A Level Physics 9702 Paper 42, May/June 2026

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Question paper

9702/42 · May/June 2026

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1
Figure 1 of 3 for question 1
Figure 2 of 3 for question 1
Figure 3 of 3 for question 1
a

With reference to velocity and acceleration, describe uniform circular motion.

[2]
b(i)

An aircraft is travelling in a horizontal circle of radius 7200 m at a speed of 180 ms−1, as shown in the view from above in Figure 1.1. In order to move in a circle, the aircraft has to tilt its wings so that the lift force from the wings is not vertical, as shown in the view from behind in Figure 1.2. With reference to the forces acting on the aircraft, explain why the circular motion of the aircraft requires the lift force to be in the direction shown rather than vertically upwards.

[2]
b(ii)

On Figure 1.2, draw an arrow from the aircraft to represent the direction of the resultant force on the aircraft.

[1]
b(iii)

Calculate the centripetal acceleration of the aircraft. acceleration=................................................ ms−2

[2]
b(iv)

Determine the angle θ at which the aircraft is tilted. Explain your reasoning. θ=....................................................... ∘

[3]
2
Figure 1 of 1 for question 2
a(i)

Define gravitational field at a point.

[1]
a(ii)

Figure 2.1 shows a horizontal section through a small piece of ground at the Earth's surface and the air at a small distance above it. On Figure 2.1, draw four field lines to represent the gravitational field of the Earth in the air above the ground.

[2]
b(i)

The Earth may be considered to be an isolated uniform sphere of radius 6.37×106 m. By considering the gravitational field strength at the Earth's surface, calculate a value for the mass of the Earth. Give your answer to three significant figures. mass=.................................................... kg

[2]
b(ii)

Determine, to three significant figures, the gravitational potential at the Earth's surface. Give a unit with your answer. gravitational potential=.................................. unit ...............

[2]
b(iii)

A satellite of mass 96.0 kg is in circular orbit at a height of 1.93×106 m above the Earth's surface. Determine the gravitational potential energy of the satellite. gravitational potential energy=...................................................... J

[2]
3
a

Define specific heat capacity.

[2]
b(i)

A sample of an ideal gas contains 6.00×1023 molecules, each of mass 6.64×10−27 kg. The gas is at a pressure of 1.01×105 Pa. It has an initial volume of 0.0243 m3, an initial internal energy of 3676 J and an initial temperature of 296 K. The gas is now cooled at constant pressure so that its volume becomes 80% of the initial volume. Show that the magnitude of the work done on the gas is 491 J.

[2]
b(ii)

Explain whether the work done on the gas is positive or negative.

[1]
b(iii)

Explain why the increase in internal energy of the gas is −735 J.

[2]
b(iv)

Determine the thermal energy Q transferred to the gas. Q=...................................................... J

[2]
b(v)

Calculate a value for the specific heat capacity c of the gas for this change. c=......................................... Jkg−1K−1

[2]
c

The gas in 3(b) is now heated at constant volume so that its temperature returns to 296 K. Use the first law of thermodynamics to explain, without calculation, whether the specific heat capacity for this change is less than, the same as, or greater than the answer in 3(b)(v).

[3]
4
Figure 1 of 1 for question 4
a

State the two assumptions of the kinetic theory of gases that relate to collisions of particles with each other and with the walls of the container of the gas. 1 ................................................................................................................................................ ................................................................................................................................................... 2 ................................................................................................................................................ ...................................................................................................................................................

[2]
b(i)

A single particle of an ideal gas has mass m. The particle is moving at speed u in a cubic box of side length L, as shown in Figure 4.1. The particle is moving in a direction that is perpendicular to the two shaded faces, continually rebounding from one face and then the other. Determine an expression, in terms of some or all of m, u and L, for: the magnitude of the change in momentum of the particle during each collision with a shaded face change in momentum=.........................................................

[1]
b(ii)

the time taken between consecutive collisions of the particle with one of the shaded faces time=.........................................................

[1]
b(iii)

the mean force exerted on the particle by one of the shaded faces mean force=.........................................................

