A Level Physics 9702 Paper 42, May/June 2024

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Question paper

9702/42 · May/June 2024

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1
Figure 1 of 2 for question 1
Figure 2 of 2 for question 1
a

Define the radian.

[1]
b(i)

A circular metal disc spins horizontally about a vertical axis, as shown in Fig. 1.1. A piece of modelling clay is attached to the disc. For the instant when the piece of modelling clay is in the position shown, draw on Fig. 1.1: an arrow, labelled V, showing the direction of the velocity of the modelling clay

[1]
b(ii)

an arrow, labelled A, showing the direction of the acceleration of the modelling clay.

[1]
c(i)

The metal disc in Fig. 1.1 has a radius of 9.3 cm. The centre of gravity of the modelling clay is 1.2 cm from the rim of the disc and moves with a speed of 0.68 m s−1. Calculate the angular speed ω of the disc. ω=.............................................. rad s−1

[2]
c(ii)

Calculate the acceleration a of the centre of gravity of the modelling clay. a=................................................ m s−2

[2]
d

A second piece of modelling clay is attached to the disc in the position shown in Fig. 1.2. The second piece of modelling clay has a larger mass than the first piece. By placing one tick (✓) in each row, complete Table 1.1 to show how the quantities indicated compare for the two pieces of modelling clay. Table 1.1

quantityless for second piece than first piecesame for both piecesgreater for second piece than first piece
angular speed
linear speed
acceleration
[3]
2
Figure 1 of 1 for question 2
a

With reference to thermal energy, state what is meant by two objects being in thermal equilibrium.

[1]
b(i)

Two cylinders X and Y each contain a sample of an ideal gas. The samples are in thermal equilibrium with each other. X has a volume of 0.0260 m3 and contains 0.740 mol of gas at a pressure of 1.20×105 Pa. Y has a volume of 0.0430 m3 and contains gas at a pressure of 2.90×105 Pa. Data for the two cylinders are shown in Fig. 2.1. Show that the temperature of the gas in X is 234 ∘C.

[3]
b(ii)

Determine the number N of molecules of the gas in Y. Explain your reasoning. N=.........................................................

[3]
b(iii)

The gas in X consists of molecules that each have a mass that is four times the mass of a molecule of the gas in Y. Explain how the root-mean-square (r.m.s.) speed of the molecules in X compares with the r.m.s. speed of the molecules in Y.

[3]
3
a

State what is meant by the internal energy of a system.

[2]
b(i)

With reference to molecular kinetic and potential energies, describe and explain how the internal energy of the system changes when: a gas is heated at constant volume so that its temperature increases

[3]
b(ii)

With reference to molecular kinetic and potential energies, describe and explain how the internal energy of the system changes when: a wire is stretched within its elastic limit at constant temperature.

[3]
4

A block of mass m oscillates vertically on a spring, as shown in Fig. 4.1. The acceleration a of the block varies with displacement x from its equilibrium position, as shown in Fig. 4.2. The amplitude of the oscillations is 3Y and the maximum acceleration is 2A.

Figure 1 of 2 for question 4
Figure 2 of 2 for question 4
a

Explain how Fig. 4.2 shows that the oscillations of the block are simple harmonic.

[2]
b(i)

Deduce expressions, in terms of some or all of m, A and Y, for: the angular frequency ω of the oscillations ω=.........................................................

[1]
b(ii)

Deduce expressions, in terms of some or all of m, A and Y, for: the maximum speed v0 of the oscillations v0=.........................................................

[2]
b(iii)

Deduce expressions, in terms of some or all of m, A and Y, for: the energy E of the oscillations. E=.........................................................

[2]
c

The period of the oscillations is 0.75 s and the value of 3Y is 1.8 cm. Determine an expression for x in terms of time t, where x is in cm and t is in seconds. x=.........................................................

[2]
5
Figure 1 of 2 for question 5
Figure 2 of 2 for question 5
a

Define electric potential at a point.

[2]
b

Two isolated charged metal spheres X and Y are near to each other in a vacuum. The centres of the spheres are 1.2 m apart, as shown in Fig. 5.1. Point P is on the line joining the centres of spheres X and Y and is at a variable distance x from the centre of X. Fig. 5.2 shows the variation with x of the total electric potential V due to the two spheres. State three conclusions that may be drawn about the spheres from Fig. 5.2. The conclusions may be qualitative or quantitative. 1 ................................................................................................................................ ................................................................................................................................... 2 ................................................................................................................................ ................................................................................................................................... 3 ................................................................................................................................ ...................................................................................................................................

[3]
c

A proton is held at rest on the line joining the centres of the spheres in (b) at the position where x=0.60 m. The proton is released. Describe and explain, without calculation, the subsequent motion of the proton.

