O Level Physics 5054 Paper 21, Oct/Nov 2025

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5054/21 · Oct/Nov 2025

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1

A car is at rest on a straight horizontal road. At time t=0, the car begins to accelerate. Fig. 1.1 shows how the momentum of the car varies with time.

Figure 1 of 2 for question 1
Figure 2 of 2 for question 1
a

Use Fig. 1.1 to determine the resultant force acting on the car during the first 1.5 s of its motion. resultant force = ............................................................ N

[3]
b(i)

The car has mass m. When the momentum of the car is p, its kinetic energy is Ek. Show that p22m=Ek.

[2]
b(ii)

At t=6.0 s, the kinetic energy of the car is 5.4×105 J. Use Fig. 1.1 to determine the momentum p of the car at t=6.0 s, and use the equation in (b)(i) to determine the mass m of the car. Show your working. p= ................................................... kg m/s m= ........................................................... kg

[3]
2

In a factory, an electric motor is used to lift the boxes shown in Fig. 2.1. The boxes are placed in a cage and the motor winds a cable around a cylinder to lift the cage and boxes. The total mass of the boxes is 37 kg and they are lifted vertically through 13 m to a storage area.

Figure 1 of 2 for question 2
Figure 2 of 2 for question 2
a(i)

Calculate: the total weight of the boxes weight = ...................................................... N

[1]
a(ii)

the useful work done in lifting the boxes to the storage area. useful work done = ....................................................... J

[2]
b(i)

The e.m.f. of the power supply for the motor is 230 V. The current in the motor is 5.6 A. It takes 11 s for the motor to lift the cage and boxes to the storage area. Calculate: the total energy transferred electrically to the motor in 11 s energy = ....................................................... J

[2]
b(ii)

the percentage efficiency of the lifting process. efficiency = ......................................................%

[1]
c

Some of the energy transferred by the motor during the lifting process is not transferred usefully. State two reasons why the efficiency of the lifting process is less than 100%. 1 ................................................................................................................................................ ................................................................................................................................................... 2 ................................................................................................................................................ ...................................................................................................................................................

[2]
3

Fig. 3.1 shows a small block of ice at 0 ∘C and a plastic cup that contains 0.24 kg of water. The initial temperature of the water in the cup is 22.0 ∘C. The block of ice is dropped into the water.

Figure 1 of 1 for question 3
a

Describe, in terms of molecules, how energy is transferred by conduction from the water to the ice.

[2]
b(i)

All of the ice melts and, at equilibrium, the temperature of the water in the cup is 6.0 ∘C. The specific heat capacity of water is 4200 J/(kg ∘C). Calculate the energy transferred from the 0.24 kg of water as it cools. energy = ....................................................... J

[2]
b(ii)

Describe how the molecular structure of water at 6.0 ∘C differs from the molecular structure of ice at 0 ∘C.

[2]
b(iii)

The plastic cup containing water at 6.0 ∘C is left in a room where the room temperature is 22.0 ∘C. The temperature of the water in the cup rises slowly to room temperature. When the water at 6.0 ∘C is left in a metal cup, the temperature of the water rises to room temperature more quickly. State why the temperature of the water in the cup returns to room temperature more quickly when the cup is made from metal.

[1]
4

Fig. 4.1 shows a ray of light striking the left-hand surface of a thin glass converging lens.

Figure 1 of 2 for question 4
Figure 2 of 2 for question 4
a

Explain why the ray refracts and changes direction as it enters the glass.

[2]
b(i)

Explain what is meant by: the principal focus (focal point) of a lens

[2]
b(ii)

the focal length of a lens.

[1]
c(i)

An object O of height 1.8 cm is placed at a point 2.2 cm to the left of the centre of the lens. Fig. 4.2 is a full-scale diagram that shows the converging lens, its principal axis and its two principal focuses, F1 and F2. On Fig. 4.2, draw an arrow to represent the height and position of object O. The arrow should start on the principal axis.

[1]
c(ii)

On Fig. 4.2, draw two rays from the tip of the arrow drawn in (c)(i) to locate the position of the tip of the image I of object O. Draw an arrow to represent the image I of the object O. Label the image I.

[3]
c(iii)

State whether the image I of the object O is a real or a virtual image, and explain your answer.

[1]
5

An iron beaker containing liquid X is placed on the bench in a laboratory. Liquid X begins to evaporate slowly.

