A Level Chemistry 9701 Paper 41, Oct/Nov 2025

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9701/41 · Oct/Nov 2025

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1
a(i)

Solutions of Group 2 hydrogencarbonates, M(HCO3)2, decompose on heating to give the corresponding metal carbonate, carbon dioxide and water. Write an equation for the decomposition of strontium hydrogencarbonate, Sr(HCO3)2.

[1]
a(ii)

The thermal stability of Group 2 carbonates increases down the group. Explain this trend.

[2]
b

The hydroxides and fluorides of Group 2 elements show similar trends in solubility. Describe the trend in the solubility of the fluorides of calcium, strontium and barium. Explain your answer. .................................... .................................... .................................... least soluble most soluble explanation ............................................................................................................................... ................................................................................................................................................... ................................................................................................................................................... ................................................................................................................................................... ................................................................................................................................................... ................................................................................................................................................... .............................................................................................................................................

[4]
c(i)

Define enthalpy change of hydration, ΔHhyd.

[1]
c(ii)

State the main factors that affect the magnitude of enthalpy change of hydration. Explain your answer.

[2]
d

Table 1.1 shows various energy changes. Table 1.1

energy changevalue / kJ mol−1
lattice energy of MgF2−2957
enthalpy change of hydration, ΔHhyd, of Mg2+−1926
enthalpy change of hydration, ΔHhyd, of F−−505

Use data from Table 1.1 to calculate the enthalpy change of solution, ΔHsol, for MgF2(s). It may be helpful to draw a labelled energy cycle. Show your working. ΔHsol of MgF2(s)=..............................  kJ mol−1

[2]
e(i)

Mercury(I) fluoride, Hg2F2, is sparingly soluble in water. The cation in Hg2F2 exists as the diatomic ion Hg22+ with a covalent Hg−Hg bond. Write the expression for the solubility product, Ksp, of Hg2F2. Include the units. Ksp= units ..............................

[2]
e(ii)

The solubility of Hg2F2 is 9.20×10−3 mol dm−3 at 298 K. Calculate the value of Ksp of Hg2F2 at 298 K. Ksp=..............................

[1]
2
a

Iron can form stable ions in the +2 and +3 oxidation states. Explain why transition elements have variable oxidation states.

[1]
b

Aqueous solutions of iron(II) salts contain the complex ion [Fe(H2O)6]2+. Define complex ion.

[1]
c(i)

[Fe(H2O)6]2+ can be converted into [Fe(H2O)4(OH)2]. Suggest a suitable reagent for this conversion. State the type of reaction. reagent .............................................................................................................................. type of reaction ..................................................................................................................

[1]
c(ii)

[Fe(H2O)4(OH)2] is a green precipitate that turns brown on standing in air. Table 2.1 shows electrode potentials for some electrode reactions. Table 2.1

electrode reactionE⊖/V
Fe(H2O)3(OH)3+H2O+e−⇌Fe(H2O)4(OH)2+OH−−0.56
O2+2H2O+4e−⇌4OH−+0.40

Use the information in Table 2.1 to explain why [Fe(H2O)4(OH)2] turns brown on standing in air. Include an equation for this reaction.

[3]
d

The complex [Co(NH3)6]2+ reacts with hydrogen peroxide as shown. reaction 1 2[Co(NH3)6]2++H2O2→2[Co(NH3)6]3++2OH−Ecell⊖=+1.67 V Calculate ΔG⊖, in kJ mol−1, for reaction 1. ΔG⊖=..............................  kJ mol−1

[2]
3
Figure 1 of 2 for question 3
Figure 2 of 2 for question 3
a

Solid manganese(IV) oxide, MnO2, catalyses the decomposition of hydrogen peroxide. 2H2O2(aq)→2H2O(l)+O2(g) State the type of catalysis for this reaction. Explain your answer.

