O Level Mathematics 4024 Paper 21, May/June 2024

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4024/21 · May/June 2024

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1
a(i)

The cost of a ticket to watch a basketball match is $67.60 . The total money received from ticket sales for one match is $1 183 000. Find the number of tickets sold for this match.

[1]
a(ii)

The cost of one ticket at $67.60 is 4% more than the cost of one ticket last year. Calculate the cost of one ticket last year.

[2]
b

The number of seats in the basketball stadium is 20 545. The number of seats sold for the first match of the season is 19 340. Calculate the percentage of the seats in the stadium that are sold.

[1]
c

A team plays 41 matches. For the 41 matches, the mean number of seats sold per match is 16 440. The total number of seats sold for the first 21 matches is 329 000. Calculate the mean number of seats sold per match for the last 20 matches.

[3]
d(i)

The table shows the salaries of three basketball players.

Basketball playerSalary ($)
Stephen8.27×106
Joe4.29×106
Tristan3.64×107

Find the difference between the salaries of Tristan and Stephen.

[1]
d(ii)

The total Joe earns is his salary plus a bonus of $x. The total he earns is 102.5% of his salary. Calculate the value of x.

[2]
2
Figure 1 of 1 for question 2
a(i)

The temperature at midday was recorded at ten different heights on a mountain. The results are shown in the table.

Height (m)3008256004259001001250145011251350
Temperature (∘C)3.0−0.80.01.2−1.93.5−4.6−6.4−4.0−3.8

Complete the scatter diagram. The first five points have been plotted for you.

[2]
a(ii)

Describe the type of correlation shown in the scatter diagram.

[1]
a(iii)

Draw a line of best fit on the scatter diagram.

[1]
a(iv)

Another reading is taken at a height of 1000 m. Use your line of best fit to estimate the temperature at this height.

[1]
b(i)

The table summarises the times taken by 80 adults to climb the mountain.

Time taken (h hours)5.5<h⩽6.56.5<h⩽7.57.5<h⩽88<h⩽8.58.5<h⩽10.5
Frequency815202314

Calculate an estimate of the mean time.

[3]
b(ii)

A histogram is drawn to show this information. The height of the bar representing 5.5<h⩽6.5 is 8 mm. Calculate the height of the bar representing 8<h⩽8.5.

[1]
3
Figure 1 of 2 for question 3
Figure 2 of 2 for question 3
a

Triangle PQR is isosceles with PQ=QR. The exterior angle of the triangle at R is 142∘. Calculate angle PQR.

[2]
b

The diagonals of trapezium ABCD meet at E. Show that triangle ABE is similar to triangle CDE. Give a reason for each statement you make.

[3]
4
a

Two of the factors of 50 are square numbers. One of these square numbers is 1. Find the other square number that is a factor of 50.

[1]
b(i)

A=2x−1×32y×7 B=2x+3×3y×5 The numbers A and B are written as the product of their prime factors, where x and y are positive integers. Find the highest common factor (HCF) of A and B in terms of x and y.

[2]
b(ii)

Find the lowest common multiple (LCM) of A and B in terms of x and y.

[2]
5
a

Two companies move boxes. Company A charges $0.50 for each box plus a fixed fee of $125. Company B charges only a fixed fee of $350. Find the number of boxes moved when Company A charges the same as Company B.

[2]
b

The maximum mass a van can carry is exactly 770 kg. The van carries boxes each of mass 4 kg, correct to the nearest kilogram. Find the upper bound for the number of boxes this van can carry.

[2]
c

A lorry contains boxes of three sizes S, M and L. The ratio of the number of boxes S:M=2:7. The ratio of the number of boxes S:L=5:4. The lorry contains 72 boxes of size L. Find the total number of boxes in the lorry.

[3]
6
Figure 1 of 3 for question 6
Figure 2 of 3 for question 6
Figure 3 of 3 for question 6
a

Triangle A is mapped onto triangle P by a translation of (1−3). Draw triangle P.

[2]
b

Describe fully the single transformation that maps triangle A onto triangle B.

[3]
c

Transformation M is a reflection in the line y=−1. Transformation R is a rotation 90∘ clockwise about (1,1). RM(B)=Q. Draw triangle Q.

[3]
7
Figure 1 of 1 for question 7
a

A cuboid has dimensions 5 cm by 12 cm by h cm. The volume of the cuboid is 480 cm3. Calculate the value of h.

[2]
b(i)

ABCDE is a pentagon. AE is parallel to BD. AE=21 cm, BD=16 cm and DE=8 cm. Angle DEA=90∘ and angle CBD=65∘. Calculate angle BAE.

[3]
b(ii)

The area of pentagon ABCDE is 200 cm2. Calculate the length of BC.

[5]
8
Figure 1 of 1 for question 8
a(i)

Complete the table for y=2x5.

x012345
y0.20.40.81.63.2
[1]
a(ii)

On the grid, draw the graph of y=2x5 for 0⩽x⩽5.

[3]
a(iii)(a)

2x+3=100 Show that 2x5=52.

[2]
a(iii)(b)

By drawing a suitable line on the grid, solve 2x+3=100.

