A Level Chemistry 9701 Paper 42, May/June 2023

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9701/42 · May/June 2023

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1
Figure 1 of 2 for question 1
Figure 2 of 2 for question 1
a(i)

Group 2 carbonates decompose when heated to form the metal oxide and carbon dioxide. Suggest a mechanism for the decomposition of the carbonate ion by adding two curly arrows in Fig. 1.1.

[1]
a(ii)

Describe the variation in the thermal stability of Group 2 carbonates. Explain your answer.

[3]
b(i)

Define lattice energy.

[2]
b(ii)

The lattice energy of the Group 2 carbonates, ΔHlatt⊖(MCO3), becomes less exothermic down the group. The lattice energy of the Group 2 oxides, ΔHlatt⊖(MO), also becomes less exothermic down the group. ΔHlatt⊖(MCO3) and ΔHlatt⊖(MO) change by different amounts going down the group. Suggest how the standard enthalpy change of the decomposition reaction for Group 2 carbonates changes down the group. Explain your reasoning in terms of the relative sizes of the anions and the relative changes in lattice energy down the group.

[2]
c(i)

Potassium sulfite, K2SO3, is used as a food additive. The concentration of sulfite ions, SO32−, can be determined by titration using aqueous acidified manganate(VII) ions, MnO4−. • A 250 cm3 solution contains 3.40 g of impure K2SO3. • 25.0 cm3 of this solution requires 22.40 cm3 of 0.0250 mol dm−3 acidified MnO4− to reach the end-point. All the SO32− ions are oxidised. None of the other species in the impure K2SO3 are oxidised. The reaction occurs as shown by the two half-equations. H2O+SO32−→SO42−+2H++2e− MnO4−+8H++5e−→Mn2++4H2O Give the ionic equation for the reaction between SO32− and acidified MnO4−.

[1]
c(ii)

Calculate the percentage purity of the sample of K2SO3. Show your working.

[3]
d

Potassium disulfite, K2S2O5, is another food additive. The disulfite ion, S2O52−, has the displayed formula shown in Fig. 1.2. Deduce the geometry (shape) around the S(α) atom in S2O52−.

[1]
2
Figure 1 of 2 for question 2
Figure 2 of 2 for question 2
a

State two typical chemical properties of a transition element.

[1]
b(i)

Aqueous solutions of cobalt(II) salts contain the complex ion [Co(H2O)6]2+. Define complex ion.

[1]
b(ii)

Samples of [Co(H2O)6]2+ are reacted separately with an excess of aqueous ammonia, with an excess of concentrated HCl and with an excess of aqueous sodium hydroxide, as shown in Fig. 2.1. Complete Table 2.1 about the reactions shown by [Co(H2O)6]2+.

[4]
c(i)

The ethanedioate ion, C2O42−, can act as a bidentate ligand. Explain what is meant by a bidentate ligand.

[2]
c(ii)

The complex [Co(H2O)2(C2O4)BrCl]− exists as stereoisomers. Complete the three-dimensional diagrams in Fig. 2.2 to show four stereoisomers of [Co(H2O)2(C2O4)BrCl]−. The C2O42− ligand is represented using O—O.

[3]
c(iii)

State the oxidation state of cobalt in this complex and a type of stereoisomerism shown.

[1]
3
a

Complete Table 3.1 by placing one tick (✓) in each row to indicate the sign of each type of energy change under standard conditions.

[1]
b

Define standard enthalpy change of atomisation.

[2]
c

Table 3.2 shows some energy changes. Calculate the lattice energy, ΔHlatt⊖, of Ag2O(s) using relevant data from Table 3.2. It may be helpful to draw a labelled energy cycle. Show your working.

[3]
d

Suggest the trend in the magnitude of the lattice energies of the silver compounds Ag2S, Ag2O and Ag2Se. Explain your answer.

[2]
e(i)

Silver sulfite, Ag2SO3(s), is sparingly soluble in water. Give an expression for the solubility product, Ksp, of Ag2SO3.