[1]
b(i)

Hydrogen peroxide reacts with iodide ions in acidic conditions as shown. H2O2+2I−+2H+→2H2O+I2 The initial rate of this reaction is investigated with different concentrations of H2O2, I− and H+. The results obtained are shown in Table 3.1. Table 3.1

experiment[H2O2]/mol dm−3[I−]/mol dm−3[H+]/mol dm−3initial rate / mol dm−3 s−1
10.04500.03000.01252.42×10−3
20.02250.06000.01252.42×10−3
30.02250.1200.01254.84×10−3
40.04500.1200.05009.68×10−3

Use the information in Table 3.1 to deduce the rate equation for this reaction. Explain your reasoning.

[4]
b(ii)

Use your rate equation from (b)(i) and the data from Experiment 1 to calculate the rate constant, k, for this reaction. Include the units of k. k=.............................. units ..............................

[2]
c(i)

The rate of the thermal decomposition of azomethane, CH3N=NCH3, is investigated. CH3N=NCH3→N2+C2H6 Fig. 3.1 shows the results obtained. The reaction is first order with respect to CH3N=NCH3. Use Fig. 3.1 to calculate two half-lives, t12, to show that the reaction is first order.

[2]
c(ii)

Use your answer to (c)(i) to calculate the rate constant, k, for the decomposition of azomethane. k=..............................  s−1

[1]
d

Describe the effect of increasing temperature on the rate constant and on the rate of a reaction.

[1]
4
a

Define standard cell potential, Ecell⊖. Include a description of standard conditions.

[2]
b(i)

The Daniell cell is an electrochemical cell consisting of a Cu2+(aq)/Cu(s) electrode and a Zn2+(aq)/Zn(s) electrode. Draw a labelled diagram of this electrochemical cell. Include all necessary substances and relevant pieces of apparatus needed to measure the Ecell⊖. It is not necessary to state the conditions used.

[3]
b(ii)

State the charge carriers that transfer current through the solutions and through the wire. the solutions .............................. the wire ..............................

[1]
b(iii)

The standard electrode potential, E⊖, for the Zn2+(aq)/Zn(s) electrode is −0.76 V. Water is added to a standard Zn2+(aq)/Zn(s) electrode. The new concentration of Zn2+(aq) is 0.25 mol dm−3. Use the Nernst equation to calculate the electrode potential, E, for this new Zn2+(aq)/Zn(s) electrode. E(Zn2+(aq)/Zn(s))=.............................. V

[2]
c(i)

An electrochemical cell consists of a ZnO/Zn electrode and a MnO2/Mn2O3 electrode in an alkaline electrolyte. The standard cell potential, Ecell⊖, for this cell is +1.47 V. The half-equation at each electrode when this cell is discharging is shown. Zn+2OH−→ZnO+H2O+2e− 2MnO2+H2O+2e−→Mn2O3+2OH− Use this information to determine the change in oxidation state of manganese when this cell is discharging. from .............................. to ..............................

[1]
c(ii)

Write the equation for the overall reaction that occurs when this cell is discharging.

[1]
c(iii)

The E⊖ for the ZnO/Zn electrode is −1.28 V. Calculate the standard electrode potential, E⊖, for the MnO2/Mn2O3 electrode. E⊖(MnO2/Mn2O3)=.............................. V

[1]
5
a

Copper shows typical properties of transition elements, including its behaviour as a catalyst. Complete Table 5.1 to show the total number of unpaired electrons in the 3d and 4s orbitals of an isolated gaseous Cu atom and a Cu2+ ion. Table 5.1

speciesnumber of unpaired electrons
3d4s
Cu
Cu2+
[1]
b

The 3d orbitals in an isolated Cu2+ ion are degenerate. Complete the diagram to show the relative energies of the 3d orbitals in an isolated Cu2+ ion and in Cu2+ in a tetrahedral complex.

[2]
c

Explain why transition elements behave as catalysts.