[2]
6
Figure 1 of 2 for question 6
Figure 2 of 2 for question 6
a

Two capacitors X and Y are connected in series to a power supply of voltage V, as shown in Fig. 6.1. The capacitance of X is CX and the capacitance of Y is CY. Derive an expression, in terms of CX and CY, for the combined capacitance CT of the capacitors in this circuit. Explain your reasoning.

[3]
b(i)

Two capacitors P and Q are connected in parallel to a power supply of voltage V. The capacitance of P is 200 μF. The capacitance CQ of Q can be varied between 0 and 400 μF. When CQ=0, the total energy stored in the capacitors is 2.5 mJ. Show that the supply voltage V is 5.0 V.

[2]
b(ii)

Calculate the total energy, in mJ, stored in the capacitors when CQ has its maximum value. total energy=................................................... mJ

[3]
b(iii)

On Fig. 6.2, sketch the variation of the total energy E stored in the capacitors with CQ, as CQ varies from 0 to 400 μF.

[2]
7
Figure 1 of 3 for question 7
Figure 2 of 3 for question 7
Figure 3 of 3 for question 7
a

State Faraday’s law of electromagnetic induction.

[2]
b(i)

Fig. 7.1 shows a coil at rest in a uniform magnetic field that is parallel to the axis of the coil. The coil is connected to a centre-zero voltmeter. The flux density B of the uniform magnetic field varies with time t as shown in Fig. 7.2. The coil consists of 340 turns, each of cross-sectional area 3.2×10−4 m2. Calculate the maximum magnetic flux through one turn of the coil. maximum magnetic flux=................................................... Wb

[2]
b(ii)

Determine the maximum rate of change of magnetic flux linkage in the coil. maximum rate of change of flux linkage=............................................. Wb s−1

[3]
b(iii)

State the maximum electromotive force (e.m.f.) V0 induced across the coil. V0=...................................................... V

[1]
b(iv)

On Fig. 7.3, sketch the variation of the e.m.f. V induced across the coil with t from t=0 to t=6.0 ms.

[3]
b(v)

The variation of V with t can be described by V=Asin⁡Bt where A and B are constants. Determine the values of A and B. Give units with your answers. A=.......................................unit ................ B=.......................................unit ................

[3]
8

Fig. 8.1 shows part of the emission spectrum of visible radiation emitted by hydrogen gas in a star in a distant galaxy. The galaxy is moving away from the Earth at a speed of 6.2×106 m s−1.

Figure 1 of 1 for question 8
a(i)

Explain how the positions of the lines in the emission spectrum seen by an observer on the Earth differ from the positions shown in Fig. 8.1.

[2]
a(ii)

On Fig. 8.1, draw the three lines in possible positions in the spectrum seen by the observer.

[2]
b(i)

The lines in Fig. 8.1 correspond to electron transitions down to the energy level −3.40 eV. One of the lines represents emitted radiation of wavelength 488 nm. Calculate the energy of a photon of this radiation. photon energy=...................................................... J

[2]
b(ii)

Determine the energy, in eV, of the energy level from which the electron transition originates to cause the emission of this radiation. energy level=.................................................... eV

[2]
b(iii)

Determine the wavelength, in nm, of this radiation as detected by the observer on the Earth. wavelength=................................................... nm

[2]
c

A value for the Hubble constant is 2.3×10−18 s−1. Determine the distance of the galaxy from the Earth. distance=..................................................... m

[2]
9
Figure 1 of 1 for question 9
a

State what is meant by the binding energy of a nucleus.

[2]
b(i)

Table 9.1 shows the masses of two sub-atomic particles and a polonium-212 (84212Po) nucleus. Table 9.1

mass /u
proton1.007 276
neutron1.008 665
polonium-212 nucleus211.942 749

For the polonium-212 nucleus, determine: the mass defect Δm, in kg Δm=.................................................... kg

[3]
b(ii)

For the polonium-212 nucleus, determine: the binding energy binding energy=...................................................... J

[2]
b(iii)

For the polonium-212 nucleus, determine: the binding energy per nucleon. binding energy per nucleon=...................................................... J

[1]
c(i)

On Fig. 9.1, sketch the variation with nucleon number A of binding energy per nucleon for values of A from 1 to 250.

[2]
c(ii)

On your line in Fig. 9.1, draw an X to show the approximate position of polonium-212.

[1]
c(iii)

Polonium-212 is radioactive and undergoes alpha-decay. Suggest and explain, with reference to Fig. 9.1, why the alpha-decay of polonium-212 results in a release of energy.

[2]
10
a

Describe how reflected ultrasound pulses may be used to obtain diagnostic information about internal structures.