[1]
e(ii)

Calculate the equilibrium concentration of Ag+ in a saturated solution of Ag2SO3 at 298 K. [Ksp: Ag2SO3, 1.50×10−14 mol3 dm−9 at 298 K]

[1]
f

The standard enthalpy change of solution, ΔHsol⊖, of AgNO3(s) in water is +22.6 kJ mol−1. Suggest how the feasibility of dissolving AgNO3(s) in water changes with temperature. Explain your answer.

[2]
4
Figure 1 of 1 for question 4
a(i)

In aqueous solution, iron(III) ions react with iodide ions, as shown. 2Fe3++2I−→2Fe2++I2 A series of experiments is carried out using different concentrations of Fe3+ and I−, as shown in Table 4.1. Explain what is meant by overall order of reaction.

[1]
a(ii)

Use the data in Table 4.1 to deduce the order of reaction with respect to Fe3+ and with respect to I−. Explain your reasoning.

[2]
a(iii)

Use your answer to (a)(ii) to construct the rate equation for this reaction.

[1]
a(iv)

Use your answer to (a)(iii) and the data from experiment 1 to calculate the rate constant, k, for this reaction. Include the units of k.

[2]
a(v)

Describe qualitatively the effect of an increase in temperature on the rate constant and on the rate of this reaction.

[1]
b(i)

In aqueous solution, iodide ions react with acidified hydrogen peroxide, as shown. 2I−+H2O2+2H+→I2+2H2O The initial rate of reaction is found to be first order with respect to I−, first order with respect to H2O2 and zero order with respect to H+. Fig. 4.1 shows a possible four-step mechanism for this reaction. step 1: H2O2+I−→IO−+H2O step 2: H++IO−→HIO step 3: HIO+I−→I2+OH− step 4: OH−+H+→H2O Suggest which of the steps, 1, 2, 3 or 4, in this mechanism is the rate-determining step. Explain your answer.

[1]
b(ii)

Identify a step in Fig. 4.1 that involves a redox reaction. Explain your answer in terms of oxidation numbers.

[1]
b(iii)

Suggest the role of HIO in this mechanism. Explain your reasoning.

[1]
5
Figure 1 of 4 for question 5
Figure 2 of 4 for question 5
Figure 3 of 4 for question 5
Figure 4 of 4 for question 5
a(i)

Methylbenzene can undergo different reactions, as shown in Fig. 5.1. Draw structures in Fig. 5.1 for the possible organic products of the three reactions shown.

[3]
a(ii)

Complete Table 5.1.

[2]
b

When methylbenzene reacts with an electrophile, a substitution reaction occurs. No addition reaction takes place under these conditions. Explain why no addition reaction takes place.

[1]
c(i)

The reaction of methylbenzene with thionyl bromide, SOBr2, in the presence of an iron(III) bromide catalyst, FeBr3, is shown in Fig. 5.2. The mechanism of this reaction is similar to that of the bromination of benzene. The first step of the mechanism generates the SOBr+ electrophile, as shown. SOBr2+FeBr3→SOBr++FeBr4− The reaction of methylbenzene with SOBr+ ions is shown in Fig. 5.3. Complete the mechanism in Fig. 5.3. Include all relevant curly arrows and charges. Draw the structure of the organic intermediate.

[3]
c(ii)

The reaction shown in Fig. 5.2 produces a small amount of a by-product, P, with the molecular formula C14H14OS. Suggest a structure for by-product P.

[1]
d(i)

Acyl bromides, RCOBr, can be synthesised by the reaction of a carboxylic acid and SOBr2. This is a similar reaction to the synthesis of acyl chlorides using SOCl2. Give an equation for the reaction between ethanoic acid and SOBr2.

[1]
d(ii)

Suggest the relative ease of hydrolysis of acyl bromides, RCOBr, acyl chlorides, RCOCl, and alkyl chlorides, RCl. Explain your answer.

