A Level Further Mathematics 9231 Paper 21, May/June 2026

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Question paper

9231/21 · May/June 2026

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1

Find the first three terms in the Maclaurin’s series for sinh⁡−1(x+1) in the form ln⁡a+bx+cx2, giving the exact values of the constants a, b and c.

[5]
2

Let In=∫01(1+t)nsin⁡πt dt, where n is a non-negative integer.

a

Show that, for n⩾2, π2In=π(2n+1)−n(n−1)In−2.

[4]
b

Find the exact value of I2.

[3]
3
a

Using the substitution u=cosh⁡x, find ∫sinh⁡3x dx.

[4]
b

Find the particular solution of the differential equation dydx+ycoth⁡x=sinh⁡2x, given that y=0 when x=ln⁡13. Give your answer in the form y=f(x).

[7]
4

The curve C has equation (x−y)5+ln⁡(xy)=1+ln⁡2.

Figure 1 of 1 for question 4
a

Show that, at the point (−1,−2) on C, dydx=811.

[3]
b

Find the value of d2ydx2 at the point (−1,−2).

[5]
5

The diagram shows the curve with equation y=1110x3+110 for 0⩽x⩽1, together with a set of n rectangles of width 1n.

a

By considering the sum of the areas of these rectangles, show that ∫01(1110x3+110)dx<Un, where Un=1140(1+1n)2+110.

[4]
b

Use a similar method to find, in terms of n, a lower bound Ln for ∫01(1110x3+110)dx.

[4]
c

Show that lim⁡n→∞(Un−Ln)=0.

[2]
6

Find the particular solution of the differential equation 5d2ydx2+4dydx+y=x2+7x+1, given that, when x=0, y=0 and dydx=0.

[10]
7
a

State the sum of the series z+z2+z3+…+zn, for z≠1.

[1]
b

Find all roots of the equation 1+z+z2+…+z6=0 in the form eiqπ, where q is rational.

[2]
c

Given instead that z=e−1+iθ, use de Moivre’s theorem to show that ∑m=1∞e−mcos⁡mθ=ecos⁡θ−1e2−2ecos⁡θ+1.

[7]
8
a

The constants a and b are such that the system of equations −x−2y+z=1,ax+y−z=2,by+2z=3 does not have a unique solution. Find a in terms of b.

[3]
b

The matrix A is given by A=(−1−2101−1002). Use the characteristic equation of A to show that A4=pA2+qI, where p and q are integers to be determined.

[4]
c

Find a matrix P and a diagonal matrix D such that A7=PDP−1.

[7]

Mark scheme

9231/21 · May/June 2026

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1 · 5 marks

  • B1

    Finds first derivative. Accept 1x+1+(x+1)2+1(1+2x+22(x+1)2+1) or implicit y′cosh⁡y=1.

  • B1

    Finds second derivative. Allow not simplified or implicit y′′cosh⁡y+(y′)2sinh⁡y=0.

  • B1

    sinh⁡−11=ln⁡(1+2)

  • M1

    Evaluates their derivatives at zero only. Must have attempted both derivatives.

  • A1

    CWO.

2a · 4 marks

  • M1

    Applies integration by parts. Allow limits missing. M1 for correct trigonometric functions and powers of (1+t).

  • A1

    Correct first integration by parts result.

  • 1 mark

    Applies integration by parts again. M1 for correct trigonometric functions and powers of (1+t).

  • A1

    AG. Must have seen limits and correct use of brackets. CWO.

2b · 3 marks

  • B1

    Finds I0.

  • M1

    Uses reduction formula from (a).

  • A1

    I2=5π−4π3

3a · 4 marks

  • B1

    u=cosh⁡x  ⟹  du=sinh⁡x dx

  • M1

    Applies correct identity sinh⁡2u=cosh⁡2u−1 to find integral in terms of u.

  • A1

    Correct integral in terms of u.

  • A1

    =13u3−u(+C)=13cosh⁡3x−cosh⁡x(+C)

3b · 7 marks

  • M1

    Finds integrating factor.

  • A1

    Integrating factor correctly simplified to sinh⁡x.

  • M1

    Correct form on LHS and attempt to integrate RHS.

  • M1

    Integrates RHS using their part (a). For M1, their answer to (a) must be of the correct form acosh⁡3x+bcosh⁡x with a,b non-zero.