[2]
b(i)

Define specific acoustic impedance of a medium.

[2]
b(ii)

Table 10.1 shows some data for water and for glass. Table 10.1

density / kg m−3speed of sound / m s−1
water10001420
glass25004560

Determine the intensity reflection coefficient for ultrasound that is incident on a water–glass boundary. intensity reflection coefficient=.........................................................

[3]

Mark scheme

9702/42 · May/June 2024

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1a · 1 mark

  • B1

    angle (subtended at the centre of a circle) when arc (length) = radius

1b(i) · 1 mark

  • B1

    arrow, labelled V, pointing in NE direction

1b(ii) · 1 mark

  • B1

    arrow, labelled A, pointing in NW direction

1c(i) · 2 marks

  • C1

    v=rω

  • A1

    ω=0.68/(0.093−0.012) =8.4 rad s−1

1c(ii) · 2 marks

  • C1

    a=v2/r or a=rω2

  • A1

    a=0.682/(0.093−0.012) or (0.093−0.012)×8.42 =5.7 m s−2

1d · 3 marks

  • B1

    angular speed: same for both pieces

  • B1

    linear speed: less for second piece than first piece

  • B1

    acceleration: less for second piece than first piece

2a · 1 mark

  • B1

    (if in thermal contact) no net transfer of (thermal) energy (between them)

2b(i) · 3 marks

  • C1

    pV=nRT

  • M1

    T=(1.20×105×0.0260)/(0.740×8.31) (=507 K)

  • A1

    temperature =507−273=234 ∘C

2b(ii) · 3 marks

  • B1

    thermal equilibrium so temperatures (of X and Y) are equal

  • C1

    pV=NkT

  • A1

    N=(2.90×105×0.0430)/(1.38×10−23×507) =1.78×1024

2b(iii) · 3 marks

  • B2

    - (molecular) kinetic energy is proportional to temperature or kinetic energy (of molecules) is same in both cylinders - kinetic energy proportional to mass × mean-square speed or temperature proportional to mass × mean-square speed or r.m.s. speed proportional to (temperature / mass) - mean-square speed inversely proportional to mass or r.m.s. speed inversely proportional to (mass)

  • B1

    r.m.s. speed (of molecules) in X is half r.m.s. speed (of molecules) in Y

3a · 2 marks

  • B1

    sum of potential energy and kinetic energy

  • B1

    (total) energy of random motion of particles

3b(i) · 3 marks

  • B1

    no change in separation so no change in (molecular) potential energy

  • B1

    temperature increases so kinetic energy (of molecules) increases

  • B1

    kinetic energy increases and potential energy unchanged, so internal energy increases

3b(ii) · 3 marks

  • B1

    temperature constant so no change in (molecular) kinetic energy

  • B1

    separation increases so potential energy (of molecules) increases

  • B1

    potential energy increases and kinetic energy unchanged, so internal energy increases

4a · 2 marks

  • B1

    straight line through the origin shows that a is proportional to x

  • B1

    negative gradient shows that a and x are (always) in opposite directions

4b(i) · 1 mark

  • A1

    a=−ω2x ω=(2A/3Y)

4b(ii) · 2 marks

  • C1

    v0=ωx0

  • A1

    =3Y×(2A/3Y) =(6AY)

4b(iii) · 2 marks

  • C1

    E=12mω2x02

  • A1

    =12m×(2A/3Y)×(3Y)2 =3mAY

4c · 2 marks

  • C1

    ω=2π/T (=2π/0.75)

  • A1

    x=1.8sin⁡(8.4t)

5a · 2 marks

  • B1

    work done per unit charge

  • B1

    work (done) moving positive charge from infinity (to the point)

5b · 3 marks

  • B3

    Any three points from: Up to 2 points from: - radius of sphere X is 0.30 m - radius of sphere Y is 0.10 m - radius of X is treble the radius of Y Up to 2 points from: - charge on X is positive - charge on Y is positive - spheres X and Y carry charges of the same sign Up to 1 point from: - (magnitudes of) charges on the spheres are equal - charges on the spheres have the same magnitude

5c · 2 marks

  • M1

    proton remains at rest (in the position of release)

  • A1

    potential energy of proton is (already) at its minimum or (electric) forces (from spheres) on proton are equal and opposite or no resultant (electric) force on proton or resultant electric field strength (at proton) is zero

6a · 3 marks

  • B1

    equal charge on both capacitors

  • M1

    VX+VY=V

  • A1

    (Q/CX)+(Q/CY)=(Q/CT) leading to (1/CX)+(1/CY)=(1/CT) or (VX/Q)+(VY/Q)=(V/Q) leading to (1/CX)+(1/CY)=(1/CT)