[3]
6
Figure 1 of 2 for question 6
Figure 2 of 2 for question 6
a(i)

Perindopril is a drug used to treat heart disease. State the number of chiral carbon atoms present in one molecule of perindopril.

[1]
a(ii)

Suggest one benefit and one disadvantage of producing a drug such as perindopril as a single pure optical isomer.

[2]
b(i)

Name all the functional groups in perindopril.

[2]
b(ii)

A sample of perindopril is hydrolysed with hot aqueous acid. Draw the structures of the three organic products of the complete acid hydrolysis of perindopril.

[3]
7
Figure 1 of 1 for question 7
a

Explain why phenol is brominated much more easily than benzene is brominated.

[3]
b

Iodine monobromide, I-Br, reacts with benzene in the presence of an AlBr3 catalyst. Predict whether the organic product will be bromobenzene or iodobenzene. Explain your answer.

[1]
c(i)

Fig. 7.1 shows some reactions of phenol. Give an equation for the reaction of phenol with Na(s).

[1]
c(ii)

Draw the structure of the organic product, R, formed when phenol reacts with an excess of Br2(aq).

[1]
c(iii)

State the reagents and conditions for reaction 1 and reaction 2 in Fig. 7.1.

[2]
8
Figure 1 of 2 for question 8
Figure 2 of 2 for question 8
a

Describe the difference in reactivity between chloroethane and chlorobenzene with OH−(aq). Explain your answer.

[2]
b(i)

Compound T, C5H9O2Cl, is a useful synthetic intermediate. Fig. 8.1 shows some reactions of T. Give the systematic name for T.

[1]
b(ii)

Draw the structures of W, X, Y and Z in Fig. 8.1.

[4]
b(iii)

State the reagents and conditions for steps 1 and 2 in Fig. 8.1.

[2]
c(i)

The proton (1H) NMR spectrum of compound T, C5H9O2Cl, in CDCl3 is shown in Fig. 8.2. Suggest why CDCl3 is used as a solvent instead of CHCl3 for the proton (1H) NMR spectrum.

[1]
c(ii)

Complete Table 8.2 for the proton (1H) NMR spectrum of T.

[4]
c(iii)

Explain the splitting pattern of the peak at δ 3.9 ppm.

[1]
9
a

Define standard cell potential, Ecell⊖.

[1]
b

An electrochemical cell is set up to measure Ecell⊖ of a cell consisting of an Fe3+/Fe2+ half-cell and a Cl2/Cl− half-cell. Draw a labelled diagram of this electrochemical cell. Include all necessary substances. It is not necessary to state conditions used.

[3]
c

The cell reaction for the electrochemical cell in (b) is shown. Cl2+2Fe2+→2Fe3++2Cl−Ecell⊖=+0.59 V Calculate ΔG⊖, in kJ mol−1, for this cell reaction.

[2]
d(i)

Another experiment is set up using the same electrochemical cell. In this experiment the Fe2+ concentration is 0.15 mol dm−3. All other concentrations remain at their standard values. The Nernst equation is shown. E=E⊖+(0.059/z)log⁡[oxidised species][reduced species] Use the Nernst equation to calculate the electrode potential, E, for the Fe3+/Fe2+ half-cell in this experiment. [E⊖: Fe3+/Fe2+=+0.77 V]

[1]
d(ii)

Use your answer to (d)(i) to calculate Ecell for this electrochemical cell.

[1]

Mark scheme

9701/42 · May/June 2023

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1a(i) · 1 mark

  • 1 mark

    ARROW 1 starts from O– to the C–O bond AND ARROW 2 starts at the C-O bond to other O– ion

1a(ii) · 3 marks

  • M1

    increases (down the group)

  • M2

    (cat)ionic radius / ion size increases (down the group) OR charge density of M2+ decreases

  • M3

    less polarisation / distortion of anion / carbonate ion / CO3(2)–

1b(i) · 2 marks

  • M1

    energy released when one mole of a ionic solid / compound is formed

  • M2

    from gas (phase) ion(s) / gaseous ion(s) (under standard conditions)