Figure 1 of 2 for question 5
Figure 2 of 2 for question 5
a

Explain why the evaporation causes the temperature of liquid X to decrease.

[2]
b(i)

The iron beaker containing liquid X is placed on an induction heater as shown in Fig. 5.1. The induction heater contains a coil of wire in which there is a high-frequency alternating current (a.c.). The alternating current in the coil generates a current in the base of the iron beaker by electromagnetic induction. Explain how electromagnetic induction generates the current in the base of the iron beaker.

[3]
b(ii)

The current in the base of the iron beaker causes the base to become hot. The temperature of the liquid at point P just above the base increases. Fig. 5.2 shows the position of point P. Explain, in terms of particles, why the density of liquid X decreases as its temperature increases.

[3]
b(iii)

The decrease in the density of the liquid at point P causes the transfer of thermal energy throughout liquid X. Explain how this happens.

[2]
6

A circuit consists of a battery of e.m.f. 9.0 V, a switch, a resistor P, an ammeter, a 4.0 Ω resistor and a voltmeter. Fig. 6.1 is the circuit diagram of the circuit.

Figure 1 of 3 for question 6
Figure 2 of 3 for question 6
Figure 3 of 3 for question 6
a

State Ohm’s law.

[2]
b(i)

Resistor P is a cylinder of length l, made from conducting modelling clay. Fig. 6.2 shows resistor P. P has a resistance of 8.0 Ω. The switch in the circuit in Fig. 6.1 is closed. Calculate the reading on the ammeter. ammeter reading = .......................................................A

[2]
b(ii)

Calculate the power transferred electrically to resistor P. power transferred = ..................................................... W

[2]
c(i)

Resistor P is removed from the circuit. The conducting modelling clay from resistor P is reshaped to make a second cylindrical resistor that has the same volume as resistor P but has a length l2. Fig. 6.3 shows the reshaped resistor. Calculate the resistance of the reshaped resistor. resistance of reshaped resistor = ...................................................... Ω

[2]
c(ii)

The reshaped resistor is connected into the circuit instead of resistor P. Calculate the new reading on the voltmeter. Show your working. voltmeter reading = ...................................................... V

[2]
7

An insulating rod is made of plastic and is initially uncharged. The rod is rubbed with a cloth and becomes negatively charged.

Figure 1 of 2 for question 7
Figure 2 of 2 for question 7
a

Describe, in terms of particles, what happens as the rod becomes negatively charged.

[2]
b(i)

A light ball has a thin conducting surface. The ball is suspended from the ceiling by an insulating thread. The ball is not charged. The negatively charged rod is brought close to the ball. Fig. 7.1 shows that the ball experiences a force attracting it towards the negatively charged rod. Explain, in terms of particles, how an electrical conductor differs from an electrical insulator.

[1]
b(ii)

The conducting surface of the ball contains both negatively charged particles and positively charged particles. Explain what happens to the negatively charged particles and to the positively charged particles as the rod is brought close to the ball.

[3]
b(iii)

Explain why the resultant force on the ball is towards the rod.

[2]
8

The nuclide notation for the radioactive isotope radon-222 is 86222Rn. An atom of radon-222 decays by the emission of an alpha particle (α-particle).

Figure 1 of 2 for question 8
Figure 2 of 2 for question 8
a

Describe how the composition of an atom of radon-222 differs from that of an atom of radon-224.

[2]
b

Radon-222 decays to an isotope of polonium (Po). Complete the nuclide equation for the decay of radon-222. 86222Ra⟶……………………α+……………………Po

[3]
c(i)

Radon-222 is used in an alpha-particle scattering experiment. Fig. 8.1 shows a beam of alpha particles from radon-222 hitting a very thin sheet of gold in a vacuum. An alpha-particle detector is moved around in the vicinity of the gold sheet. Two positions of the detector, J and K, are shown. Describe what is observed when the detector is at position J and when it is at position K. position J ........................................................................................................................... ........................................................................................................................................... ........................................................................................................................................... position K .......................................................................................................................... ........................................................................................................................................... ...........................................................................................................................................

[2]
c(ii)

Explain what these observations show about the structure of a gold atom.

[2]
9

An object moves through space. It is a large distance from any other object.

