A Level Physics 9702 Paper 23, Oct/Nov 2024

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Question paper

9702/23 · Oct/Nov 2024

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1
Figure 1 of 2 for question 1
Figure 2 of 2 for question 1
a

Define acceleration.

[1]
b(i)

A small aircraft is flying horizontally at a speed of 42 ms−1 at a height of 63 m above horizontal ground, as shown in Fig. 1.1. Fig. 1.1 The aircraft drops a small parcel. The parcel is released from the aircraft at the instant shown in Fig. 1.1. Air resistance is negligible. On Fig. 1.1, draw a line to show the path of the parcel as it falls from the aircraft to the ground.

[1]
b(ii)

Calculate the time taken from the instant of release to the instant the parcel reaches the ground. time=...................................................... s

[2]
b(iii)

Calculate the vertical component of the velocity of the parcel immediately before it reaches the ground. vertical component of velocity=................................................ ms−1

[1]
b(iv)

Determine the speed at which the parcel reaches the ground. speed=................................................ ms−1

[2]
2
Figure 1 of 2 for question 2
Figure 2 of 2 for question 2
a

State the principle of conservation of momentum.

[2]
b(i)

A ball X has mass 240 g and moves in a straight line on a horizontal frictionless surface with an initial speed of 16 ms−1. The ball collides with a stationary ball Y that has mass 480 g. After the collision, ball X is stationary, as shown in Fig. 2.1. Fig. 2.1 Show that the speed v of ball Y after the collision is 8.0 ms−1.

[1]
b(ii)

Calculate the change in the total kinetic energy ΔEK of the balls due to the collision. ΔEK=...................................................... J

[3]
c(i)

The collision in (b) lasts for a time of 2.0 ms. Assume that the contact force between the balls is constant during this time. Determine the magnitude and direction of the force exerted on ball X by ball Y during the collision. magnitude=........................................................... N direction ...............................................................

[3]
c(ii)

Compare the magnitude and direction of the force exerted on ball Y by ball X during the collision with the answers in (c)(i). No further calculations are required.

[2]
3
Figure 1 of 2 for question 3
Figure 2 of 2 for question 3
a

State the principle of moments.

[1]
b(i)

A rigid uniform beam rests on a pivot at its centre, as shown in Fig. 3.1. Fig. 3.1 (not to scale) A load of weight 2.6 N is suspended from the beam at distance x from the pivot. A wooden cylinder of weight 4.0 N is suspended from the beam at a distance of 0.40 m from the pivot on the opposite side of the pivot to the load. The cylinder rests in a container of water. The lower part of the cylinder is immersed in the water to depth h. Initially, h is equal to 0.10 m and x is equal to 0.40 m. The system is in equilibrium. Use the principle of moments to show that the upthrust U exerted by the water on the cylinder is 1.4 N.

[2]
b(ii)

The density of the water is 1.0×103 kg m−3. Calculate the area A of the circular cross-section of the cylinder. A=.................................................... m2

[3]
c

More water is gradually added to the container in (b), so that depth h in Fig. 3.1 gradually increases. The length x is continuously adjusted so that the system remains in equilibrium. On Fig. 3.2, sketch the variation of x with h. Use the space below for any working. Fig. 3.2

[3]
4
Figure 1 of 1 for question 4
a(i)

Define: stress

[1]
a(ii)

strain.

[1]
b(i)

Two wires X and Y, with equal unstretched lengths of 0.84 m, are suspended from fixed points that are at the same horizontal level. The lower ends of the wires are attached to a beam of negligible mass. The beam is horizontal and in equilibrium, as shown in Fig. 4.1. Fig. 4.1 Wire X is made from a metal that has a Young modulus of 1.9×109 Pa. Wire Y is made from a different metal. A load of weight 18 N is suspended from the beam at a point that is equidistant from the two wires. This load causes both wires to extend by 0.47 mm. Determine the cross-sectional area of wire X. cross-sectional area=.................................................... m2

[3]
b(ii)

Wire Y has a greater diameter than wire X. Explain, without calculation, whether the Young modulus of the metal from which wire Y is made is less than, the same as or greater than 1.9×109 Pa.