[1]
b(iv)

the mean pressure p exerted over the area of each of the shaded faces by the particle. Explain your reasoning. p=.........................................................

[2]
c

An ideal gas consists of N particles moving in many different directions with a mean-square speed of ⟨c2⟩. Explain how the equation in 4(b)(iv) is modified to arrive at the more general equation pV=13Nm⟨c2⟩ where V is the volume of the gas.

[3]
5

A block of mass 27 g is suspended from a spring so that it rests in equilibrium, as shown in Figure 5.1. The block is displaced downwards through a small distance. The block is released and then oscillates vertically with simple harmonic motion. The oscillations have a period of 1.7 s and an energy of 13 μJ.

Figure 1 of 2 for question 5
Figure 2 of 2 for question 5
a(i)

Show that the angular frequency of the oscillations is 3.7 rad s−1.

[1]
a(ii)

State what is meant by the amplitude of the oscillations.

[1]
a(iii)

Calculate the amplitude of the oscillations. amplitude=..................................................... m

[3]
b

On Figure 5.2, sketch the variation of the kinetic energy EK of the block with displacement x from the equilibrium position for one complete oscillation of the block. Add a suitable scale to the x-axis.

[3]
6
Figure 1 of 2 for question 6
Figure 2 of 2 for question 6
a

Define electric potential at a point.

[2]
b(i)

An isolated conducting sphere of radius R is in a vacuum. The sphere has a charge of +Q distributed around its surface, as illustrated in Figure 6.1. State an expression, in terms of R and Q, for the magnitude V0 of the electric potential at the surface of the sphere. Identify any other symbols that you use. V0=.........................................................

[1]
b(ii)

On Figure 6.2, sketch the variation of the electric potential V at distance x from the centre of the sphere between x=R and x=3R.

[3]
c(i)

The dome of an electrostatic generator, called a Van de Graaff generator, may be considered to be a conducting sphere of radius 11.9 cm. The dome is charged so that the electric potential at its surface is −4.80×104 V. Calculate the charge on the surface of the dome. charge=..................................................... C

[2]
c(ii)

Explain why the dome acts as a capacitor.

[1]
c(iii)

Calculate the capacitance of the dome. Give a unit with your answer. capacitance=.................................. unit ...............

[2]
c(iv)

Determine the energy stored by the dome. energy=...................................................... J

[2]
7

A Hall probe consists of a slice of conducting material, as shown in Figure 7.1. Current I enters the slice at face WXYZ and leaves it at face PQRS. The slice is in a uniform magnetic field of flux density B. This magnetic field is perpendicular to faces WXQP and ZYRS. A Hall voltage VH is induced between two of the faces of the slice.

Figure 1 of 2 for question 7
Figure 2 of 2 for question 7
a(i)

Using the letters P, Q, R, S, W, X, Y and Z, identify the faces of the slice between which the Hall voltage is induced. .............................................................. and ..............................................................

[1]
a(ii)

The magnitude of the Hall voltage in Figure 7.1 is given by the equation VH=BInqt. State the meanings of the symbols n, q and t in this equation. n ........................................................................................................................................ q ......................................................................................................................................... t .........................................................................................................................................

[3]
b(i)

Explain the origin of the Hall voltage.

[3]
b(ii)

Identify which of the faces in 7(a)(i) is at the higher potential. Explain your reasoning.

[1]
8

A sinusoidal alternating input voltage VIN is supplied to a circuit that produces a rectified and smoothed output voltage VOUT. The variations with time t of VIN and VOUT are shown in Figure 8.1 and Figure 8.2 respectively.

Figure 1 of 4 for question 8
Figure 2 of 4 for question 8
Figure 3 of 4 for question 8
Figure 4 of 4 for question 8
a(i)

State the name of the component in the circuit that produces the rectification.

[1]
a(ii)

State the name of the component in the circuit that produces the smoothing.