Figure 1 of 1 for question 9
a

There are no external forces acting on the object. Describe two features of the motion of the object that are a consequence of Newton’s first law. 1 ................................................................................................................................................ ................................................................................................................................................... 2 ................................................................................................................................................ ...................................................................................................................................................

[2]
b(i)

Planet X and Venus are two of the planets in the Solar System. Fig. 9.1 shows the orbit of Venus and the orbit of planet X. Both orbits are approximately circular. Venus experiences an external force as it orbits the Sun. State why a force must act on Venus to keep it following an approximately circular orbit.

[1]
b(ii)

State what causes this force, and state the direction of the force. cause ................................................................................................................................. ........................................................................................................................................... direction .............................................................................................................................

[3]
b(iii)

The average radius of the orbit of Venus is 1.1×1011 m. It takes Venus 5400 hours to complete one orbit of the Sun. Calculate the average orbital speed of Venus around the Sun. speed = .................................................. m/s

[2]
b(iv)

Planet X is closer to the Sun than Venus. State the name of planet X and state how its orbital speed around the Sun compares with the orbital speed of Venus. name ................................................................................................................................. speed ................................................................................................................................ ...........................................................................................................................................

[2]

Mark scheme

5054/21 · Oct/Nov 2025

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1a · 3 marks

  • C1

    (change in momentum / momentum =) 18 000 (kg m/ s)

  • C1

    (force =) change in momentumtime taken or 18 0001.5

  • A1

    12 000 (N)

1b(i) · 2 marks

  • B1

    (p22m=)m2v22m

  • B1

    shown to be ½mv2 (and equal to Ek / kinetic energy) Ek = ½mv2 seen

1b(ii) · 3 marks

  • B1

    39 000 seen

  • C1

    (m =) 39 00022×5.4×105

  • A1

    1400 (kg)

2a(i) · 1 mark

  • B1

    360 (N)

2a(ii) · 2 marks

  • C1

    (work done = ) Fx or 360  13

  • A1

    4700 (J)

2b(i) · 2 marks

  • C1

    (energy =) VIt or 230  5.6  11

  • A1

    1.4  104 (J)

2b(ii) · 1 mark

  • B1

    0.33 or 33%

2c · 2 marks

  • B2

    (work done / GPE) to lift the cage / cable

  • 1 mark

    (energy transferred) thermally in motor (coils)

  • 0 marks

    (work done) overcoming friction / air resistance

3a · 2 marks

  • B1

    water molecules collide with molecules in ice

  • B1

    molecules in ice vibrate faster / with more energy /more vigorously / with greater amplitude or molecules knocked out of solid lattice / bonds are broken / forces of attraction are overcome

3b(i) · 2 marks

  • C1

    (energy =) mc or 0.24  4200  (22 – 6) or 0.24  4200  16

  • A1

    1.6  104 (J)

3b(ii) · 2 marks

  • B2

    (molecules of water have) no orderly arrangement

  • 1 mark

    (molecules of water) move within the water’s volume

  • 0 marks

    (molecules of water are) closer together

  • 0 marks

    (molecules of water) slide over each other

3b(iii) · 1 mark

  • B1

    plastic is a bad (thermal) conductor) or a good (thermal) insulator or no delocalised electrons in plastic

4a · 2 marks

  • B2

    (in glass) light / it travels more slowly / at a different speed

  • 1 mark

    enters (an optically) denser medium/ medium with different refractive index

  • 0 marks

    wavelength changes (and frequency stays the same)

  • 0 marks

    angle of incidence is greater than 0

4b(i) · 2 marks

  • C1

    (point) where parallel rays meet (after refraction)

  • A1

    (point) where rays parallel to principal axis meet (after refraction) or (point) where paraxial rays meet (after refraction)

4b(ii) · 1 mark

  • B1

    distance between principal focus / focal point and (centre of) lens

4c(i) · 1 mark

  • B1

    arrow of height 1.8 cm and 2.2 cm and on left of the centre of the lens

4c(ii) · 3 marks

  • M2

    any two from: - paraxial ray from tip of O to lens and from lens to F2 - straight ray through centre of lens - ray that seems to come from F1 from tip of O to lens and emerges paraxially from lens

  • A1

    two rays traced back to image (labelled I)

4c(iii) · 1 mark

  • B1

    virtual and rays (merely) seem to come from I / do not pass through the image / object distance less than focal length / the image is upright

