IGCSE Mathematics 0580 Paper 42, May/June 2023

Question paper and mark scheme130 marks10 questions

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Question paper

0580/42 · May/June 2023

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1
Figure 1 of 4 for question 1
Figure 2 of 4 for question 1
Figure 3 of 4 for question 1
Figure 4 of 4 for question 1
a

The diagram shows an isosceles triangle with the base extended. Find the value of x.

[3]
b

The diagram shows three lines meeting at a point. The ratio a:b:c=3:4:5. Find the value of c.

[3]
c

A regular pentagon has an exterior angle, d. A regular hexagon has an interior angle, h. Find the fraction dh. Give your answer in its simplest form.

[4]
d

Show that PQRS is a cyclic quadrilateral.

[5]
e

The diagram shows a circle of radius 9 cm, centre O. The minor sector AOB, with sector angle 50∘, is removed from the circle. Calculate the length of the major arc AB.

[3]
2
a

Anil changes $830 into euros when the exchange rate is 1euro=$1.16. He spends 500 euros. He then changes the remaining money back into dollars at the same exchange rate. Work out how much, in dollars, Anil receives.

[3]
b(i)

In 2021, Anil earns $37 000. He spends $12 400 on bills in 2021. Calculate the percentage of his earnings he spends on bills.

[2]
b(ii)

His earnings of $37 000 increase by 3.2 in 2022. Calculate his earnings in 2022.

[2]
c(i)

Anil invests $3500 in an account that pays a rate of 2.4 per year compound interest. Calculate the total interest earned at the end of 5 years.

[3]
c(ii)

Find the number of complete years before Anil has at least $5000 in this account.

[3]
3

The diagram shows a right-angled triangle ABC.

a(i)

The area of the triangle is 60 cm2. Show that 2x2+11x−105=0.

[3]
a(ii)

Solve by factorisation. 2x2+11x−105=0

[3]
a(iii)

Calculate angle ACB.

[3]
b(i)

Triangle ABC is similar to triangle DEF. Triangle DEF has an area of 93.75 cm2. Find the size of the smallest angle of triangle DEF.

[1]
b(ii)

Find the length of the shortest side of triangle DEF.

[3]
4

The table shows information about the heights of 80 children.

Height (h metres)1.2<h⩽1.41.4<h⩽1.51.5<h⩽1.651.65<h⩽1.81.8<h⩽1.9
Frequency21324329
a(i)

Write down the interval containing the median.

[1]
a(ii)

Calculate an estimate of the mean height.

[4]
b(i)

One of these children is chosen at random. Calculate the probability that they have a height of 1.4 m or less.

[1]
b(ii)

Two of these children are chosen at random. Calculate the probability that both children are taller than 1.5 m but only one of them is taller than 1.8 m.

[3]
c(i)

Complete the cumulative frequency table for the heights.

Height (h metres)h⩽1.4h⩽1.5h⩽1.65h⩽1.8h⩽1.9
Cumulative frequency2
[2]
c(ii)

On the grid, draw the cumulative frequency diagram.

[3]
d(i)

Use your diagram to find an estimate of the interquartile range

[2]
d(ii)

the 60th percentile.

[2]
5
Figure 1 of 2 for question 5
Figure 2 of 2 for question 5
a(i)

A cone has base diameter 8 cm and perpendicular height 15 cm. Calculate the volume of the cone. [The volume, V, of a cone with radius r and height h is V=13πr2h.]

[2]
a(ii)

A label completely covers the curved surface area of the cone. Calculate the area of the label as a percentage of the total surface area of the cone. [The curved surface area, A, of a cone with radius r and slant height l is A=πrl.]

[5]
b(i)

An empty cylindrical container has radius 0.45 m. 300 litres of water is poured into the container at a rate of 375 ml per second. Find the time taken, in minutes and seconds, for all the water to be poured into the container.

[3]
b(ii)

Calculate the height of the water in the container.

[3]
6
a(i)

A sequence has nth term n2n+3. Find the first three terms of this sequence. Give your answers as fractions.

[2]
a(ii)

The kth term of this sequence is 1225. Find the value of k.

[2]
b(i)

Find the nth term of each sequence. 6, 13, 32, 69, 130, …

[2]
b(ii)

100, 50, 25, 12.5, 6.25, …

[2]
7

The diagram shows the straight roads between town A, town B and town C. AC=60 km, CB=87 km and B is due east of A. The bearing of C from A is 038∘.

Figure 1 of 1 for question 7
a

Show that angle ACB=95.1∘, correct to 1 decimal place.

[5]
b

Without stopping, a car travels from town A to town C then to town B, before returning directly to town A. The total time taken for the journey is 3 hours 20 minutes. Calculate the average speed of the car for this journey. Give your answer in kilometres per hour.

[6]
8
a(i)

Show that the equation y=(x−4)(x+1)(x−2) can be written as y=x3−5x2+2x+8.

[2]
a(ii)

On the diagram, sketch the graph of y=x3−5x2+2x+8, indicating the values where the graph crosses the axes.

[4]
b

The graph of y=x3−5x2+2x+8 has two tangents with a gradient of 10. Find the equations of these two tangents. You must show all your working and give your answers in the form y=mx+c.