[1]
b(i)

Determine the peak value of VIN. peak value of VIN=...................................................... V

[1]
b(ii)

Determine the period of VIN. period of VIN=...................................................... s

[1]
c

Apart from the peak value and period of VIN, determine three other conclusions that can be drawn from Figure 8.1 and Figure 8.2 about the input and output voltages and about the circuit. The conclusions may be qualitative or quantitative. Use the space for any working. 1 ................................................................................................................................................ ................................................................................................................................................... 2 ................................................................................................................................................ ................................................................................................................................................... 3 ................................................................................................................................................ ...................................................................................................................................................

[3]
9
a

State what is meant by the de Broglie wavelength.

[1]
b

Complete Table 9.1 to identify experimental evidence for the wave nature and the particulate nature of matter and of electromagnetic radiation. Table 9.1

[4]
c(i)

An electron in a vacuum is accelerated from rest by a potential difference (p.d.) of 3.5 kV. For the accelerated electron, calculate the speed speed=................................................ ms−1

[3]
c(ii)

the de Broglie wavelength. wavelength=..................................................... m

[2]
10
a

Define the binding energy of a nucleus.

[2]
b(i)

A star emits radiation that is produced in a series of nuclear reactions that form helium from hydrogen. The reactions may be summarised by the overall equation 4 11H→ 24He+2 10X where X is a particle that has no binding energy. All of the radiation emitted by the star is produced by this series of nuclear reactions. The mass defect of the 24He nuclide is 0.030377 u, where u is the unified atomic mass unit. State the name of particle X.

[1]
b(ii)

Show that the binding energy of the 24He nuclide is 4.54×10−12 J.

[2]
c(i)

The star in 10(b) has a luminosity of 7.98×1027 W. An observer on the Earth detects radiation from this star at a distance away of 8.15×1016 m. Calculate the radiant flux intensity F detected by the observer. F=.............................................. Wm−2

[2]
c(ii)

The mass of hydrogen in the star decreases continuously as a result of the series of nuclear reactions. Determine the rate of decrease of mass of hydrogen in the star. rate of decrease of mass=............................................... kgs−1

[4]

Mark scheme

9702/42 · May/June 2026

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1a · 2 marks

  • B1

    acceleration is (always) perpendicular to velocity

  • B1

    velocity and acceleration have constant magnitude or velocity and acceleration change direction

1b(i) · 2 marks

  • B1

    only other force is weight, which is vertical or weight has no horizontal component or vertical component of lift is equal (and opposite) to the weight

  • B1

    lift must have a horizontal component to cause centripetal acceleration

1b(ii) · 1 mark

  • B1

    arrow drawn from aircraft, horizontally to the left

1b(iii) · 2 marks

  • C1

    a = v^2 / r

  • A1

    a = 180^2 / 7200 = 4.5 m s–2

1b(iv) · 3 marks

  • B1

    vertical component of lift balances the weight or horizontal component of lift causes the centripetal acceleration or mg = L cos θ and ma = L sin θ

  • C1

    tan θ = a / g

  • A1

    tan θ = 4.5 / 9.81 θ = 25°

2a(i) · 1 mark

  • B1

    force per unit mass (at the point)

2a(ii) · 2 marks

  • B1

    four straight parallel lines perpendicular to ground approximately evenly spaced

  • B1

    lines pointing towards the ground

2b(i) · 2 marks

  • C1

    g = GM / R^2

  • A1

    mass = 9.81 × (6.37 × 10^6)^2 / (6.67 × 10^–11) = 5.97 × 10^24 kg

2b(ii) · 2 marks

  • C1

    ϕ = –(6.67 × 10^–11 × 5.97 × 10^24) / (6.37 × 10^6) or ϕ = –9.81 × 6.37 × 10^6

  • A1

    ϕ = –6.25 × 10^7 J kg^–1

2b(iii) · 2 marks

  • C1

    GPE = potential × mass = (–) GMm / R = –(6.67 × 10^–11 × 5.97 × 10^24 × 96.0) / ((6.37 + 1.93) × 10^6)

  • A1

    = –4.61 × 10^9 J

3a · 2 marks

  • B1

    thermal energy per unit mass (to change temperature)