[2]
d

CN− is a monodentate ligand. Table 5.2 shows information about two complex ions that contain only CN− ions as ligands. Complete Table 5.2. Table 5.2

metal ioncoordination numberformula of complex ioncharge of complex ion
Ag+2
Fe2+4-
[2]
e

The complex ion [Au(CN)2Br2]− displays geometrical (cis/trans) isomerism. Draw the structure of trans-[Au(CN)2Br2]−. State its shape and the Br-Au-Br bond angle. shape .............................. Br-Au-Br bond angle = ..............................

[2]
f(i)

An impure sample of a vanadium(V) compound of mass 0.250 g is dissolved in aqueous acid. This solution contains VO3− ions. An excess of zinc is added to this solution. All the VO3− ions are reduced to V2+ ions and Zn atoms are oxidised to Zn2+ ions. The unreacted zinc is removed and the resulting solution is titrated with acidified MnO4−. The end-point is reached when 22.5 cm3 of 0.0750 mol dm−3 MnO4− is added. A redox reaction takes place and all the V2+ reacts forming VO3−. 3MnO4−+5V2++3H2O→3Mn2++5VO3−+6H+ Calculate the percentage by mass of vanadium in the 0.250 g of impure sample. Assume the impurities do not contain any vanadium ions. Show your working. percentage of vanadium = ..............................

[3]
f(ii)

Complete the equation for the reaction between acidified VO3− ions and Zn metal. ...... VO3− + ...... Zn + ............ → ...... V2+ + ...... Zn2+ + ..............

[2]
6
Figure 1 of 1 for question 6
a(i)

Thin-layer and gas/liquid chromatography can be used to separate mixtures into their individual components. Define the following terms used in chromatography. Rf value ............................................................................................................................. ........................................................................................................................................... retention time .................................................................................................................... ...........................................................................................................................................

[2]
a(ii)

Each type of chromatography makes use of a stationary phase and a mobile phase. Complete Table 6.1 with a description of each of these. Table 6.1

stationary phasemobile phase
thin-layer chromatography
gas/liquid chromatography
[1]
b

A mixture of two substances A and B is analysed by thin-layer chromatography. The Rf value of substance A is larger than that of substance B. Suggest why substance A has a larger Rf value.

[1]
c(i)

The two isomeric compounds Y and Z are analysed by proton (1H) NMR spectroscopy. Complete Table 6.2 to predict the number of peaks observed in the proton (1H) NMR spectra for Y and Z. Table 6.2

compoundnumber of peaks observed
Y
Z
[1]
c(ii)

Name all the different splitting patterns observed in the proton (1H) NMR spectra for Y and Z. Y ........................................................................................................................................ Z ........................................................................................................................................

[2]
7
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Figure 2 of 6 for question 7
Figure 3 of 6 for question 7
Figure 4 of 6 for question 7
Figure 5 of 6 for question 7
Figure 6 of 6 for question 7
a

State the relative acidities of bromoethanoic acid, BrCH2COOH, chloroethanoic acid, ClCH2COOH, ethanoic acid, CH3COOH and ethanol, CH3CH2OH. Explain your answer. .................................. .................................. .................................. .................................. most acidic least acidic ................................................................................................................................................... ................................................................................................................................................... ................................................................................................................................................... ................................................................................................................................................... ................................................................................................................................................... ................................................................................................................................................... ...................................................................................................................................................

[4]
b

Fig. 7.1 shows the reaction of methylbenzene and ethanedioic acid with KMnO4. Predict the major carbon-containing product for each of these reactions.

[2]
c(i)

Polyamide X can be synthesised from ethanedioic acid and benzene-1,4-diamine. Draw the repeat unit of polyamide X in the box. The new functional group formed should be shown displayed. polyamide X

[2]
c(ii)

Benzene-1,4-diamine can be formed by reduction of 1,4-dinitrobenzene. Complete the equation for this reduction. [H] represents one atom of hydrogen from a reducing agent. + .......... [H] →H2N−C6H4−NH2 + .......................................................... .....................