[2]
5
Figure 1 of 3 for question 5
Figure 2 of 3 for question 5
Figure 3 of 3 for question 5
a(i)

A stationary wave is formed on a string XY that has a length of 0.48 m. Fig. 5.1 shows the string at one instant in time. Fig. 5.1 The speed of the wave on the string is 1400 ms−1. On Fig. 5.1, draw a cross (×) at one position that is a node and another cross at one position that is an antinode. Label the node N and the antinode A.

[1]
a(ii)

Show that the wavelength of the wave produced is 0.32 m. Explain your reasoning.

[1]
a(iii)

Calculate the frequency of the wave. frequency=.................................................... Hz

[2]
b(i)

A source of sound waves of frequency 780 Hz is on a rotating platform. The speed of the source is 39 ms−1. The sound is detected by an observer that is a large distance from the rotating platform, as shown in Fig. 5.2. Fig. 5.2 (not to scale) The speed of sound in air is 320 ms−1. Calculate the maximum frequency of the sound detected by the observer. maximum frequency=.................................................... Hz

[2]
b(ii)

At time t=0, the observer detects the sound emitted by the source when it was in the position shown in Fig. 5.2. On Fig. 5.3, sketch the variation with t of the frequency f of the sound detected by the observer for one complete rotation of the platform. Calculations are not required. Fig. 5.3

[2]
6
a

Define resistance.

[1]
b(i)

A cylindrical metal wire of length 2.4 m and cross-sectional area 8.0×10−6 m2 has a resistance of 0.33 Ω. There is a current in the wire of 4.7 A. Determine the resistivity of the metal from which the wire is made. resistivity=.................................................. Ωm

[2]
b(ii)

Calculate the charge that passes through the wire in a time of 5.0 minutes. charge=..................................................... C

[2]
b(iii)

The free electrons (charge carriers) in the wire have an average drift speed of 0.16 mms−1. Determine the number density of charge carriers in the metal. number density=.................................................. m−3

[2]
c(i)

The wire in (b) may be considered to be a fixed resistor. It is connected in series with a thermistor to a battery that has negligible internal resistance. Use circuit symbols to complete Fig. 6.1 to show the circuit diagram of this arrangement. Fig. 6.1

[1]
c(ii)

Explain, without calculation, how the power dissipated in the wire changes as the temperature of the thermistor is increased.

[2]
7
a

Complete Table 7.1 to show the charges, in terms of the elementary charge e, on each of the flavours of quark and antiquark shown. Table 7.1

flavourcharge / e
quarkantiquark
up
down
strange
[3]
b(i)

State the name of the class (group) of fundamental particles to which baryons and mesons belong.

[1]
b(ii)

Compare baryons and mesons in terms of their constituent particles.

[2]
c

Describe β+ decay in terms of the fundamental particles involved.

[2]

Mark scheme

9702/23 · Oct/Nov 2024

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1a · 1 mark

  • B1

    rate of change of velocity

1b(i) · 1 mark

  • B1

    curved path from aircraft to ground, starting horizontal at aircraft and then with increasing negative gradient as it moves towards the ground

1b(ii) · 2 marks

  • C1

    s = ut + ½at2 63 = ½  9.81  t2

  • A1

    time = 3.6 s

1b(iii) · 1 mark

  • A1

    v2 = 2  9.81  63 or v = 0 + (9.81  3.6) or 63 = (v  3.6) – (½  9.81  3.62) or 63 = ½  (0 + v)  3.6 v = 35 m s–1

1b(iv) · 2 marks

  • C1

    speed2 = 352 + 422

  • A1

    speed = 55 m s–1

2a · 2 marks

  • M1

    sum / total momentum (of a system of bodies) is constant or sum / total momentum before = sum / total momentum after

  • A1

    for an isolated system / no (resultant) external force

2b(i) · 1 mark

  • A1

    240  16 = 480v and so v = 8.0 m s–1 or (initial momentum =) 240  16 (= 3840 g m s–1) and v = 3840 / 480 = 8.0 m s–1

2b(ii) · 3 marks

  • C1

    (EK =) ½ mv2

  • C1

    EK = ½ [(0.24  162) – (0.48  8.02)]

  • A1

    = 15 J

2c(i) · 3 marks

  • C1

    F = (0.24  16) / (2.0  10–3) or F = (0.48  8) / (2.0  10–3)

  • A1

    = 1900 N

  • B1

    direction: to the left

2c(ii) · 2 marks

  • B1

    equal (magnitude)

  • B1

    opposite (direction)

