 3C5H12O4+.....Cr2O72−+.....H+→3C5H4O8+.....Cr3++.....H2O

[1]
5

Propane, CH3CH2CH3, reacts with Cl2(g) in the presence of ultraviolet light to produce different organic products, including those shown in Table 5.1. Table 5.1

structure of productsystematic name of product
CH3(CH2)2Cl1-chloropropane
CH3CHClCH32-chloropropane
(CH3)2CHCH(CH3)22,3-dimethylbutane
hexane
2-methylpentane
Figure 1 of 3 for question 5
Figure 2 of 3 for question 5
Figure 3 of 3 for question 5
a(i)

Complete Table 5.1.

[2]
a(ii)

Name the mechanism for the reaction of propane and Cl2(g) in the presence of ultraviolet light.

[1]
b(i)

The mechanism for this reaction involves three stages. stage 1 initiation stage 2 propagation stage 3 termination During the initiation reaction, a chlorine free radical is produced. Complete Figure 5.1 to describe the arrangement of electrons in a chlorine free radical.

[1]
b(ii)

Suggest a reaction sequence of two propagation reactions that result in CH3CH2CH3 forming CH3CH2CH2Cl. propagation reaction 1 CH3CH2CH3 ............................................. → ................................................................. propagation reaction 2 ................................................................... →CH3CH2CH2Cl ........................................

[2]
b(iii)

Suggest a reaction sequence of one propagation reaction followed by a termination reaction that results in CH3CH2CH3 forming (CH3)2CHCH(CH3)2. propagation reaction 3 CH3CH2CH3 ......................................... → ..................................................................... termination reaction ............................................................... →(CH3)2CHCH(CH3)2

[2]
c(i)

Compound A has the molecular formula CH2Cl2. Figure 5.2 shows the mass spectrum of A. Explain the difference in relative abundance of the peaks at m/e=35 and m/e=37.

[2]
c(ii)

Complete Table 5.2. Table 5.2

m/e value of peakmolecular formula of species responsible for peak
84
86
88
[2]

Mark scheme

9701/23 · May/June 2026

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1a(i) · 3 marks

  • 1 mark

    formula of chloride: NaCl, SiCl4

  • 1 mark

    type of bonding: ionic, covalent

  • 1 mark

    type of reaction: no reaction / none (A dissolves / dissociates / dissolution), hydrolysis (R hydration)

1a(ii) · 1 mark

  • 1 mark

    PCl5 + 4 H2O → H3PO4 + 5 HCl

1b(i) · 1 mark

  • 1 mark

    Cl2 + H2O → HCl + HOCl

1b(ii) · 1 mark

  • 1 mark

    (HOCl AND / OR ClO–) kill bacteria

1c(i) · 1 mark

  • 1 mark

    Cl2 > Br2 > I2 OR oxidising power decreases down the group.

1c(ii) · 3 marks

  • 1 mark

    colour of aqueous halogen: pale green, red-brown

  • 1 mark

    appearance after NaBr(aq) is added: orange / brown, pale(r) (red-brown) / no change

  • 1 mark

    identity of halide ions present in mixture after the reaction: Cl– (and Br–), Br–

1d · 2 marks

  • M1

    (after addition of Ag+(aq))……(pale) yellow precipitate

  • M2

    (after addition of NH3(aq))……precipitate remains / precipitate does not dissolve / precipitate does not disappear

2a · 2 marks

  • M1

    (down the group) (atomic radius) increases OR (atom) volume increases OR Ne < Ar < Kr < Xe

  • M2

    (down the group) the number of shells (of electrons) increases

2b · 3 marks

  • M1

    neon / Ne (most like an ideal gas)

  • M2

    it has the smallest volume

  • M3

    weakest vdw / temporary dipole – induced dipole attractions / London (dispersion) forces / London forces

2c · 4 marks

  • M1

    PV=nRT

  • M2

    use of appropriate pressure value with volume e.g. convert volume to m3 and kPa to Pa OR 101 × 617.0 × 10-3 etc.

