A Level Mathematics (9709)14 July 2026·4 min read

Binomial Expansion Explained: A-Level Maths (9709)

Short answer: Binomial expansion is a fast way to expand a bracket like (a+b)n(a+b)^n without multiplying it out term by term. For a positive whole-number power you use (a+b)n=r=0n(nr)anrbr(a+b)^n = \sum_{r=0}^{n} \binom{n}{r} a^{n-r} b^r, which gives a finite expansion. For negative or fractional powers (Pure 3), you use the extended version, which gives an infinite series that is only valid when x|x| is small enough.

The binomial theorem for positive integer powers

In Cambridge 9709 Pure Mathematics 1, you expand (a+b)n(a+b)^n where nn is a positive whole number. The theorem is:

(a+b)n=(n0)an+(n1)an1b+(n2)an2b2++(nn)bn(a+b)^n = \binom{n}{0}a^n + \binom{n}{1}a^{n-1}b + \binom{n}{2}a^{n-2}b^2 + \dots + \binom{n}{n}b^n

The symbol (nr)\binom{n}{r}, read as "n choose r", is calculated as (nr)=n!r!(nr)!\binom{n}{r} = \frac{n!}{r!\,(n-r)!}. Your calculator has this as the nCr button, which saves a lot of time in the exam.

Notice the pattern: the power of aa goes down by one each term while the power of bb goes up by one, and the two powers always add up to nn.

Finding a specific term

Most 9709 questions do not ask for the whole expansion. They ask for one term, such as "the coefficient of x3x^3". Expanding everything wastes time, so use the general term:

term in br=(nr)anrbr\text{term in } b^r = \binom{n}{r} a^{n-r} b^r

Worked example. Find the coefficient of x3x^3 in (1+2x)10(1 + 2x)^{10}.

Here a=1a = 1, b=2xb = 2x, and n=10n = 10. The term in x3x^3 comes from r=3r = 3:

(103)(1)7(2x)3=120×8x3=960x3\binom{10}{3}(1)^{7}(2x)^{3} = 120 \times 8x^3 = 960x^3

So the coefficient of x3x^3 is 960960. The key steps are choosing the right rr, remembering to raise the whole of 2x2x to the power, and then evaluating 23=82^3 = 8. Forgetting that last cube is one of the most common slips.

When there is more than one source of the power

If both terms in the bracket contain xx, say (3x2x)n(3x - \frac{2}{x})^n, then the power of xx in a term depends on rr. You set up the general term, simplify the powers of xx, set the total power equal to the one you want, and solve for rr. Only then do you evaluate. This is a favourite exam trick because it forces you to track the powers carefully rather than just reading off a coefficient.

The extended binomial expansion (Pure 3)

In Pure Mathematics 3 the power can be negative or a fraction. The nCr formula no longer works because nn is not a whole number, so you use:

(1+x)n=1+nx+n(n1)2!x2+n(n1)(n2)3!x3+(1+x)^n = 1 + nx + \frac{n(n-1)}{2!}x^2 + \frac{n(n-1)(n-2)}{3!}x^3 + \dots

This series never terminates. It only equals (1+x)n(1+x)^n when x<1|x| < 1.

Worked example. Expand (1+x)1/2(1+x)^{1/2} up to the term in x2x^2.

With n=12n = \tfrac{1}{2}:

  • First term: 11
  • Second term: 12x\tfrac{1}{2}x
  • Third term: 12(121)2!x2=12×(12)2x2=18x2\dfrac{\tfrac{1}{2}\left(\tfrac{1}{2}-1\right)}{2!}x^2 = \dfrac{\tfrac{1}{2} \times \left(-\tfrac{1}{2}\right)}{2}x^2 = -\tfrac{1}{8}x^2

So (1+x)1/21+12x18x2(1+x)^{1/2} \approx 1 + \tfrac{1}{2}x - \tfrac{1}{8}x^2, valid for x<1|x| < 1.

Getting the bracket into the right form

The extended formula only works when the bracket starts with a 11. If you are given (4+x)1/2(4 + x)^{1/2}, first factor out the constant:

(4+x)1/2=(4(1+x4))1/2=2(1+x4)1/2(4+x)^{1/2} = \left(4\left(1 + \tfrac{x}{4}\right)\right)^{1/2} = 2\left(1 + \tfrac{x}{4}\right)^{1/2}

Now expand (1+x4)1/2(1 + \tfrac{x}{4})^{1/2} using the formula and multiply every term by 22. The validity condition also changes: you need x4<1\left|\tfrac{x}{4}\right| < 1, which means x<4|x| < 4.

Comparing the two versions

Positive integer power (P1)Extended power (P3)
Value of nnWhole numberNegative or fractional
Number of termsFinite (n+1n+1 terms)Infinite series
Uses (nr)\binom{n}{r}YesNo, uses the fraction formula
Validity conditionAlways validOnly when x<1\lvert x\rvert < 1
Bracket must start with 1NoYes, factor out first

Common mistakes to avoid

  • Forgetting to raise the coefficient inside the bracket to the power, for example writing 2x32x^3 instead of (2x)3=8x3(2x)^3 = 8x^3.
  • Losing a minus sign when the bracket has a subtraction, such as (13x)n(1 - 3x)^n.
  • Quoting the validity condition for the factored bracket but forgetting to translate it back into a condition on xx.
  • Reading "coefficient" as "term" or the other way round. A coefficient is just the number, so 960960, not 960x3960x^3.

Practise until the steps are automatic

Binomial questions reward accuracy more than cleverness, so the fastest way to improve is to do many of them and check each line. ExamPal is an AI tutor that already knows the 9709 syllabus and marks your working against the Cambridge mark scheme, so if you drop a coefficient or misstate a validity range it can show you exactly where and why. That kind of targeted correction is how the small slips stop happening.

Frequently asked questions

What is the difference between binomial expansion in P1 and P3?

In Pure Mathematics 1 the power is a positive whole number, so the expansion is finite and uses the nCr notation. In Pure Mathematics 3 you also learn the extended binomial expansion for negative and fractional powers, which produces an infinite series that is only valid for a limited range of x.

How do I find a single term without expanding everything?

Use the general term formula. For the expansion of a plus b all to the power n, the term containing b to the power r is nCr times a to the power n minus r times b to the power r. Set the power of x equal to the one you want, solve for r, then evaluate that one term.

Why does the extended expansion need a validity condition?

For negative or fractional powers the series never ends, so it only adds up to the true value when x is small enough. The expansion of one plus x to a power is valid when the modulus of x is less than one. If your bracket is one plus a x, rewrite the condition in terms of x.

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