  • A1

    Correct integrated form ysinh⁡x=13cosh⁡3x−cosh⁡x+C.

  • 1 mark

    Substitutes initial conditions. M0 if expression incorrectly manipulated before substitution. E.g. not all terms divided by sinh⁡x.

  • A1

    OE.

4a · 3 marks

  • B1

    Differentiates (x−y)5 correctly.

  • B1

    Differentiates ln⁡(xy) correctly.

  • B1

    Substitutes (−1,−2) into 5(x−y)4(1−y′)+y′y−1+x−1=0, AG. CWO. Might see y′(y−1−5(x−y)4)=−5(x−y)4−x−1.

4b · 5 marks

  • B1

    Differentiates first part of 5(x−y)4(1−y′).

  • B1

    Differentiates second part of 5(x−y)4(1−y′).

  • B1

    Differentiates y′y−1+x−1. Might see xy′+yxy differentiated using product or quotient rules. E.g. xy(xy′′+2y′)−(xy′+y)2(xy)2 or −(xy)−2(xy′+y)2+(xy)−1(xy′′+2y′).

  • M1

    Substitutes (−1,−2) and y′=811.

  • A1

    y′′=861331

5a · 4 marks

  • M1

    Forms the sum of the areas of the rectangles. M1 for sum of n complete terms.

  • A1

    A1 for at least 3 correct terms including first and last. May be written in summation form.

  • M1

    Applies formula for ∑r3 from MF19.

  • A1

    AG. CWO.

5b · 4 marks

  • M1

    Forms the sum of the areas of appropriate rectangles. M1 for sum of n complete terms.

  • A1

    A1 for at least 3 correct terms including first and last.

  • M1

    Applies formulae from MF19. Allow Un+110n−1210n.

  • A1

    OE. e.g. 1140(1+1n)2+110−1110n.

5c · 2 marks

  • M1

    Their Un−Ln simplifies to cn. Accept 1140(1)2+110−1140(1)2−110.

  • A1

    AG. Their Ln must be correct.

6 · 10 marks

  • M1

    Auxiliary equation. M1 for correct type of roots a±bi.

  • A1

    Complementary function. Allow ‘y=’ missing.

  • B1

    Particular integral and its derivatives.

  • M1

    Substitutes and equates coefficients.

  • A1

    q=−1r=−5

  • A1

    General solution. Must have ‘y=’. FT on CF.

  • M1

    Differentiates. General solution must be of the correct form. Must use product rule.

  • 1 mark

    Uses initial conditions.

  • A1

    A1 is both A and B correct.

  • A1

    Must have ‘y=’. CWO.

7a · 1 mark

  • B1

    z−zn+11−z or zn+1−zz−1 or z(zn−1)z−1

7b · 2 marks

  • B1

    States one root of z7=1,z≠1.

  • B1

    Five other roots. No repeats or incorrect roots, z=1 must be omitted.

7c · 7 marks

  • M1

    Applies sum to infinity and substitutes for z. Expect eiθe−eiθ.

  • A1

    Correct expression for sum to infinity with z substituted.

  • 1 mark

    Rationalises denominator. Expect eiθe−eiθ(e−e−iθe−e−iθ)=e1+iθ−1e2−e(eiθ+e−iθ)+1.

  • 1 mark

    Applies eiθ+e−iθ=2cos⁡θ (or sin⁡2θ+cos⁡2θ=1).

  • A1

    Correct simplified complex form with real and imaginary parts separated.

  • 1 mark

    Takes the real part.

  • A1

    AG.

8a · 3 marks

  • M1

    Finds determinant in terms of a and b.

  • A1

    Determinant correctly evaluated as 4a+ab−b−2.

  • A1

    a=b+2b+4[since b≠−4]

8b · 4 marks

  • B1

    Finds characteristic equation.

  • M1

    Replaces λ with A and multiplies through by A.

  • M1

    Substitutes A3=2A2+A−2I.

  • A1

    CWO

8c · 7 marks

  • B1

    Upper diagonal matrix or characteristic equation.

  • M1

    Uses vector product (or equations) to find corresponding eigenvectors. M0 if all three vectors are zero vectors.

  • A1

    First eigenvector correct.

  • A1

    Second eigenvector correct.

  • A1

    Third eigenvector correct.

  • M1

    Constructs P and D. A column of zeros or repeated column in P is M0.

  • A1

    Or correctly matched permutations of columns.

Questions

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  3. 3
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