1b(ii) · 2 marks

  • 1 mark

    Any two points from: (ΔHdecomp / it) becomes more positive/less negative (down the group); size /(ionic) radii of oxide ion is smaller (than carbonate ion) ORA; so ΔHlatt of oxides becomes ORA less exothermic faster OR less negative faster OR changes more OR changes faster

  • 1 mark

    All three points from above

1c(i) · 1 mark

  • 1 mark

    2MnO4– + 6H+ + 5SO32– → 2Mn2+ + 3H2O + 5SO42–

1c(ii) · 3 marks

  • M1

    any two bullets from: moles MnO4– = 0.025 × 22.40 / 1000 = 5.6 × 10–4; moles SO32– = 5.6 × 10–4 × 5 / 2 = 1.4 × 10–3 (in 25 cm3) ecf from (c)(i) and bullet 1; moles SO32– = 1.4 × 10–2 (in 250 cm3) ecf bullet 2; mass K2SO3 = 1.4 × 10–2 × 158.3 = 2.2162 g ecf bullet 3 OR moles K2SO3 (if 100% pure) = 3.40 ÷ 158.3 = 0.02148

  • M2

    all four bullets from above

  • M3

    % purity = 100 × 2.2162 / 3.40 = 65.2 / 65.3 % ecf min 2sf OR % purity = 100 × 0.014 / 0.02148 = 65.2 / 65.3 %

1d · 1 mark

  • 1 mark

    S(α) tetrahedral

2a · 1 mark

  • 1 mark

    Any two from: they have variable / multiple oxidation states OWTTE; they behave as catalysts; they form complex ions / complexes; they form coloured compounds/ions

2b(i) · 1 mark

  • 1 mark

    (is a molecule or ion formed by a central) metal atom / metal ion bonded / surrounded by (one or more) ligands

2b(ii) · 4 marks

  • 1 mark

    formula and colour / state: any two correct

  • 1 mark

    formula and colour / state: any four correct

  • 1 mark

    formula and colour / state: all six correct

  • 1 mark

    type of reaction: all three correct

2c(i) · 2 marks

  • M1

    (a species) that donates / uses two lone pairs

  • M2

    to form a two dative / coordinate bond to a metal atom / metal ion

2c(ii) · 3 marks

  • 1 mark

    Any two correct isomer structures drawn

  • 1 mark

    Any three correct isomer structures drawn

  • 1 mark

    All four correct isomer structures drawn

2c(iii) · 1 mark

  • 1 mark

    oxidation state of cobalt (+)3 AND type of stereoisomerism cis-trans OR geometric(al) OR optical

3a · 1 mark

  • 1 mark

    bond energy: always positive; enthalpy change of atomisation: always positive; enthalpy change of formation: can be either negative or positive

3b · 2 marks

  • M1

    (enthalpy change) when one mole of gaseous atoms is produced

  • M2

    from its element(s) in its standard state / standard conditions / 298 K AND 1 atm

3c · 3 marks

  • M1

    use of correct six numbers only –31 / 285 / 731 / –141 / 798 / 496

  • M2

    2 × used correctly with Ag (2 × 285 (570) and 2 × 731 (1462)) AND 0.5 with O=O (496 (248))

  • M3

    correct signs and evaluation: –31 = (2 × 285) + (2 × 731) + (–141) + (798) + x + (0.5 × 496), x = –2968 kJ mol–1

3d · 2 marks

  • 1 mark

    Any two points from: Ag2Se least exothermic to Ag2O most exothermic OWTTE; charge density of anion decreases down the group ORA / radius/size of anion increases down the group / Se2– largest radius / O2– smallest radius / O has smallest ionic radius; less attraction between the ions / ionic bond gets weaker (with Ag2Se) ORA

  • 1 mark

    All three points from above

3e(i) · 1 mark

  • 1 mark

    (Ksp = ) [Ag+]2[SO32–]