[2]
b

This is a sketch of the graph y=a+bx−x2. The graph crosses the x-axis at integer values of x. Find the value of a and the value of b.

[3]
9

The diagram shows the positions of three ports A, B and C. The bearing of port B from port A is 107∘. The bearing of port C from port A is 192∘. AB=176 km and AC=132 km.

Figure 1 of 1 for question 9
a

Find the bearing of A from B.

[1]
b

Calculate BC.

[4]
c

Boat B leaves port B at 10.00 am. It sails directly to port A at an average speed of 48 km/h. Boat C leaves port C at 10.15 am. It sails directly to port A and arrives there 7 minutes before boat B. Find the average speed of boat C in km/h.

[5]
10
Figure 1 of 1 for question 10
a

r=4p+3t2 Find the value of p when r=10 and t=−2.

[3]
b

The diagram shows a quadrilateral. Form an equation in w and solve it to find the size of the largest angle in the quadrilateral.

[4]
c

Simplify 2k2−5k−3k2−9.

[3]
d

Solve 2x+3+5x−2=1. Show all your working and give your answers correct to 2 decimal places.

[6]
11
a(i)

On any day in January, the probability the temperature at a weather station is above 14∘C is 0.35 . There are 31 days in January. Find the number of days in January when you would expect the temperature to be above 14∘C.

[1]
a(ii)(a)

The temperature on two consecutive days in January is recorded. Complete the tree diagram.

[2]
a(ii)(b)

Find the probability that the temperature is above 14∘C on both days.

[1]
a(ii)(c)

Find the probability that the temperature is above 14∘C on only one of the two days.

[2]
b

In a group of 14 children: • 8 wear red T-shirts • 1 wears a green T-shirt • 5 wear blue T-shirts. Two children are chosen from the group at random. Find the probability that they wear different coloured T-shirts.

[3]

Mark scheme

4024/21 · May/June 2024

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1a(i) · 1 mark

  • 1 mark

    17 500

1a(ii) · 2 marks

  • M1

    for (100+4100)x=67.60 soi

  • A1

    65[.00] nfww

1b · 1 mark

  • 1 mark

    94.1 or 94.13…

1c · 3 marks

  • M1

    for 16440×41 oe

  • M1

    for their 674040−32900020 oe

  • A1

    17 252

1d(i) · 1 mark

  • 1 mark

    28 130 000 or 2.813 × 10^7 oe

1d(ii) · 2 marks

  • M1

    for 102.5100×4.29×106−4.29×106 oe or 4.29×106+x4.29×106×100=102.5 oe

  • A1

    107 250 or 1.0725 × 10^5 oe

2a(i) · 2 marks

  • B1

    for 3 or 4 correct plots

  • B2

    Complete scatter diagram

2a(ii) · 1 mark

  • 1 mark

    Negative

2a(iii) · 1 mark

  • 1 mark

    Ruled line of best fit

2a(iv) · 1 mark

  • 1 mark

    Reading _their_ ruled line of best fit at 1000 m

2b(i) · 3 marks

  • B1

    for correct midpoints soi

  • M1

    for 6×8+7×15+7.75×20+8.25×23+9.5×1480

  • A1

    7.88 or 7.884…

2b(ii) · 1 mark

  • 1 mark

    46

3a · 2 marks

  • B1

    for angle QRP=38 or angle QPR=38 or M1 for 180−2×their 38

  • B1

    104

3b · 3 marks

  • B2

    for two correct pairs of angles with correct reasons or B1 for one correct pair of angles with correct reason or two correct pairs of angles with no/incorrect reasons

  • B1

    complete proof with conclusion Hence similar

4a · 1 mark

  • 1 mark

    25

4b(i) · 2 marks

  • B1

    for correct answer seen and spoilt or answer 2x−1×k oe or m×3y

  • B1

    2^{x-1} × 3^y oe final answer

4b(ii) · 2 marks

  • B1

    for correct answer seen and spoilt or answer 2x+3×3a×5×7 oe or 2b×32y×5×7 oe or 2x+3×32y×5 oe or 2x+3×32y×7 oe

  • B1

    2^{x+3} × 3^{2y} × 5 × 7 oe final answer

5a · 2 marks

  • M1

    for 0.5x + 125 = 350 or better

  • A1

    450

5b · 2 marks

  • B1

    for 3.5 used

  • B1

    220 nfww

5c · 3 marks

  • B1

    for 10k : 35k : 8k or [S =] 90

  • M1

    for [M=]their 902×7 oe or 72their 8k(their 10k+their 35k+their 8k) oe

  • A1

    477

6a · 2 marks

  • B1

    for translation of (1k) or (k−3)

  • B1

    Triangle with vertices (5, –2) (7, –2) and (5, –6)

6b · 3 marks

  • B1

    Enlargement

  • B1

    [Scale factor] −12 oe

  • B1

    [Centre] (0, 1)

6c · 3 marks

  • B2

    for triangle with vertices (–2, –5) (–2, –3) and (–3, –3) seen or B1 for triangle Q correct size and orientation but wrong position