[1]
d(i)

Fig. 7.2 shows the two-step synthesis of the azo compound W. Suggest structures for compounds V and W and draw them in the boxes in Fig. 7.2.

[2]
d(ii)

Give the reagents and conditions for step 1.

[1]
8
Figure 1 of 4 for question 8
Figure 2 of 4 for question 8
Figure 3 of 4 for question 8
Figure 4 of 4 for question 8
a(i)

In the electrophilic substitution of arenes, different substituents can direct to different ring positions. Describe the directing effect of the −NO2 group. Explain your answer.

[1]
a(ii)

The nitration of arenes uses a mixture of concentrated HNO3 and concentrated H2SO4 to generate the NO2+ electrophile. Write an equation for the formation of the NO2+ electrophile.

[1]
b(i)

Carbon-carbon bond formation is an important reaction in organic synthesis. Fig. 8.1 shows the synthesis of compound Q from benzene in two reaction steps. Draw the structure of compound P in the box in Fig. 8.1.

[1]
b(ii)

Suggest reagents and conditions for reactions 1 and 2 in Fig. 8.1. reaction 1 .......................................................................................................................... reaction 2 ..........................................................................................................................

[2]
c

Separate samples of C6H5Br and C6H5CH2Br are added to warm AgNO3(aq). State the expected observations, if any. Explain your answer. C6H5Br with AgNO3(aq) ................................................ C6H5CH2Br with AgNO3(aq) ................................................ explanation ............................................................................................................................... ................................................................................................................................................... ................................................................................................................................................... ...................................................................................................................................................

[3]
d(i)

Acyl bromides, RCOBr, react readily with H2O. The mechanism of this reaction is similar to that of the reaction of H2O with acyl chlorides, RCOCl. Name the mechanism of this reaction.

[1]
d(ii)

Complete the mechanism in Fig. 8.2 for the reaction of RCOBr with H2O. Include all relevant lone pairs of electrons, curly arrows, charges and dipoles. Draw the structure of the intermediate.

[4]
9
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Figure 5 of 10 for question 9
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Figure 7 of 10 for question 9
Figure 8 of 10 for question 9
Figure 9 of 10 for question 9
Figure 10 of 10 for question 9
a

Explain why amides are much weaker bases than amines.

[2]
b(i)

Fig. 9.1 shows the preparation of 2-phenylethylamine, C6H5CH2CH2NH2, by three different routes. Suggest structures for compounds M and N and draw them in the boxes in Fig. 9.1.

[2]
b(ii)

Give the reagents and conditions for reaction 1.

[1]
c

Fig. 9.2 shows compound H which is a useful starting material in organic synthesis. H contains an alkene and an amine functional group. Name the other functional group and give the classification of the amine group in H. other functional group in H ................................................ classification of amine ................................................

[1]
d(i)

Ozonolysis involves the oxidative cleavage of a C=C bond in alkenes using ozone, O3, as shown in Fig. 9.3. Fig. 9.4 shows the first step in this reaction which involves the formation of an ozonide intermediate. On Fig. 9.4, draw three curly arrows to complete the mechanism of this step.

[2]
d(ii)

L is formed from alkene K, C8H14, by a similar reaction to that shown in Fig. 9.3. Suggest the structure of K. K C8H14

[1]

Mark scheme

9701/41 · Oct/Nov 2025

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1a(i) · 1 mark

  • 1 mark

    Sr(HCO3)2 → SrCO3 + CO2 + H2O

1a(ii) · 2 marks

  • M1

    radius of cation / M2+ increases OR charge density of cation / M2+ decreases

  • M2

    less polarisation / less distortion of the anion / carbonate ion

1b · 4 marks

  • M1

    least soluble CaF2 < SrF2 < BaF2 most soluble

  • M2

    Hlatt and Hhyd both become less exothermic / less negative

  • M3

    Hhyd changes less / becomes less exothermic by a smaller extent OR Hlatt changes more / becomes less exothermic by a larger extent