3e(ii) · 1 mark

  • 1 mark

    x = 3√1.5 × 10–14 / 4 = 1.55 × 10–5 (mol dm-3) and [Ag+] = 1.55 × 10–5 × 2 = 3.11 × 10–5 (mol dm-3) min 2sf ecf (e)(i)

3f · 2 marks

  • 1 mark

    Any two points from: feasibility / it increases as temperature increases ORA; ΔS is positive / ΔS is >0 / entropy change is positive (and ΔH is positive) OR –TΔS becomes more negative / TΔS becomes more positive; as ΔG becomes / is negative / ΔG < 0

  • 1 mark

    All three points from above

4a(i) · 1 mark

  • 1 mark

    the sum/total of the power / exponent to which a concentration of a reactant is raised in the rate equation / law

4a(ii) · 2 marks

  • M1

    (expt 1 and 2) when [Fe3+] × 3, rate × 3 so first order w.r.t. Fe3+

  • M2

    (expt 1 and 3) when [Fe3+] × 2, [I–] × 2, rate × 8 so second order w.r.t. I– OR (expt 2 and 3) when [Fe3+] ÷ 1.5, [I–] × 2, rate × 2.7 so second order w.r.t. I–

4a(iii) · 1 mark

  • 1 mark

    (rate =) k[Fe3+][I–]2 ecf (a)(ii)

4a(iv) · 2 marks

  • 1 mark

    k = 16.5 min 2sf ecf

  • 1 mark

    units = mol-2 dm6 s–1 ecf

4a(v) · 1 mark

  • 1 mark

    (k and rate of reaction) both increase

4b(i) · 1 mark

  • 1 mark

    step 1 as this has one mole of H2O2 and one mole of I– OR step 1 as correct stoichiometry / coefficients of 1 H2O2 and 1 I– OR step 1 as number of moles of each reactant are consistent with rate equation / their orders

4b(ii) · 1 mark

  • 1 mark

    step 1 I oxid no –1 → +1 AND O oxid no –1 → –2 OR step 3 I oxid no –1 → 0 AND I oxid no +1 → 0

4b(iii) · 1 mark

  • 1 mark

    intermediate AND formed (in step 2) and used up (in step 3)

5a(i) · 3 marks

  • M1

    reaction 1 structure: cyclohexane

  • M2

    reaction 2 structure: (bromomethyl)benzene / benzyl bromide

  • M3

    reaction 3 structures: both 2-bromotoluene and 4-bromotoluene

5a(ii) · 2 marks

  • M1

    reaction 1: hydrogenation / reduction

  • M2

    mechanism 2: (free) radical substitution

5b · 1 mark

  • 1 mark

    the substitution product is stabilised by delocalization of π-electrons / by π-electrons in the ring OR the addition product is not stabilised by delocalisation (of π-)electrons

5c(i) · 3 marks

  • M1

    curly arrow from inside the hexagon to S atom

  • M2

    structure of the intermediate

  • M3

    curly arrow from C-H bond into the ring AND formation/loss of H+

5c(ii) · 1 mark

  • 1 mark

    structure of bis(3-methylphenyl) sulfoxide OR (3-methylphenyl)(4-methylphenyl) sulfoxide

5d(i) · 1 mark

  • 1 mark

    CH3COOH + SOBr2 → CH3COBr + HBr + SO2

5d(ii) · 3 marks

  • M1

    acyl bromides > acyl chlorides > alkyl chlorides (easiest to hardest)

  • M2

    First explanation point from the list

  • M3

    Second explanation point from the list

6a(i) · 1 mark

  • 1 mark

    5 / five

6a(ii) · 2 marks

  • M1

    benefit: higher biological efficiency / activity (of the drug) OR less side effects OR smaller dose required (as drug more potent)

  • M2

    disadvantage: the need to separate (a racemic mixture into a single stereoisomer) OR lower yield (of biologically active molecule/product) OR need a chiral catalyst / enzyme (in the synthesis so expensive)