[7]
9
a(i)

Simplify. (3x2y4)3

[2]
a(ii)

(16x16y8)−32

[3]
b(i)

Factorise. x2−9

[1]
b(ii)

Simplify. x2−92xy−6y+5x−15

[3]
c

Solve the simultaneous equations. You must show all your working and give your answers correct to 2 decimal places. 2x+y=7 y=5x2+2x−13

[6]
10
Figure 1 of 2 for question 10
Figure 2 of 2 for question 10
a

ABCDEFGH is a cuboid with a square base of side x cm. CG=20 cm and AG=28 cm. Calculate the value of x.

[4]
b

The diagram shows a different cuboid JKLMNPQR. MR=30 cm correct to the nearest centimetre. KR=37 cm correct to the nearest centimetre. Calculate the lower bound of the angle between KR and the base JKLM of the cuboid.

[4]

Mark scheme

0580/42 · May/June 2023

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1a · 3 marks

  • 3 marks

    111

1b · 3 marks

  • 3 marks

    150

1c · 4 marks

  • 4 marks

    35 cao nfww

1d · 5 marks

  • M1

    x+2x−5+x+20+3x−40=360

  • M1

    7x=360+5−20+40 or better

  • B1

    x=55

  • B1

    55 and 125 or 105 and 75

  • A1

    Opposite angles sum to 180 oe [so PQRS is a cyclic quadrilateral]

1e · 3 marks

  • 3 marks

    48.7 or 48.69 to 48.70…

2a · 3 marks

  • 3 marks

    249.98 to 250[.0…]

2b(i) · 2 marks

  • 2 marks

    33.5 or 33.51…

2b(ii) · 2 marks

  • 2 marks

    38 184 cao

2c(i) · 3 marks

  • 3 marks

    441 or 440.6 or 440.64 to 440.65

2c(ii) · 3 marks

  • 3 marks

    16

3a(i) · 3 marks

  • M1

    (x+3)(2x+5)2=60

  • B1

    2x2+6x+5x+15 seen

  • A1

    2x2+11x−105=0

3a(ii) · 3 marks

  • M2

    (2x+21)(x−5)[=0]

  • B1

    –10.5 and 5

3a(iii) · 3 marks

  • 3 marks

    61.9 or 61.92 to 61.93

3b(i) · 1 mark

  • 1 mark

    28.1 or 28.07 to 28.08

3b(ii) · 3 marks

  • 3 marks

    10

4a(i) · 1 mark

  • 1 mark

    1.65<h≤1.8

4a(ii) · 4 marks

  • 4 marks

    1.63875

4b(i) · 1 mark

  • 1 mark

    140 oe

4b(ii) · 3 marks

  • 3 marks

    63395 oe

4c(i) · 2 marks

  • 2 marks

    15, 39, 71, 80

4c(ii) · 3 marks

  • 3 marks

    Correct curve

4d(i) · 2 marks

  • 2 marks

    Strict FT their UQ – their LQ

4d(ii) · 2 marks

  • 2 marks

    Strict FT their reading at 48

5a(i) · 2 marks

  • 2 marks

    251 or 251.3 to 251.4

5a(ii) · 5 marks

  • 5 marks

    79.5 or 79.51…

5b(i) · 3 marks

  • 3 marks

    13 min 20 sec

5b(ii) · 3 marks

  • 3 marks

    0.472 or 0.4715 to 0.4716…

6a(i) · 2 marks

  • 2 marks

    15, 27, 39 final answer

6a(ii) · 2 marks

  • 2 marks

    36

6b(i) · 2 marks

  • 2 marks

    n3+5 oe final answer

6b(ii) · 2 marks

  • 2 marks

    100×21−n oe final answer

7a · 5 marks

  • B1

    Angle CAB=52

  • M3

    180−52−sin⁡−1(60sin⁡their 5287)

  • A1

    95.08…

7b · 6 marks

  • 6 marks

    77.1 or 77.08 to 77.11

8a(i) · 2 marks

  • M1

    Correct expansion of a pair of brackets x2−4x+[1]x−4 or x2−4x−2x+8 or x2+[1]x−2x−2

  • A1

    x3−4x2+x2−4x−2x2+8x−2x+8 leading to and stating [y=]x3−5x2+2x+8

8a(ii) · 4 marks

  • 4 marks

    Correct labelled sketch positive cubic Crossing x-axis at –1, 2 and 4 only Crossing y – axis at 8 only

8b · 7 marks

  • M3

    3x2−10x−8[=0]

  • B1

    x=4 and x=−23

  • B1

    (4,0) and (−23,11227) oe

  • B2

    [y=]10x−40 and [y=]10x+29227

9a(i) · 2 marks

  • 2 marks

    27x6y12 final answer

9a(ii) · 3 marks

  • 3 marks

    x24y1264 final answer

9b(i) · 1 mark

  • 1 mark

    (x+3)(x−3) final answer

9b(ii) · 3 marks

  • 3 marks

    x+32y+5 final answer

9c · 6 marks

  • M2

    5x2+4x−20[=0] oe or 5y2−78y+221[=0] oe

  • M2

    −4±(4)2−4(5)(−20)2(5) oe or −410±4+(410)2 oe

  • B2

    x=1.64 y=3.72 and x=−2.44 y=11.88

10a · 4 marks

  • 4 marks

    13.9 or 13.85 to 13.86

10b · 4 marks

  • 4 marks

    51.9 or 51.87 to 51.88

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