  • M4

    Hsol becomes more exothermic / more negative

1c(i) · 1 mark

  • 1 mark

    enthalpy change when one mole of gaseous ions dissolve in water to form a solution

1c(ii) · 2 marks

  • M1

    ionic radii AND ionic charge

  • M2

    (ionic) radii increase / charge density decreases AND ∆Hhyd decreases/less exothermic AND less attraction between water molecules and (gaseous) ions OR as ionic charge increases / charge density increases AND ∆Hhyd increases/more exothermic AND more attraction between water molecules and (gaseous) ions

1d · 2 marks

  • M1

    use of –2957 / –1926 / –505 AND 2  (–505)

  • M2

    correct signs and evaluation ∆Hsol of MgF2(s) = –1926 + (2  –505) – (–2957) = (+)21 kJ mol–1

1e(i) · 2 marks

  • M1

    Ksp = [Hg22+] [F–]2

  • M2

    units = mol3 dm–9

1e(ii) · 1 mark

  • 1 mark

    Ksp = 22  (9.20  10–3)3 = 3.11  10–6 min 2sf

2a · 1 mark

  • 1 mark

    the (3)d and (4)s sub-shells / orbitals / electrons are close / similar in energy

2b · 1 mark

  • 1 mark

    species or ion formed by a central metal atom/ion AND surrounded by/bonded to (one or more) ligands

2c(i) · 1 mark

  • 1 mark

    NaOH / OH–(aq) AND precipitation / ligand exchange / deprotonation / acid–base

2c(ii) · 3 marks

  • M1

    Fe(H2O)4(OH)2 is oxidised (from + 2 to + 3 on standing)

  • M2

    Eo of Fe(H2O)3(OH)3 is more negative than Eo of O2 OR Eocell = 0.40 – (–0.56) = (+)0.96 V

  • M3

    4Fe(H2O)4(OH)2 + O2 → 4Fe(H2O)3(OH)3 + 2H2O

2d · 2 marks

  • M1

    ∆Go = –nEocellF AND n = 2 OR –2  1.67  96 500

  • M2

    ∆Go = –322.3 kJ mol–1

3a · 1 mark

  • 1 mark

    heterogeneous AND MnO2 is in a different state / phase to the reactants / H2O2

3b(i) · 4 marks

  • M1

    (expt 2 and 3) [I–]  2 initial rate  2 so 1st order wrt [I–]

  • M2

    (expt 1 and 2) [I–]  2, [H2O2]  0.5 initial rate  1 so 1st order wrt [H2O2] OR (expt 1 and 4) [I–]  4 initial rate  4 AND [H+]  4 so zero order wrt [H+] OR (expt 1 and 3) [I–]  4, [H2O2]  0.5 initial rate  2 so 1st order wrt [H2O2]

  • M3

    (expt 1 and 4) [I–] x 4 , [H+]  4 initial rate  4 so zero order wrt [H+] OR (expt 3 and 4) [H2O2]  2 initial rate  2AND [H+] x 4 so zero order wrt [H+] OR (expt 3 and 4) [H2O2]  2, [H+]  4 initial rate  2 so 1st order wrt [H2O2]

  • M4

    rate = k [H2O2] [I–] OR rate = k [H2O2] [I–] [H+]0

3b(ii) · 2 marks

  • M1

    k = 2.42  10–3 ÷ (0.045  0.030) = 1.79 min 2sf

  • M2

    units = dm3 mol-1 s-1

3c(i) · 2 marks

  • M1

    calculation of one t1/2 = 60 s ± 5 s

  • M2

    two t1/2 calculated that are constant

3c(ii) · 1 mark

  • 1 mark

    k = In2 ÷ 60 = 0.0116 OR k = 0.693 ÷ 60 = 0.0116 min 2sf

3d · 1 mark

  • 1 mark

    increases k and increases the rate of reaction

4a · 2 marks

  • M1

    potential difference / voltage / EMF AND between two half-cells / two electrodes (in a cell)