3a · 1 mark

  • B1

    (for a system in equilibrium,) sum of clockwise moments (about a point) equals sum of anticlockwise moments (about the same point)

3b(i) · 2 marks

  • C1

    2.6  0.40 or F  0.40 (any one moment) or 2.6  0.4 or (4.0 − U)  0.4

  • A1

    U = 4.0 – F = 4.0 – (2.6  0.40 / 0.40) = 1.4 N or 2.6  0.4 = (4.0 − U)  0.4 hence U = (4.0 − 2.6) = 1.4 N

3b(ii) · 3 marks

  • C1

    U = gV and A = V / h or p = hg and A = U / p or A = U / hg

  • C1

    A = 1.4 / (0.10  1.0  103  9.81)

  • A1

    = 1.4  10–3 m2

3c · 3 marks

  • B1

    line starting at (0.10, 0.40)

  • B1

    straight line with negative gradient

  • B1

    line ending at (0.29, 0)

4a(i) · 1 mark

  • B1

    (normal) force per unit cross-sectional area

4a(ii) · 1 mark

  • B1

    extension per unit unstretched length

4b(i) · 3 marks

  • C1

    E = FL / Ax

  • C1

    A = (9.0  0.84) / (1.9  109  0.47  10–3)

  • A1

    = 8.5  10–6 m2

4b(ii) · 2 marks

  • B1

    F, L and x are all the same (for both wires / as in X) or F and strain are the same

  • B1

    A is greater (for Y), so the Young modulus (for Y) is less than 1.9  109 Pa or less than that of wire X

5a(i) · 1 mark

  • B1

    cross labelled N marked at the intersection of the solid and dashed lines or at X or Y and cross labelled A marked at a peak or a trough

5a(ii) · 1 mark

  • B1

    (XY is 1.5 wavelengths, so) wavelength = 0.48  (2 / 3) = 0.32 m or (wavelength is twice node–node distance so)  / 2 = 0.48 / 3 = 0.16 m and wavelength = 0.16  2 = 0.32 m

5a(iii) · 2 marks

  • C1

    v = f

  • A1

    frequency = 1400 / 0.32 = 4400 Hz

5b(i) · 2 marks

  • C1

    fo = fsv / (v – vs) fo = (780  320) / (320 – 39)

  • A1

    maximum frequency = 890 Hz

5b(ii) · 2 marks

  • B1

    line showing f varying both above and below a mean frequency and returning to the original start value of f

  • B1

    a single cycle of a smoothly oscillating curve of correct phase (starting at mean position, falling to a trough, then rising to a peak, ending at mean position)

6a · 1 mark

  • B1

    potential difference per unit current

6b(i) · 2 marks

  • C1

     = RA / L

  • A1

    = (0.33  8.0  10–6) / 2.4 = 1.1  10–6  m

6b(ii) · 2 marks

  • C1

    Q = It

  • A1

    = 4.7  5.0  60 = 1400 C

6b(iii) · 2 marks

  • C1

    I = nAvq n = 4.7 / (8.0  10–6  0.16  10–3  1.60  10–19)

  • A1

    = 2.3  1028 m–3

6c(i) · 1 mark

  • B1

    correct symbols for resistor and thermistor, shown correctly connected in series with the battery

6c(ii) · 2 marks

  • M1

    (as temperature increases) resistance of thermistor decreases

  • A1

    (total resistance decreases so) greater current (in circuit/wire) so power (dissipated in the wire) increases or (total resistance decreases so) greater (share of) p.d. across wire so power (dissipated in the wire) increases

7a · 3 marks

  • B1

    up quark charge = (+) 2 / 3 and down quark charge = −1 / 3

  • B1

    strange quark charge = −1 / 3

  • B1

    up antiquark charge = –2 / 3 and down antiquark charge = (+) 1 / 3 and strange antiquark charge = (+) 1 / 3

7b(i) · 1 mark

  • B1

    hadron(s)

7b(ii) · 2 marks

  • B1

    baryons composed of three quarks or baryons composed of three antiquarks

  • B1

    mesons composed of one quark and one antiquark

7c · 2 marks

  • B1

    up quark changes to a down quark

  • B1

    positron and (electron) neutrino (emitted)

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  1. 1
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  2. 2
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  3. 3
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  4. 4
    Question 47 marks
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  5. 5
    Question 58 marks
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  6. 6
    Question 610 marks
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  7. 7
    Question 78 marks
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