O Level Mathematics 4024 Paper 12, May/June 2026

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4024/12 · May/June 2026

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1

Write down the value of

a

53

[1]
b

121.

[1]
2

Buses travel from the city centre to the airport.

a

A bus leaves the city centre at 1005. The bus journey from the city centre to the airport takes 1 hour 25 minutes. Work out the time the bus arrives at the airport.

[1]
b

Another bus arrives at the airport at 1620. This bus journey from the city centre to the airport takes 1 hour 35 minutes. Work out the time this bus leaves the city centre.

[1]
3

These are the scores for each of 10 children in a spelling test. 710101575117135

a

Work out the median.

[2]
b

Work out the mean.

[2]
4

Ana has 60 cards. Each card is red or green.

a

The ratio red cards:green cards=2:1. Show that there are 20 green cards.

[1]
b

Each of the 60 cards is a square or a triangle. The ratio square cards:triangle cards=5:1. There are 16 green square cards. Complete the two-way table.

redgreentotal
square16
triangle
total2060
[2]
5

The scale drawing shows the positions of two villages, A and B. The scale is 2 cm to 1 km. Farm C is 4 km from village A and 2.5 km from village B. Farm C is further south than village B.

Figure 1 of 1 for question 5
a

Using a ruler and compasses only, construct the position of farm C.

[3]
b

Measure the bearing of farm C from village A.

[1]
6

Pran invests $2000 in a savings account. The account pays simple interest at a rate of 3.5% per year. Calculate the value of the investment at the end of 4 years.

[3]
7

The diagram shows a trapezium. All the lengths are in centimetres. The area of the trapezium is 100 cm2. Work out the value of x.

[3]
Figure 1 of 1 for question 7
8

Leo has a 5-sided spinner numbered from 1 to 5. Leo spins the spinner 500 times. His results are shown in the table.

number on spinner12345
frequency1059695104100
a

Leo says that the results show that the spinner is fair. Explain why he is correct.

[1]
b

Find the relative frequency of the spinner landing on 5.

[1]
c

Mary spins this spinner 100 times. Find the number of times Mary should expect the spinner to land on 5.

[1]
9

Work out. 123×910+215 Give your answer as a mixed number in its simplest form.

[4]
10

The diagram shows triangle A. Reflect triangle A in the line y=x.

[2]
11
a

Write 400 as a product of its prime factors.

[2]
b

Find the highest common factor (HCF) of 400 and 180.

[2]
12

Rearrange the formula to make m the subject. k=4(m−p)

[2]
13
a

The nth term of a sequence is n+8. Find the first three terms of this sequence.

[1]
b(i)

These are the first four terms of a different sequence. T1=4T2=10T3=16T4=22 Write down the term-to-term rule for this sequence.

[1]
b(ii)

Find an expression for the nth term of the sequence, T.

[2]
c

The nth term of another sequence is Rn=Tnn+8. The kth term of this sequence is 5. Find the value of k.

[3]
14
a

Write 350000 in standard form.

[1]
b

Write 2.7×10−4 as an ordinary number.

[1]
c

Work out. 1.3×1012+4.5×1013 Give your answer in standard form.

[2]
15

The equation of line L is 2y+x=19.

a(i)

Find the gradient of line L.

[2]
a(ii)

Find the y-intercept of line L.

[1]
b

Line M is perpendicular to line L. Line M passes through the point (−1,−5). Show that the equation of line M is y=2x−3.

[2]
c

Find the coordinates of the point of intersection of the lines 2y+x=19 and y=2x−3.

[3]
16

ABCD is a rhombus. M is a point on DC. AM and BD intersect at X.

Figure 1 of 1 for question 16
a

Show that triangle AXB is similar to triangle MXD. Give a geometrical reason for each statement you make.

[3]
b(i)

M is the midpoint of DC. AB=8 cm and BD=15 cm. Calculate DX.

[2]
b(ii)

Complete the statement. area of triangle AXB:area of triangle MXD=…………⋯:1

[1]
17

In a right-angled triangle • the base is x cm • the height is 7 cm shorter than the base • the hypotenuse (longest side) is 2 cm longer than the base.

a

Use this information to form an equation and show that it simplifies to x2−18x+45=0.

[4]
b

Solve by factorising. x2−18x+45=0

[3]
c

Find the area of the triangle.

[2]
18

The masses of 200 apples are summarised in the table.

mass (m grams)80<m⩽100100<m⩽110110<m⩽120120<m⩽140
frequency30508040
Figure 1 of 1 for question 18
a

Find the percentage of apples with a mass greater than 110 g.

[2]
b

On the grid, draw a histogram to represent the information in the table.

[3]
19

The diagram shows a solid hemisphere and a solid cylinder. All the lengths are in centimetres. The radius of the hemisphere is 3x. The radius of the cylinder is 2x. The height of the cylinder is kx. The volume of the hemisphere is equal to the volume of the cylinder. Work out the total surface area of the cylinder. Give your answer in the form aπx2, where a is an integer.

[6]
Figure 1 of 1 for question 19
20

OPQ is a triangle and O is the origin. R is a point on OQ and OQ=3OR. OP⃗=3a and OR⃗=2b. X is the midpoint of PQ. Find as simply as possible in terms of a and/or b

Figure 1 of 1 for question 20
a

PR⃗

[1]
b

RQ⃗

[1]
c

the position vector of X.

[3]
21

Write as a single fraction in its simplest form. 2x+3x−1−5x4−x

[4]
22

The diagram shows a sketch of the graph of y=ax+b. The graph passes through point P(0,5) and point Q(2,13).