  • M2

    (at concentration of) 1 mol dm–3 AND (pressure of) 1 atm / 101 kPa AND (temperature of) 298 K / 25 °C

4b(i) · 3 marks

  • M1

    salt bridge labelled AND voltmeter / V AND wire to electrode and liquid level shown [complete circuit]

  • M2

    Cu(s) AND Cu2+(aq)

  • M3

    Zn(s) AND Zn2+(aq)

4b(ii) · 1 mark

  • 1 mark

    ions AND electrons

4b(iii) · 2 marks

  • M1

    Nernst equation E = Eo + (0.059/z) log(Zn2+/Zn)

  • M2

    E = –0.76 + (0.059 / 2) log(0.25) = –0.778 V OR E = –0.76 + (8.31  298) / (96 500  2) ln(0.25) = –0.778 V min 2sf

4c(i) · 1 mark

  • 1 mark

    (from) +4 (to) +3

4c(ii) · 1 mark

  • 1 mark

    Zn + 2MnO2 → ZnO + Mn2O3

4c(iii) · 1 mark

  • 1 mark

    Eo(MnO2 / Mn2O3) = 1.47 – 1.28 = (+)0.19 V

5a · 1 mark

  • 1 mark

    species Cu: 3d = 0, 4s = 1; Cu2+: 3d = 1, 4s = 0

5b · 2 marks

  • 1 mark

    five 3d orbitals (lines, boxes) in the isolated Cu2+ ion of the same energy

  • 1 mark

    splitting: three higher and two lower d orbitals

  • 1 mark

    energy of all five d orbitals in complex higher than all d orbitals in isolated ion

5c · 2 marks

  • M1

    more than one (stable) oxidation state / exist in variable oxidation states

  • M2

    vacant / empty (d) orbitals are energetically accessible OR vacant / empty (d) orbitals can form dative bonds with ligands

5d · 2 marks

  • 1 mark

    Ag+: coordination number = 2, formula = Ag(CN)2, charge = 1–

  • 1 mark

    Fe2+: coordination number = 6, formula = Fe(CN)6, charge = 4–

5e · 2 marks

  • M1

    stereoisomers drawn for Au(CN)2Br2

  • M2

    (shape) square planar AND (bond angle) 180o

5f(i) · 3 marks

  • M1

    moles MnO4– = 0.075  0.0225 = 1.6875  10–3

  • M2

    moles V2+ = 5 / 3  1.6875  10–3 = 2.8125  10–3

  • M3

    mass V = 50.9  2.8125  10–3 = 0.143 g % of V = 0.143 / 0.250  100 = 57.3 min 2sf

5f(ii) · 2 marks

  • M1

    2 : 3 ratio on both sides

  • M2

    rest of the equation correct

6a(i) · 2 marks

  • M1

    (Rf value) is distance moved by a component / spot / solute AND divided by distance moved by solvent OR (Rf value) is the ratio of distance moved by a component / spot / solute AND by distance moved by solvent

  • M2

    (retention time) is (the time) between injection and detection (of a component)

6a(ii) · 1 mark

  • 1 mark

    thin-layer chromatography: polar solvent OR non-polar solvent OR named solvent gas-liquid chromatography: non-volatile liquid OR high boiling point liquid

6b · 1 mark

  • 1 mark

    A is more soluble in the mobile phase OR A has less adsorption to the stationary phase

6c(i) · 1 mark

  • 1 mark

    Y: 2, Z: 2

6c(ii) · 2 marks

  • M1

    Y (two) singlet(s)

  • M2

    Z triplet AND quartet

7a · 4 marks

  • M1

    ClCH2COOH BrCH2COOH CH3COOH CH3CH2OH (most acidic to least acidic)

  • M2

    electron withdrawing groups / electronegative groups / negative inductive effect AND weakens O–H bond / more stable anion OR electron donating groups / positive inductive effect AND strengthens O-H bond / less stable anion