  • B1

    thermal energy per unit change in temperature

3b(i) · 2 marks

  • C1

    W = pΔV

  • A1

    = 1.01 × 10^5 × (1.00 – 0.80) × 0.0243 = 491 J

3b(ii) · 1 mark

  • B1

    volume decreases so (work done on the gas is) positive

3b(iii) · 2 marks

  • B1

    internal energy is proportional to (thermodynamic) temperature or (thermodynamic) temperature is proportional to volume or internal energy is proportional to volume

  • B1

    internal energy decreases to 80% of initial value, so increase is (negative and) equal to 0.20 × 3676 (i.e. –735 J) or ΔU is given by (3/2)NkΔT or U is given by (3/2)NkT ΔU = (3/2) × 6.00 × 10^23 × 1.38 × 10^–23 × (–0.20 × 296) = –735 J

3b(iv) · 2 marks

  • C1

    –735 = Q + 491

  • A1

    Q = –1226 J

3b(v) · 2 marks

  • C1

    ΔT = 0.20 × 296 (= 59 K)

  • A1

    c = 1226 / (6.00 × 10^23 × 6.64 × 10^–27 × 0.20 × 296) = 5200 J kg^–1 K^–1

3c · 3 marks

  • B1

    (same temperature change so) same change in internal energy

  • B1

    (constant volume so) no work done (on/by gas)

  • B1

    less thermal energy supply needed (for same temperature change) so specific heat capacity is less

4a · 2 marks

  • B1

    collisions are instantaneous

  • B1

    collisions are elastic

4b(i) · 1 mark

  • A1

    change in momentum = 2mu

4b(ii) · 1 mark

  • A1

    time = 2L / u

4b(iii) · 1 mark

  • A1

    mean force = Δp / t = 2mu / (2L / u) = mu^2 / L

4b(iv) · 2 marks

  • B1

    clear application of Newton’s third law (e.g. force exerted on face by particle equal (and opposite) to force exerted on particle by face)

  • A1

    p = F / A = (mu^2 / L) / L^2 = mu^2 / L^3

4c · 3 marks

  • B1

    volume of cube is L^3 (which is V, so equation becomes pV = mu^2)

  • B1

    particles moving in 3 dimensions, so u^2 becomes ⅓<c^2>

  • B1

    N particles (rather than 1 particle) so (pV) multiplied by N or multiply by N to get pV for all particles (rather than just 1 particle)

5a(i) · 1 mark

  • A1

    ω = 2π / 1.7 = 3.7 rad s^–1

5a(ii) · 1 mark

  • B1

    (magnitude of) maximum displacement (of block) from equilibrium position

5a(iii) · 3 marks

  • C1

    E = ½ mω^2 x0^2

  • C1

    13 × 10^–6 = ½ × 27 × 10^–3 × 3.7^2 × x0^2

  • A1

    amplitude = 8.4 × 10^–3 m

5b · 3 marks

  • B1

    dome-shaped curve with correct curvature and a single peak with maximum EK shown at 13 μJ

  • B1

    curve symmetrical about EK-axis, with single peak at x = 0, end points at EK = 0 and x-axis intercepts at the same positions in the positive and negative directions

  • B1

    x-axis scale marked with a consistent scale that corresponds with the end points of the line being at ± values of x equal to the answer in 5(a)(iii)

6a · 2 marks

  • B1

    work done per unit charge

  • B1

    work done (on charge) in moving positive charge from infinity (to the point)

6b(i) · 1 mark

  • B1

    V0 = Q / 4πε0R, where ε0 is the permittivity of free space

6b(ii) · 3 marks

  • B1

    curve from x = R to x = 3R with decreasing magnitudes of V and gradient, starting at (R, V0)

  • B1

    line passing through (2R, ½V0) and (3R, ⅓V0)