Figure 1 of 1 for question 22
a

Find the value of a and the value of b.

[3]
b

Find the equation of the asymptote to the graph.

[1]
23

Find the value of x. 27−43=9x

[3]
24

Expand and simplify. (3+52)(28−1) Give your answer in the form a+b2.

[3]

Mark scheme

4024/12 · May/June 2026

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1a · 1 mark

  • 1 mark

    125

1b · 1 mark

  • 1 mark

    11

2a · 1 mark

  • 1 mark

    1130

2b · 1 mark

  • 1 mark

    1445 or 2.45 pm

3a · 2 marks

  • 2 marks

    8.5 oe

3b · 2 marks

  • 2 marks

    9

4a · 1 mark

  • 1 mark

    60 ÷ (2 + 1) = 20 OR 60 × 2/(2 + 1) = 40 and 60 – 40 = 20

4b · 2 marks

  • 2 marks

    | 34 | 16 | 50 | | 6 | 4 | 10 | | 40 | 20 | 60 |

5a · 3 marks

  • 3 marks

    C positioned correctly south of B with intersecting arcs seen AC = 8 cm, BC = 5 cm

5b · 1 mark

  • 1 mark

    _their_ bearing of C from A

6 · 3 marks

  • 3 marks

    2280

7 · 3 marks

  • 3 marks

    18

8a · 1 mark

  • 1 mark

    Frequencies all close to 100 oe

8b · 1 mark

  • 1 mark

    100/500 oe

8c · 1 mark

  • 1 mark

    20

9 · 4 marks

  • 4 marks

    3 7/10 cao

10 · 2 marks

  • 2 marks

    Correct triangle (1, –1), (1, –3), (2, –3)

11a · 2 marks

  • 2 marks

    2⁴ × 5² or 2 × 2 × 2 × 2 × 5 × 5

11b · 2 marks

  • 2 marks

    20

12 · 2 marks

  • 2 marks

    k/4 + p or (k + 4p)/4 final answer

13a · 1 mark

  • 1 mark

    9, 10, 11

13b(i) · 1 mark

  • 1 mark

    add 6 oe

13b(ii) · 2 marks

  • 2 marks

    6n – 2 oe final answer

13c · 3 marks

  • 3 marks

    42

14a · 1 mark

  • 1 mark

    3.5 × 10⁵ cao

14b · 1 mark

  • 1 mark

    0.00027 cao

14c · 2 marks

  • 2 marks

    4.63 × 10¹³ cao

15a(i) · 2 marks

  • 2 marks

    -1/2 oe

15a(ii) · 1 mark

  • 1 mark

    19/2 oe

15b · 2 marks

  • B1

    Correct justification for gradient = 2 e.g. m × (-1/2) = -1

  • B1

    -5 = 2 × -1 + c oe or (y - -5) = 2(x - -1) leading to y = 2x - 3

15c · 3 marks

  • 3 marks

    (5, 7) cao

16a · 3 marks

  • 3 marks

    ∠AXB = ∠DXM [vertically] opposite angles ∠BAX = ∠DMX alternate angles ∠ABX = ∠XDM alternate angles All angles equal, so triangles similar

16b(i) · 2 marks

  • 2 marks

    5

16b(ii) · 1 mark

  • 1 mark

    4 [: 1] cao

17a · 4 marks

  • M2

    x² + (x – 7)² = (x + 2)² or x² = (x + 2)² – (x – 7)² or (x – 7)² = (x + 2)² – x²

  • M1

    x² – 7x – 7x + 49 and x² + 2x + 2x + 4

  • A1

    Correct simplification to x² – 18x + 45 = 0

17b · 3 marks

  • M2

    (x – 3)(x – 15)

  • B1

    3 15

17c · 2 marks

  • 2 marks

    60

18a · 2 marks

  • 2 marks

    60

18b · 3 marks

  • 3 marks

    Correct histogram

19 · 6 marks

  • 6 marks

    26πx²

20a · 1 mark

  • 1 mark

    2b – 3a final answer

20b · 1 mark

  • 1 mark

    4b final answer

20c · 3 marks

  • 3 marks

    3/2 a + 3b or (3a + 6b)/2 or 3/2 (a + 2b) final answer

21 · 4 marks

  • 4 marks

    (-7x² + 10x + 12)/((x - 1)(4 - x)) or (-7x² + 10x + 12)/(-x² + 5x - 4) final answer

22a · 3 marks

  • 3 marks

    [a =] 3 [b =] 4

22b · 1 mark

  • 1 mark

    y = 4 or y = _their_ b

23 · 3 marks

  • 3 marks

    –2

24 · 3 marks

  • 3 marks

    37 + 7√2 cao

Questions

  1. 1
    Question 12 marks
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  2. 2
    Question 22 marks
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  3. 3
    Question 34 marks
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  4. 4
    Question 43 marks
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  5. 5
    Question 54 marks
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  6. 6
    Question 63 marks
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  7. 7
    Question 73 marks
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  8. 8
    Question 83 marks
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  9. 9
    Question 94 marks
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  10. 10
    Question 102 marks
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  11. 11
    Question 114 marks
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  12. 12
    Question 122 marks
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  13. 13
    Question 137 marks
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  14. 14
    Question 144 marks
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  15. 15
    Question 158 marks
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  16. 16
    Question 166 marks
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  17. 17
    Question 179 marks
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  18. 18
    Question 185 marks
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  19. 19
    Question 196 marks
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  20. 20
    Question 205 marks
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  21. 21
    Question 214 marks
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  22. 22
    Question 224 marks
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  23. 23
    Question 233 marks
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  24. 24
    Question 243 marks
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