  • M3

    chlorine is more electron-withdrawing / electronegative than bromine (related to XCH2COOH)

  • M4

    electron withdrawing of C=O / negative inductive effect of C=O (related to COOH) OR positive inductive effect / electron donating of alkyl / ethyl / R group (related to ROH)

7b · 2 marks

  • M1

    benzoic acid structure / C6H5COOH

  • M2

    CO2

7c(i) · 2 marks

  • M1

    correct displayed amide bond with C=O, (C6H5)−N and (C–)C=O

  • M2

    rest of the structure correct with continuation bonds

7c(ii) · 1 mark

  • 1 mark

    O2N-C6H4-NO2 + 12[H] → H2N-C6H4-NH2 + 4H2O

7d(i) · 2 marks

  • M1

    Cl- +N#N-C6H4-N#N+ Cl-

  • M2

    structure of bis-azo dye

7d(ii) · 1 mark

  • 1 mark

    HNO2 (and HCl) AND ⩽10 °C OR NaNO2 AND HCl AND ⩽10 °C

8a(i) · 1 mark

  • 1 mark

    NO2 group directs to 3 (and 5) / meta position AND due to being an electron-withdrawing / electronegative group

8a(ii) · 1 mark

  • 1 mark

    HNO3 + H2SO4 → NO2+ + HSO4– + H2O OR HNO3 + 2H2SO4 → NO2+ + 2HSO4– + H3O+

8b(i) · 1 mark

  • 1 mark

    acetophenone / C6H5COCH3 structure

8b(ii) · 2 marks

  • M1

    (reaction 1) ethanoyl chloride / CH3COCl AND AlCl3

  • M2

    (reaction 2) 2-bromopropane / (CH3)2CHBr AND FeBr3

8c · 3 marks

  • M1

    with C6H5Br no change / no precipitate AND with C6H5CH2Br cream precipitate

  • M2

    in C6H5Br: lone pair / p-orbital on Br delocalised / overlaps with ring /  system

  • M3

    C–Br bond stronger / has partially double bond character

8d(i) · 1 mark

  • 1 mark

    (nucleophilic) addition–elimination

8d(ii) · 4 marks

  • M1

    any two of: lone pair on O; curly arrow from (lone pair) O (in H2O) to C (of C=O); correct dipole on C=O; curly arrow from the C=O bond to O atom

  • M2

    all four of: lone pair on O; curly arrow from (lone pair) O (in H2O) to C (of C=O); correct dipole on C=O; curly arrow from the C=O bond to O atom

  • M3

    correct intermediate

  • M4

    curly arrow from (lone pair on) O(–) to C–O bond AND curly arrow from C–Br to Br

9a · 2 marks

  • M1

    (basicity linked to) ability of lone pair / p-orbital to AND accept / coordinate with a proton / H+

  • M2

    (lone pair of) electrons on N is delocalised into C=O group (and make amides neutral)

9b(i) · 2 marks

  • M1

    structure M (C6H5CH2CH2CN)

  • M2

    structure N (C6H5CH2CH2Br)

9b(ii) · 1 mark

  • 1 mark

    LiAlH4

9c · 1 mark

  • 1 mark

    ketone / carbonyl AND secondary / 2o

9d(i) · 2 marks

  • 1 mark

    curly arrow 1: from O lone pair to C atom (in C=C)

  • 1 mark

    curly arrow 2: from C=C bond to the right-hand O atom in O=O AND curly arrow 3: from O=O bond to O+

9d(ii) · 1 mark

  • 1 mark

    structure of 1-ethyl-2-methylcyclopentene

Questions

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  2. 2
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  3. 3
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  4. 4
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  5. 5
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  6. 6
    Question 67 marks
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  7. 7
    Question 712 marks
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  8. 8
    Question 813 marks
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  9. 9
    Question 99 marks
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