6b(i) · 2 marks

  • C1

    E=12CV2

  • A1

    V=[(2×2.5×10−3)/(200×10−6)]=5.0 V

6b(ii) · 3 marks

  • C1

    total capacitance =600 μF

  • C1

    E=12×600×10−6×5.02 (=7.5×10−3 J)

  • A1

    =7.5 mJ

6b(iii) · 2 marks

  • B1

    line with positive gradient starting at (0, 2.5)

  • B1

    straight line passing through (400, 7.5)

7a · 2 marks

  • M1

    (induced) e.m.f. is (directly) proportional to rate

  • A1

    of change of (magnetic) flux (linkage)

7b(i) · 2 marks

  • C1

    Φ=BA

  • A1

    =7.2×10−3×3.2×10−4 =2.3×10−6 Wb

7b(ii) · 3 marks

  • C1

    tangent drawn at steepest point on Fig. 7.2

  • C1

    evidence of multiplication by 340

  • A1

    maximum rate of change of flux =0.82 Wb s−1

7b(iii) · 1 mark

  • A1

    V0=0.82 V or V0 given as identical numerical answer to the answer in (b)(ii)

7b(iv) · 3 marks

  • B1

    sinusoidal curve of period 2.0 ms from t=0 to t=6.0 ms

  • B1

    all peaks at +V0 and all troughs at −V0

  • B1

    line showing V=0 at (and only at) t=0,1.0,2.0,3.0,4.0,5.0 and 6.0 ms

7b(v) · 3 marks

  • A1

    A=0.82 V or A has same numerical value as answer in (b)(iii), with unit V

  • C1

    B=2π/(2.0×10−3)

  • A1

    =3100 rad s−1

8a(i) · 2 marks

  • B1

    movement of star causes change in (observed) frequency or movement of star causes redshift

  • B1

    observed frequency is lower (than emitted frequency)

8a(ii) · 2 marks

  • B1

    all three lines shown to left of corresponding printed lines

  • B1

    distance between drawn line and corresponding printed line approximately the same for all three lines

8b(i) · 2 marks

  • C1

    E=hf and λ=c/f

  • A1

    E=(6.63×10−34×3.00×108)/(488×10−9) =4.08×10−19 J

8b(ii) · 2 marks

  • C1

    photon energy =(4.08×10−19)/(1.60×10−19) =2.55 eV

  • A1

    energy level =−3.40+2.55 =−0.85 eV

8b(iii) · 2 marks

  • C1

    Δλ=λ×(v/c) =(488×6.2×106)/(3.00×108) (=10 nm)

  • A1

    observed wavelength =488+Δλ=488+10 =498 nm

8c · 2 marks

  • C1

    v=H0d

  • A1

    d=(6.2×106)/(2.3×10−18) =2.7×1024 m

9a · 2 marks

  • M1

    energy required to separate (all) the nucleons (in the nucleus)

  • A1

    to infinity

9b(i) · 3 marks

  • C1

    Δm={[(84×1.007276)+(128×1.008665)]−211.942749} (u) (=1.778 u)

  • C1

    =1.778×1.66×10−27 (kg)

  • A1

    =2.95×10−27 kg

9b(ii) · 2 marks

  • C1

    E=(Δ)mc2

  • A1

    binding energy =2.95×10−27×(3.00×108)2 =2.66×10−10 J

9b(iii) · 1 mark

  • A1

    binding energy per nucleon =(2.66×10−10)/212 =1.25×10−12 J

9c(i) · 2 marks

  • B1

    line rising to a single peak that is to the left of the ‘9’ in the Fig. 9.1 label and then continually decreasing

  • B1

    steep positive gradient on the left of the peak and shallow negative gradient on the right

9c(ii) · 1 mark

  • B1

    X shown on the line at a value of A that is to the right of the left-hand edge of the ‘A’ in the axis label, and to the left of ‘2’ in the 250 label

9c(iii) · 2 marks

  • B1

    nucleus formed (as a result of the decay) has a lower nucleon number

  • B1

    (nucleus formed has a) greater binding energy per nucleon

10a · 2 marks

  • B1

    time gives information about depth (of boundary)

  • B1

    intensity gives information about nature of boundary

10b(i) · 2 marks

  • M1

    product of density and speed

  • A1

    speed of ultrasound in medium (and density of medium)

10b(ii) · 3 marks

  • C1

    Zwater=1000×1420 (=1.42×106 kg m−2 s−1) and Zglass=2500×4560 (=11.4×106 kg m−2 s−1)

  • C1

    intensity reflection coefficient =(11.4−1.42)2/(11.4+1.42)2

  • A1

    =0.61

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