  • M3

    calculate value for n n = (101 000 × 617.0 × 10 -6) ÷ 8.31 × 300 = 0.024997 / 0.025

  • M4

    (1.775 / Mr(X) = 0.02499 / 0.025) Mr = 71(.0)

3a · 2 marks

  • 1 mark

    correct shape profile

  • 1 mark

    arrow label ΔH from reactant line to product line AND arrow label EA (from reactant line to maximum on hump)

3b · 2 marks

  • M1

    (if a change in conditions occurs) the equilibrium shifts

  • M2

    to minimise the change (in conditions)

3c · 3 marks

  • 1 mark

    effect on value of equilibrium constant, Kp: decreases, no change

  • 1 mark

    effect on yield of product at equilibrium: decreases, no change

  • 1 mark

    effect on rate of reaction: increases, decreases

3d(i) · 3 marks

  • M1

    amount at equilibrium for SO2(g) = 0.04(0)

  • M2

    amount at equilibrium for O2(g) = (2-0.98) = 1.02

  • M3

    mol fraction at equilibrium for SO3(g) = (1.96 / 3.02) = 0.649(007)

3d(ii) · 3 marks

  • M1

    correct expression for Kp using numerical values

  • M2

    correct value for Kp.

  • M3

    kPa–1

4a(i) · 2 marks

  • 2 marks

    primary hydroxy groups: 2, secondary hydroxy groups: 1, tertiary hydroxy groups: 1

4a(ii) · 2 marks

  • M1

    Na(s): effervescence / fizzing / bubbling

  • M2

    2,4-dinitrophenylhydrazine (2,4-DNPH): none

4a(iii) · 1 mark

  • 1 mark

    Alcohols / Compound V are / is not oxidised by Fehling’s reagent (aldehydes are oxidised by Fehling’s reagent) OR Aldehydes are oxidised by Fehling’s reagent (alcohols / Compound V are / is not oxidised by Fehling’s reagent)

4b(i) · 1 mark

  • 1 mark

    (colour of mixture at start of the reaction) ……orange (colour of mixture after the reaction) ……green

4b(ii) · 1 mark

  • 1 mark

    Structure of (HOOC)C=OC(COOH)(OH)CH3 / displayed/skeletal formula given

4c(i) · 2 marks

  • M1

    (molecules / isomers with) the same molecular formula / same number of atoms of each element

  • M2

    different arrangement of atoms

4c(ii) · 2 marks

  • M1

    compound W AND compound V

  • M2

    both have (2) chiral centres / (2) asymmetric carbon atoms

4c(iii) · 1 mark

  • 1 mark

    methanoic acid

4d(i) · 1 mark

  • 1 mark

    (isomer) Y

4d(ii) · 1 mark

  • 1 mark

    3 C5H12O4 + 8 Cr2O72- + 64 H+ → 3 C5H4O8 + 16 Cr3+ + 44 H2O

5a(i) · 2 marks

  • 2 marks

    Correct identification/structure and systematic names of products in table

5a(ii) · 1 mark

  • 1 mark

    free-radical substitution

5b(i) · 1 mark

  • 1 mark

    1s² 2s² 2p⁶ 3s² 3p⁵ orbital diagram showing pairs in 1s, 2s, three pairs in 2p, pair in 3s, and two pairs and one single electron in 3p

5b(ii) · 2 marks

  • M1

    CH3CH2CH3 + Cl → CH2CH2CH3 + HCl

  • M2

    CH2CH2CH3 + Cl2 → CH3CH2CH2Cl + Cl

5b(iii) · 2 marks

  • M1

    CH3CH2CH3+ Cl → CH3CHCH3 + HCl

  • M2

    2 CH3CHCH3 → (CH3)2CHCH(CH3)2

5c(i) · 2 marks

  • M1

    two Cl isotopes

  • M2

    35Cl is 3 times more abundant than 37Cl

5c(ii) · 2 marks

  • 2 marks

    84: (CH235Cl2)+, 86: (CH235Cl37Cl)+, 88: (CH237Cl2)+

Questions

  1. 1
    Question 112 marks
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  2. 2
    Question 29 marks
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  3. 3
    Question 313 marks
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  4. 4
    Question 414 marks
    Mark scheme ›
  5. 5
    Question 512 marks
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