  • B1

    Triangle with vertices (–5, 4) (–3, 4) and (–3, 5)

7a · 2 marks

  • M1

    for 5 × 12 × h = 480 oe

  • A1

    8

7b(i) · 3 marks

  • M2

    for tan⁡[]=821−16 oe or B1 for horizontal distance 21 – 16 soi

  • A1

    58[.0] or 57.99… nfww

7b(ii) · 5 marks

  • M2

    for 200−12(16+21)×8 oe or M1 for 12(16+21)×8 oe

  • M2

    for 2×their 5216×sin⁡65 oe or M1 for 12×BC×16×sin⁡65 oe or for [height =] 2×their 5216

  • A1

    7.17 or 7.171 to 7.172

8a(i) · 1 mark

  • 1 mark

    6.4 oe cao

8a(ii) · 3 marks

  • B2

    B2FT for 5 or 6 points correctly plotted or B1FT for 3 or 4 points correctly plotted

  • B1

    Correct smooth curve

8a(iii)(a) · 2 marks

  • M1

    2x+3=2x×23 soi

  • A1

    2x5=1008×5 leading to 2x5=52

8a(iii)(b) · 2 marks

  • M1

    y = 2.5 drawn

  • A1

    3.5 to 3.8

8b · 3 marks

  • B1

    for a = 7

  • B1

    for (–1, 0) and (7, 0) soi or (–7, 0) and (1, 0) soi or (c, 0) and (d, 0) where cd = – their a soi where c and d are integer values

  • B1

    b = 6

9a · 1 mark

  • 1 mark

    287

9b · 4 marks

  • B1

    for angle CAB = 85 soi

  • M2

    B2 for 44350.[…] or M2 for 1762+1322−2×176×132cos⁡(their 85) oe or M1 for 1762+1322−2×176×132cos⁡(their 85) oe

  • A1

    211 or 210.5 to 210.6

9c · 5 marks

  • M2

    for 17648×60 oe soi or M1 for 17648 oe OR M2 for 17648 and 760 or 1560 and 760 oe soi or M1 for 17648 oe

  • M2

    AND M2 for 132(their 220)−15−7[×60] oe or M1 for 1.33pm oe or (their 220) – 15 – 7 oe or 132their 220+k×60 oe OR M2 for 132their (17648−1560−760) oe or M1 for their (17648−1560−760) oe or 132their (17648)+k oe

  • A1

    40

10a · 3 marks

  • M2

    for 10×2−3×−2=4p oe or p=2r−3t4 oe or M1 for 10=4p+3×−22 oe or 2r=4p+3t or r−3t2=4p2 or better

  • A1

    6.5 oe

10b · 4 marks

  • M1

    w + 2w + w + 10 + w – 15 = 360 oe

  • B2

    for [w =] 73 OR M1 for correctly rearranging their initial equation to kw = c M1 for largest angle = 2 × their 73

  • B1

    146

10c · 3 marks

  • B1

    for (2k + 1)(k – 3) seen

  • B1

    for (k + 3)(k – 3) seen

  • B1

    2k+1k+3 final answer

10d · 6 marks

  • B4

    x^2 – 6x – 17 [= 0] or equivalent 3-term quadratic all terms on one side (M2 for 2(x – 2) + 5(x + 3) = (x + 3)(x – 2) or 2(x−2)(x+3)(x−2)+5(x+3)(x+3)(x−2) or M1 for 2(x – 2) + 5(x + 3) seen, M1 for x2+3x−2x−6 soi)

  • B1

    --6 ± √((-6)^2 – 4 × 1 × -17) / (2 × 1) oe (FT their quadratic, oe e.g. 62±(62)2+17)

  • B1

    8.10, –2.10

11a(i) · 1 mark

  • 1 mark

    10 or 11

11a(ii)(a) · 2 marks

  • M1

    for 2 or 3 probabilities completed correctly

  • A1

    Correct tree diagram 0.65, 0.65, 0.35, 0.65 oe

11a(ii)(b) · 1 mark

  • 1 mark

    0.1225 oe e.g. 49/400

11a(ii)(c) · 2 marks

  • M1

    for [2 ×] 0.35 × 0.65

  • A1

    0.455 oe e.g. 91/200

11b · 3 marks

  • M2

    for 1−(814×713+[114×013]+514×413) oe or 814×613+114×1313+514×913 oe or M1 for 814×713+[114×013]+514×413 oe or 3 correct products

  • A1

    106/182 oe e.g. 53/91

Questions

  1. 1
    Question 110 marks
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  2. 2
    Question 29 marks
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  3. 3
    Question 35 marks
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  4. 4
    Question 45 marks
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  5. 5
    Question 57 marks
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  6. 6
    Question 68 marks
    Mark scheme ›
  7. 7
    Question 710 marks
    Mark scheme ›
  8. 8
    Question 811 marks
    Mark scheme ›
  9. 9
    Question 910 marks
    Mark scheme ›
  10. 10
    Question 1016 marks
    Mark scheme ›
  11. 11
    Question 119 marks
    Mark scheme ›

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