Non-right-angled triangles: past paper questions

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• Question 22May/June 2026, paper 22Structured8 marksHas a diagram

  The diagram shows a triangular garden $ABD$. A path from $A$ meets $BD$ at point $C$. $CD=8\text{ m}$, angle $ADC={18}^{\circ }$, angle $ACB={34}^{\circ }$ and angle $ABC={90}^{\circ }$.

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• Question 20Oct/Nov 2025, paper 21Structured9 marksHas a diagram

  The diagram shows a triangular field, ABC.

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• Question 8Oct/Nov 2024, paper 21Structured8 marksHas a diagram

  $ABCD$ is a field. $AB=320\text{ m}$, $BC=250\text{ m}$, $CD=132\text{ m}$ and $AD=365\text{ m}$. Angle $BCD={90}^{\circ }$.

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• Question 9Oct/Nov 2023, paper 21Structured14 marksHas a diagram

  The diagram shows a triangular prism. $AB=6\text{ cm}$, angle $BAC={55}^{\circ }$ and the length of the prism is $20\text{ cm}$. The area of triangle $ABC$ is $34.4{\text{ cm}}^2$.

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• Question 22Oct/Nov 2025, paper 22Structured10 marksHas a diagram

  $ABCD$ is a field. A straight path crosses the field from $B$ to $D$. Calculate $AB$.

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• Question 8Oct/Nov 2024, paper 22Structured12 marksHas a diagram

  $ADB$ and $AEC$ are straight lines. $BC$ is parallel to $DE$. $BC=9.8\text{ cm}$, $BD=2.7\text{ cm}$, $DE=5.6\text{ cm}$ and $CE=3.9\text{ cm}$.

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• Question 9Oct/Nov 2023, paper 22Structured11 marksHas a diagram

  $ABCD$ is a rectangular field. $C$ is due south of $A$. $AB=450\text{ m}$ and $BC=210\text{ m}$.

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• Question 22May/June 2025, paper 22Structured9 marksHas a diagram

  The diagram shows a triangular field $ABC$. $AB=150\text{ m}$, $BC=187\text{ m}$ and angle $ABC={112}^{\circ }$. Fencing is needed for the perimeter of the field.

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• Question 9May/June 2024, paper 21Structured10 marksHas a diagram

  The diagram shows the positions of three ports $A$, $B$ and $C$. The bearing of port $B$ from port $A$ is ${107}^{\circ }$. The bearing of port $C$ from port $A$ is ${192}^{\circ }$.

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• Question 9May/June 2023, paper 22Structured12 marksHas a diagram

  $A$, $B$ and $C$ are points on horizontal ground. The bearing of $B$ from $A$ is ${072}^{\circ }$. The bearing of $C$ from $A$ is ${205}^{\circ }$.

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