6b(i) · 2 marks

  • 1 mark

    Any two of carboxylic acid/carboxyl, ester, amide, amine

  • 1 mark

    All four of carboxylic acid/carboxyl, ester, amide, amine

6b(ii) · 3 marks

  • 1 mark

    Structure 1: HOOC-CH2-NH-CH(CH3)-COOH

  • 1 mark

    Structure 2: octahydroindole carboxylic acid derivative

  • 1 mark

    Structure 3: CH3-CH2-OH

7a · 3 marks

  • M1

    p-orbital / lone pair from O atom is overlaps / delocalised into the ring

  • M2

    greater π electron density around the ring OR makes the ring more electron rich / positions 2,4,6 more electron rich

  • M3

    polarises electrophiles more easily

7b · 1 mark

  • 1 mark

    iodobenzene AND as Br is more electronegative (than I / Iδ+/I+ in the electrophile)

7c(i) · 1 mark

  • 1 mark

    C6H6O / C6H5OH + Na → C6H5O–Na+ + ½H2

7c(ii) · 1 mark

  • 1 mark

    2,4,6-tribromophenol structure

7c(iii) · 2 marks

  • M1

    reaction 1: aqueous HNO3 / dilute HNO3

  • M2

    reaction 2: alkaline/ NaOH AND C6H5N2+ (Cl–) OR alkaline / NaOH AND benzene / phenyl diazonium ion / salt

8a · 2 marks

  • 1 mark

    Any two points from: chlorobenzene is less reactive than chloroethane OWTTE; p-orbital / lone pair on Cl will overlap / delocalise into the ring; due to partial double C-Cl bond OWTTE OR C-Cl bond strengthened (more)

  • 1 mark

    All three points from above

8b(i) · 1 mark

  • 1 mark

    ethyl 3-chloropropanoate

8b(ii) · 4 marks

  • 1 mark

    Structure W: HO-CH2-CH2-COONa

  • 1 mark

    Structure X: CH3-CH2-OH

  • 1 mark

    Structure Y: HOOC-CH2-CH2-COOH

  • 1 mark

    Structure Z: H2N-CH2-CH2-CH2-COOCH2CH3

8b(iii) · 2 marks

  • M1

    step 1 NaCN / KCN in ethanol (heat)

  • M2

    step 2 H2 + Ni / H2 + Pt

8c(i) · 1 mark

  • 1 mark

    (because solvent / D / CDCl3) doesn’t give a signal / peak / absorption ORA

8c(ii) · 4 marks

  • 1 mark

    Any three correct cells

  • 1 mark

    Any six correct cells

  • 1 mark

    Any nine correct cells

  • 1 mark

    All twelve correct cells

8c(iii) · 1 mark

  • 1 mark

    (δ = 3.9) three H on neighbouring / adjacent C / it’s next to a CH3

9a · 1 mark

  • 1 mark

    potential difference / voltage between the two half-cells / two electrodes (in a cell) under standard conditions

9b · 3 marks

  • 1 mark

    Any three correct labels/features from the diagram

  • 1 mark

    Any six correct labels/features from the diagram

  • 1 mark

    All nine correct labels/features from the diagram

9c · 2 marks

  • M1

    (ΔG⦵) = – nFEcell⦵ OR –2 × 96500 × 0.59

  • M2

    ΔG⦵ = –2 × 96500 × 0.59 = –113870 J mol-1, ΔG⦵ = –114 kJ mol-1 min 3sf ecf

9d(i) · 1 mark

  • 1 mark

    E = 0.77 + (0.059 / 1) log (1/0.15) use of z = 1, E = 0.82 V

9d(ii) · 1 mark

  • 1 mark

    Ecell = 0.59 + 0.77 – (answer to (d)(i)) = 0.54 V ecf

Questions

  1. 1
    Question 113 marks
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  2. 2
    Question 212 marks
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  3. 3
    Question 312 marks
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  4. 4
    Question 410 marks
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  5. 5
    Question 514 marks
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  6. 6
    Question 68 marks
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  7. 7
    Question 78 marks
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  8. 8
    Question 815 marks
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  9. 9
    Question 98 marks
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