5a · 2 marks

  • B1

    fast(est) moving particles (more likely to) escape / molecules with high(er) (kinetic) energy escape?) or work done / energy needed to remove particles (from liquid)

  • B1

    (average kinetic) energy of molecules remaining decreases or energy transferred from internal energy of liquid /(kinetic) energy of particles

5b(i) · 3 marks

  • B1

    magnetic field (of coil) mentioned

  • B1

    magnetic field (due to a.c.) is changing / alternating /reversing

  • B1

    e.m.f. in (base of) container

5b(ii) · 3 marks

  • B1

    speed of particles increases

  • B1

    particles push each other apart

  • B1

    volume of liquid increases

5b(iii) · 2 marks

  • B1

    less dense / heated liquid rises

  • B1

    denser / cooler liquid sinks or liquid near surface sinks or convection (current) established

6a · 2 marks

  • B1

    potential difference / p.d. (across a component) is directly proportional to the current (in the component)

  • B1

    at constant temperature / physical conditions

6b(i) · 2 marks

  • C1

    (ammeter reading =) V/ R or ERP+RQ or 9.08.0+4.0

  • A1

    0.75 (A)

6b(ii) · 2 marks

  • C1

    (power transferred =) IV or 0.75  (0.75  8.0) or 0.75  6.0

  • A1

    4.5 (W)

6c(i) · 2 marks

  • C1

    (length halves and so cross-sectional) area doubles or (new resistance =) 8.0×0.502.0

  • A1

    2.0 ()

6c(ii) · 2 marks

  • B1

    (voltmeter reading =) E×RQRnew+RQ or 9.0×4.02.0+4.0 or (I = ) 1.5 A

  • B1

    6.0 (V)

7a · 2 marks

  • C1

    electrons mentioned or movement of negative charge mentioned

  • A1

    electrons move (from cloth) to rod

7b(i) · 1 mark

  • B1

    (in conductors) electrons are free to move

7b(ii) · 3 marks

  • B1

    like charges repel

  • B1

    negative charges / electrons move away from the rod / to the right

  • B1

    positive charges / protons do not move or left-hand side (of ball) becomes positively charged

7b(iii) · 2 marks

  • B1

    unlike / opposite charges attract

  • B1

    attractive force stronger (than repulsive force on negative charges) / positive charges closer to the rod.

8a · 2 marks

  • C1

    different numbers of neutrons / nucleons

  • A1

    radon-222 / it has two fewer neutrons (in the nucleus) /radon-222 has 136 neutrons and radon-224 has 138 neutrons

8b · 3 marks

  • B1

    24(a)

  • B1

    .....218(Po)

  • B1

    84.....(Po)

8c(i) · 2 marks

  • B1

    count rate at detector J is not zero / is small or some alpha particles are deflected through large angles

  • B1

    detector K has larger / very large detection rate or most / nearly all alpha particles pass straight the gold sheet / are undeflected by the gold sheet

8c(ii) · 2 marks

  • B1

    there is a concentration of charge in the atom

  • B1

    most of the mass of an atom is concentrated into a very small volume or most of the (volume of an) atom is empty space or atom has a dense nucleus

9a · 2 marks

  • B1

    speed is constant

  • B1

    (motion is) in a straight line

9b(i) · 1 mark

  • B1

    to change the direction of the motion / velocity (of Venus) / otherwise it would move in a straight line

9b(ii) · 3 marks

  • B1

    gravitational field / gravitational attraction / gravity

  • B1

    (gravitational field) of Sun

  • B1

    towards centre of circle /Sun / inward

9b(iii) · 2 marks

  • C1

    (speed =) 2πrT or (2×π)×1.1×10115400×(3600)

  • A1

    3.6  104 (m/ s)

9b(iv) · 2 marks

  • B1

    Mercury

  • B1

    (its speed is) greater (than that of Venus)

Questions

  1. 1
    Question 18 marks
    Mark scheme ›
  2. 2
    Question 28 marks
    Mark scheme ›
  3. 3
    Question 37 marks
    Mark scheme ›
  4. 4
    Question 410 marks
    Mark scheme ›
  5. 5
    Question 510 marks
    Mark scheme ›
  6. 6
    Question 610 marks
    Mark scheme ›
  7. 7
    Question 78 marks
    Mark scheme ›
  8. 8
    Question 89 marks
    Mark scheme ›
  9. 9
    Question 910 marks
    Mark scheme ›

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