  • B1

    line entirely within the positive V region

6c(i) · 2 marks

  • C1

    Q = (–)4.80 × 10^4 × 4π × 8.85 × 10^–12 × 0.119

  • A1

    = –6.35 × 10^–7 C

6c(ii) · 1 mark

  • B1

    stores energy / charge

6c(iii) · 2 marks

  • C1

    C = Q / V

  • A1

    C = (6.35 × 10^–7) / (4.80 × 10^4) = 1.32 × 10^–11 F

6c(iv) · 2 marks

  • C1

    E = ½QV or E = ½CV^2 or E = Q^2 / 2C

  • A1

    = ½ × 6.35 × 10^–7 × 4.80 × 10^4 = 0.0152 J

7a(i) · 1 mark

  • B1

    PSZW and QRYX

7a(ii) · 3 marks

  • B1

    n: number density of charge carriers

  • B1

    q: charge on one / each charge carrier

  • B1

    t: thickness or distance PS / QR / XY / WZ

7b(i) · 3 marks

  • 1 mark

    charge carriers experience a force due to (current in) magnetic field

  • 1 mark

    force on charge carriers is perpendicular to I and B

  • 1 mark

    charge carriers deflect towards one face (and away from the opposite face)

  • 0 marks

    charge separation between faces causes a p.d. between the faces

  • 0 marks

    steady state when force due to magnetic field is equal and opposite to force due to resulting electric field

7b(ii) · 1 mark

  • B1

    the electrons deflect towards face QRYX so PSZW (is higher) or deflection is towards QRYX and the charge carriers are negative so PSZW (is higher)

8a(i) · 1 mark

  • B1

    diode

8a(ii) · 1 mark

  • B1

    capacitor

8b(i) · 1 mark

  • A1

    peak VIN = 3.6 V

8b(ii) · 1 mark

  • A1

    period = 0.040 s

8c · 3 marks

  • 1 mark

    the rectification is half-wave

  • 1 mark

    frequency (of input) = 25 Hz or angular frequency (of input) = 160 rad s–1

  • 1 mark

    r.m.s. input voltage = 2.5 V

  • 0 marks

    time constant (of smoothing circuit) = 0.058 s

  • 0 marks

    ripple / variation in (output) voltage = 1.6 V or 44%

9a · 1 mark

  • B1

    wavelength associated with a moving particle

9b · 4 marks

  • B1

    wave nature (matter): electron diffraction / interference

  • B1

    particle nature (matter): e.g. states of matter / state changes / gas behaviour / quantisation of charge / Kirchhoff’s first law / electrostatics / radioactive decay / properties of ionising radiation / Rutherford scattering / matter–antimatter annihilation

  • B1

    wave nature (EM radiation): diffraction / interference / polarisation in light / Doppler effect in light

  • B1

    particle nature (EM radiation): photoelectric effect

9c(i) · 3 marks

  • C1

    qV = ½mv^2

  • C1

    1.60 × 10^–19 × 3500 = ½ × 9.11 × 10^–31 × v^2

  • A1

    speed = 3.5 × 10^7 m s^–1

9c(ii) · 2 marks

  • C1

    wavelength = h / mv

  • A1

    = (6.63 × 10^–34) / (9.11 × 10^–31 × 3.5 × 10^7) = 2.1 × 10^–11 m

10a · 2 marks

  • M1

    energy required to separate (all) the nucleons (in the nucleus)

  • A1

    to infinity

10b(i) · 1 mark

  • B1

    positron

10b(ii) · 2 marks

  • C1

    E = (Δ)mc^2

  • A1

    = 0.030377 × 1.66 × 10^–27 × (3.00 × 10^8)^2 = 4.54 × 10^–12 J

10c(i) · 2 marks

  • C1

    F = L / 4πd^2

  • A1

    = (7.98 × 10^27) / (4π × (8.15 × 10^16)^2) = 9.56 × 10^–8 W m^–2

10c(ii) · 4 marks

  • C1

    number of He-4 nuclei formed per unit time = (7.98 × 10^27) / (4.54 × 10^–12)

  • C1

    number of H-1 nuclei fused = 4 × number of He-4 nuclei produced

  • C1

    mass of H-1 = 1.67 × 10^–27 × number of H-1 nuclei

  • A1

    mass rate = (4 × 1.67 × 10^–27 × 7.98 × 10^27) / (4.54 × 10^–12) = 1.17 × 10^13 kg s^–1

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