Indices I: past paper questions

Where the questions come from

• Question 18May/June 2026, paper 13Structured3 marks

  Write down the value of $\sqrt[3]{27}$.

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• Question 23Oct/Nov 2025, paper 11Structured2 marks

  $a^8\times a^x=a^{15}$ Find the value of $x$.

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• Question 2Oct/Nov 2024, paper 33Structured15 marks

  Write the number 845024 in words.

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• Question 16Oct/Nov 2023, paper 11Structured3 marks

  Simplify. $n^5\times n$

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• Question 13May/June 2026, paper 32Structured2 marks

  $8^y=1$ Find the value of $y$.

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• Question 21Oct/Nov 2025, paper 12Structured2 marks

  Simplify. $$\frac{18x^8}{9x^2}$$ Simplify.

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• Question 20May/June 2024, paper 11Structured2 marks

  Find the value of ${137}^0$.

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• Question 3Oct/Nov 2023, paper 32Structured12 marks

  Write the number fourteen thousand and ninety-seven in figures.

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• Question 9Oct/Nov 2025, paper 13Structured2 marks

  Find the value of $2^5$

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• Question 21May/June 2024, paper 12Structured1 mark

  $$5^7÷5^x=5^3$$ Find the value of $x$.

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• Question 3Oct/Nov 2023, paper 33Structured15 marks

  Aneel has 80 tea bags, $\frac{1}{2}\text{ kg}$ of sugar and 1 litre of milk. To make a cup of tea he uses: • 1 tea bag • 8 grams of sugar • 40 millilitres of milk. In the morning, Aneel makes 15 cups of tea.

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• Question 17Oct/Nov 2025, paper 13Structured5 marks

  $$k^x\times k^5=k^{20}$$ Find the value of $x$.

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• Question 15May/June 2023, paper 13Structured1 mark

  Simplify $d^8÷d^2$.

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• Question 6Oct/Nov 2025, paper 32Structured3 marks

  0 1 8 27 39 51 59 81 From the list of numbers, write down a square number

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• Question 18Oct/Nov 2025, paper 33Structured2 marks

  Calculate. $$\sqrt{\frac{{8.4}^2+9.3}{26.5}}$$

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• Question 14May/June 2025, paper 11Structured1 markHas a diagram

  $$3^p\times 3^4=3^{10}$$ Find the value of $p$.

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• Question 7May/June 2025, paper 12Structured2 marks

  Find the value of the reciprocal of $\frac{1}{3}$.

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• Question 3May/June 2025, paper 13Structured5 marks

  Write down $\sqrt{169}$ .

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• Question 21May/June 2025, paper 32Structured3 marks

  Simplify. $(w^3{)}^{10}$

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